工具类_参考答案(最新整理)

1、1、编写一个程序，实现从命令行参数输入两个字符串类型的数值，并计算输出两个数值的和。public class exercise_09_01 public static void main(string args) /读取命令行数据，并进行类型转换int x = integer.parseint(args0);int y = integer.parseint(args1); int z = x+y; system.out.println(z);2、编写一个程序，实现从命令行参数输入一字符串，统计该字符串中字符“e”出现的次数。public class test /* param args*/pu

2、blic static void main(string args) scanner in = new scanner(system.in); string s = in.next();int num = 0;for(int i =0;i s.length();i+)if(s.charat(i)=e) num+;system.out.println(num);3、生成十个 0100 之间的随机数，放到数组中，然后排序输出。public class test public static void num()int a = new int8;for(int i = 0;ia.length;i+)a

3、i = (int)(math.random()*101);arrays.sort(a);for(int i = 0;is.lastindexof(.) system.out.println(邮箱地址中.出现在的前面); return false;for(int i=0;i=a&s.charat(i)=a&s.charat(i)=z) )elsesystem.out.println(用户名里有其他字符);return false;return true;public class test /* param args*/public static void main(string args) /

4、todo auto-generated method stubif(mailtest.testmail() system.out.println(邮箱格式合法);elsesystem.out.println(邮箱格式不合法);6、分别在控制台输入字符串和子字符串，并计算字符串中子字符串出现的次数。public class test /* param args*/public static void main(string args) / todo auto-generated method stub scanner in = new scanner(system.in); string s =

5、 in.next();string a = in.next();int num = 0;/i是循環的次數for(int i = 0;is.length()-a.length();i=s.indexof(a, i)+1)if(s.indexof(a, i)!=-1) num+;system.out.println(num);7、有一个字符串，其中包含中文字符、英文字符和数字字符，请统计和打印出各个字符的个数。public class test /* param args*/public static void main(string args) / todo auto-generated met

6、hod stub scanner in = new scanner(system.in); string s = in.next();int num=0,eng=0,china=0;for(int i =0;i=0&s.charat(i)=a&s.charat(i)=a&s.charat( i)=z)eng+;else if(19968 = s.charat(i) & s.charat(i) 40623) china+;system.out.println(数字是：+num); system.out.println(英文是：+eng); system.out.println(中文是：+chin

7、a);8 有一种数叫回文数，正读和反读都一样，如 12321 便是一个回文数。编写一个程序，从命令行得到一个整数，判断该数是不是回文数。public class test /* param args*/public static void main(string args) / todo auto-generated method stubif(foo()system.out.println(是回数);elsesystem.out.println(不是回数);public static boolean foo()scanner in = new scanner(system.in); stri

8、ng s = in.next();int j = s.length()-1;for(int i=0;is.length()/2;i+)if(s.charat(i)!=s.charat(j)return false;j-;return true;“”“”at the end, xiao bian gives you a passage. minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a prof

9、essional clerical and teaching position, i understand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the mar