程序设计操作符的重载实验报告

1、程序设计操作符的重载实验报告实验报告二 类和对象一、实验目的本实验的U的是熟练学习和掌握类的定义及操作符的重载以及Datatime结 构。二、实验内容及结果(一)、第1个题訂的要求:定义完整的ComplexNumber类，在其中重载加减乘 除等基本操作符、相等和不等操作符、大小比较操作符以及自增自减操作符1、程序编程思路:首先定义一个ComplexNumber类，然后重载各种操作2、程序源码:static void Main(stringargs)Console. WriteLine(z/请输入第一个复数 cl: ”)；ComplexNumber cl = newComplexNumber(d

2、ouble Parse(Console ReadLine(),double Parse(Console ReadLine();Console. WriteLine (请输入笫二个复数 c2: ”)；ComplexNumber c2 = newComplexNumber(double Parse(Console ReadLine(),double Parse(Console. ReadLine();ComplexNumber c3 = cl + c2;Console. WriteLine C这两个复数的和为0, c3);ComplexNumber c4 二 cl 一 c2;Console. Wr

3、iteLine (这两个复数的差为0 、c4);Comp1exNumber co = cl * c2;Console. WriteLine C这两个复数的乘积为0, c5);Comp1exNumber c6 = cl / c2;Console. WriteLine C这两个复数相除为0, c6);if (cl = c2)Console. WriteLine C这两个复数相等)；else if (cl != c2)Console. WriteLine C这两个复数不相等)；if (cl c2)Console. WriteLine(clc2);elseConsole. WriteLine(clc2

4、);Console. WriteLine Cc 1 自增结果为0, cl+);Console. WriteLineCc 1 自减结果为0, cl-);Console. ReadLine ();public class Comp1exNumberprivate double x, y;public double Xget return x; set x = value; public double Yget return y; set y = value; public Comp1exNumber(double x, double y)this x = x;this y 二 y;public s

5、tatic Comp1exNumber operator +(Comp1exNumber cl,Comp1exNumber c2)return new Comp 1 exNumber (clx + c2 x, cl y + c2 y);public static Comp1exNumber operator -(Comp1exNumber cl,Comp1exNumber c2)return new Comp 1 exNumber (cl.x 一 c2 x, cl y 一 c2 y);public static Comp1exNumber operator *(Comp1exNumber cl

6、,Comp1exNumber c2)return new Comp 1 exNumber (cl x * c2 x 一 cl y * c2 y, cl y * c2 x + cl. x * c2. y);public static Comp1exNumber operator /(Comp1exNumber cl,Comp1exNumber c2)return new Comp 1 exNumber(clx * c2x + cl y * c2 y) / (c2x * c2+ c2. y * c2. y), (cl. y * c2. x - cl. x * c2. y) / (c2. x * c

7、2. x + c2. y * c2. y);public static bool operator =(Comp1exNumber cl, Comp1exNumber c2)return (clx = c2 x) & (cly = c2 y);public static bool operator !=(Comp1exNumber cl, Comp1exNumber c2)return (clx != c2 x) I i (cly !二 c2 y);public static bool operator (Comp1exNumber cl, Comp1exNumber c2)double a

8、= clx * clx + cl. y * cl.y;double b = c2. x * c2. x + c2. y * c2. y;return a b;public static bool operator (Comp1exNumber cl, Comp1exNumber c2)double a = cl为:* cl. X+ cl y * cl. y;double b = c2 y:* c2. x+ c2. y * c2. y;return a b;public static Comp1exNumber operator +(Comp1exNumber cl)return new Com

9、p1exNumber(cl x+, cl. y+);public static Comp1exNumber operator -(Comp1exNumber cl)return new Comp1exNumber(cl x一一, cl y一一);public override string ToStringOreturn string Format C 0 + l i，z, this x, this y);3、实验结果：(二)、第2个题目的要求:知道一个人的生日，如何计算他的年龄(严格按照周 岁计算)1、程序编程思路：首先考虑的是怎么来计算年龄，想到用当前日期减去生日日期，用年减去年， 月减去

10、月，日减去日，然后思考，各种情况下的年龄讣算方法，画出程序的流程 图，根据流程图写出源程序;接着就想到如何让操作者方便的一次性将生日的年月 日输入，就考虑用字符数组，然后用string类的split方法将输入的字符串劈 开。2、程序源码：static void Main (string Z args)int a, b, c, d, e, f;DateTime s = DateTime.Today;d = s Year;e = s. Month:f = s. Day;Console. WriteLine (0000-00-00);请输入您的生日(格式为)string g = ConsoleRea

11、dLine();char sepl 二;string J h= g. Split (sepl);int x = new inth.Length;for (int i = 0; i h. Length; i+)xi = int. Parse(hi);a =d-x0;b =e-xl;c =f-x2;辻(a 0) I I (a = 0 & b 0) I i (a = 0 & b = 0 & c 0)if (b 0) Console. WriteLine ( 0 , a);您今年岁else if (b 0) Console. WriteLine C 0z/, a - 1);您今年岁else if (b = 0)if (c0) Console. WriteLine C 0z/, aT);您今年岁else Console. WriteLine ( 0 , a);您今年岁Console. ReadLine ();3、实验结果：三、实验效果对第一个题II,要熟记操作符重载的方法与格式，掌握被重载的操作符必须被声明为共有的和静态的