非平衡载流子习题解ppt课件

1、第五章 非平衡载流子 习题解5.1题NoImageNoImagescmpUscmpUp3171010010313/10U100,/10613得：解：根据？求：已知：gpgpdtpdgAetpgpdtpdLLtL.00)2()(达到稳定状态时，方程的通解：梯度，无飘移。解：均匀吸收，无浓度5.2题题5.3题cmspqnqqpqnpqnpcmqpqncmgnpgppnpnpnpnL/06. 396. 21 . 0500106 . 1101350106 . 11010. 0:101:1010100.1916191600000316622光照后光照前光照达到稳定态后%2606. 38 . 006. 3

2、500106 . 1109.,.32. 01191610puppppcm的贡献主要是所以少子对电导的贡献献少数载流子对电导的贡5.3题题5.4题。后，减为原来的光照停止%5 .1320%5 .13)0()20()0()(1020seppeptpt5.5题cmsqnqupqnpppnnncmpcmncmpncmnKTnpni/16. 21350106 . 110:,/1025. 2,10/10.105 . 1,30019160000003403160314310无光照则设半导体的迁移率）本征空穴的迁移率近似等于的半导体中电子、注：掺杂有光照131619140010(/19. 20296. 016

3、. 2)5001350(106 . 11016. 2)(:cmcmsnqqpqnpqnqpnpnpn5.5题5.6题EFEcEiEvEcEFEiEvEFpEFn光照前光照前光照后光照后5.7题TkEEenpTkEEenncmNnpppcmnnnFPiioiFniDi01414152101420315141503/101010)105.1(10/101.11010度强电离情况，载流子浓0.0517eVPFEFE0.0025eVFEnFE0.289eV10101.51410Tln0kinDNTlnokiEFE平衡时0.229eV10101.51410Tln0kiEFPEiPPTln0kiEFPE0

4、.291eV10101.515101.1Tln0kiEFnEinnTln0kiEFnE 5.8题TkEEenppppppnrkEEennrpnrnTkEEenrnnrnsnNoFiitpoititntntoitintntntt001T,.小注入：由题知，从价带俘获空穴向导带发射电子被电子占据复合中心接复合理论：解：根据复合中心的间5.8题不是有效的复合中心。代入公式很小。,11,;011tptnoFiitpnoFiipoitinNrNrpnpnEEEErrTkEEenrTkEEenr5.9题TkEEcTkEEcTkEEcTkEEcnptpniTiFVTTCoVFFceNpeNneNpeNnpp

5、nrrppprpnnrEEEESi0001100001010;)(N)()(:根据间接复合理论得复合中心的位置本征5.9题npntptnptpnptnTiFrNrNpnnrrNpnnrpnnrrNpnnrpnpnEEE11)()()()(000000001100所以：因为：5.10题sNrrAuSipsNrrASincmNtnnntpppt9168101617316106 . 110103 . 611106 . 8101015. 111u10决定了其寿命。对少子电子的俘获系数中，型。决定了少子空穴的寿命对空穴的俘获系数中，型5.11题产生复合率为负，表明有净载流子完全耗尽，00, 0) 1 (

6、)()()(112112prnrnrrNUpnpprnnrnnprrNUpnipntpnipnt产生复合率为负，表明有净结，（反偏，只有少数载流子被耗尽0)(),)2()()()(11200112prnnrnrrNUnnpppnpprnnrnnprrNUpnipntnnnnpnipnt5.11题复合复合率为正，表明有净（0)()(),)3()()()(1122112pnrnnrnnrrNUnnpnpprnnrnnprrNUpnipntipnipnt5.11题03160340203160, 0, 0,10/1025. 2,10ppnpcmnncmnnpcmNniD5.12题题iTkEEvTkEE

7、viTkEEcTkEEcpnipntpnipntneNeNpneNeNnprnnrnrrNpprnnrnnprrNUovivicC0T00T111102112)()()()(5.12题题scmpprNnrnrrNnrnrnrnrrNpptnipntipinonipnt396400022/1025. 210101025. 2U5.12题题5.13题cmqTkDLqTkDqTkDnnnnnnonn18. 0103503600026. 0600：解：根据爱因斯坦关系5.14题241500/55. 510310400026. 0cmAxpTkxpqTkqdxpdqDJppPP5.15题sNrncmNS

8、ipgnxEnxnExnDtntnntppppp815831522106 . 110103 . 61110:遇到复合中心复合的复合中心内部掺有由于根据少子的连续性方程0, 0,2222nnnPDndxndnxndD达到稳定分布无产生率无电场nnnLxLxDLBeAexnnn,)(:方程的通解为00000002)()(0)(,)0(, 0:nTkqnDqDnqDLnqDdxxndqDJenxnnxnnxnnnnnnonnnxnnLnx边界条件5.16题pDqLpqDdxpdqDJDLepxppxcmpxpdxpdDppppxpppppLxppp00031322,)(0)(,10)0(, 00) 1 (边界条件：性方程为过剩空穴所遵从的连续5.1610ln1010ln10101312012012ppLxLxLLxepeppp(2)5.17ppLpxppLpxpxppppppg