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1、精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有The Final Examination of Chemical Reaction EngineeringUsed by graduate students of 20102011-6Name:Class:Grade:Student Number:1:For a gas reaction at 400 K the rate is reported asdp2A?3.66?D hratm / Adt (a)What are the units of the rateconstant?(b)What is th
2、e value of the rate constant for this reaction if therate equation is expressed asdN132AS .mol/mr?C,?AAdtV文档精品精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有2: For the elementary reactions in seriesC?C?AoAkkO,att ?R?S,kk ?A?2?2iOC?C?Rsofind the maximum concentration of R and when it is reached. 精品文档精品文档
3、就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有3:Give n a gaseous feedT=1000 K, n =5 atm, C=100, C=200,B000A0 T=400 K, n =4 atm, C=20. Find X, X, C.R?AB5, BABA精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有4: A gaseous feed of pure A (1 mol/liter) en ters a mixed flow reactor(2 liters) and reacts as follows:2A?
4、R,mol2C?0.05? AAliterecFind whatfeed rate (liter/m in) will give an outlet concen trati onC=0.5mol/lliter. a 精品文档精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有5:The kin etics of the aqueous-phase decompositi on of A isinvestigated in two mixed flow reactors in series, the second having twice the volume
5、 of the first reactor. At steady state with a feed concentration of 1mol A/liter and mean residence time of 96 sec in the first reactor, the concentration in the first reactor is 0.5 molA/liter and in the second is 0.25 mol A/liter.Find the kinetic equation for the decomposition. 精品 文档 精品文档就在这里 各类专业
6、好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有 6: T is the desired product and C=5.A03 in kmol/ma of radiation, reactant A C=10 ultraviolet Under A03/min) decomposes as cess stream (v=lmA一 S,r = 12Ca kniaUm -minThr(. Ckmolr-minWe wish to design a reactor setup for a specific duty. Sketch the scheme sele
7、cted, and calculate the fracti on of feed tran sformed into desired product as well as the volume of reactor n eeded.精品文档精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有7:Whe n oxyge n is bubbled through a hightemperature batch ofA-c ontaining liquid material, A oxidizes slowly to give a slowly decompos
8、ing in termediate X and final product R. Here are the results of an experime nt:r, min40LU)00.19乞書1.42.515J12?.34,0101-520e汕出tieIOCWe have no way of an alyz ing for X; however, we are safe in assu ming that at any time C+C+C二C.What can we say about the mecha nism aorax a nd kin etics of this oxidati
9、 on? Hint: plot the data and exam ine the plot.精品文档精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有 8:Phthalic An hydride from Naphthale ne. The accepted mecha nism for the highly exothermic solid catalyzed oxidati on of n aphthale ne toproduce phthalic an hydride isR= 3 X LO13 exp(-159(W RThr-1)乙J亠丁岫皿彳峙
10、工 8.15 x 1611hr1 = 2. 1(Petpj-SS6(HyRr)hr3|and whereA=n aphthale ne (reacta nt)R=n aphthaq uinone (postulated in termediate)S=phthalic an hydride (desired product)T=CO+HO (waste products)22and the Arrenhius activation energy is given in units of J/mol. This精品文档精品文档就在这里各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,
11、应有尽有 reacti on is to be run somewhere betwee n 900 K and 1200 K.A local optimum reactor setup discovered by the computer see example 1, Chem. Eng. Sci., 49, 10371051(1994) l is shown in Fig.P10.19.Figure P10.19(a) Do you like this desig n? Could you do better? If so, how ?(b) If you could keep the whole of your reactors at whatever temperature and 7 value desired, and if recyle is allowed, how much phthalican hydride could be produced per mole of
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