图示为串联电压负反馈放大电路(图1)解读

1、ii第 17 章1b 2a 3c 4d 5a 6c 7b 8b 9b 10a11b12d13c14b19b 20b21c 22a23b24(1)图示为串联电压负反馈放大电路(图1) 图示为并联 电流负反馈放大电路(图2)9R-H_R1pl_hooR1-OUOU| O1h-图1U|15b16a17a18b25(1)RF,R1电路为 反馈R+RFUOU|R1输入电阻R = U二iI:cd。26 I(1)R6为级间反馈电 阻，R6=37.5k要点ii礼i1-(1)UI Uoi6Re-(2)电路，为串联电压负反馈为并联电压负反馈。iib飞将(2)和(3)代入(1)得4Re)U|= 7.5k?I3027

2、要UAU|R1R6ii4R1R6R6=37.5kuo( R3尺R2R3 R2R4) / R1R4 ui占：八、R2石U|i3,i4UAi2i4 -i3UAI4i2,入式、UA-UO)：将巴(R1R4U|( &R4)R2- I -R1R4(1)得(1)UI2访UA-UOiR3出-(丄丄)UAUR1乜R/AR328要uoUOUIR3R4R1R3R3Ft,R +R2R4y 当RP滑动当Rp滑当RP滑点：如=_ul10=-(U| U|) - -(2V + 1V)5-3Vuo(1)动点滑动点滑图所示)u|R1R4|点滑动到A动到B点时,动到C点时,占八、 、U|10k?&R4R2&

3、; R2R4R1R4时，UO= -2VuO=2VUO- -3VUI10k JCZI00UO10kQ10k29U01u024 sintV二-4 sin，tVuO二uO1- uO2= 4Ui= 8 sintV= 7.5k?I30334UO2= -氏 ,1U|+ =UO21UO二-Ui(-UO)2二-U|- UO2U。二-U|1-2U|R1= R2= R3 = RF= 10k1.13132(1)占八、 、=(1RF-/R-)R4/RR4)U|-(RFR2)(RF1R1)U|1二U|2u1/八RF1RF2RI(1)UD1= un，比=Uo1 + Ri rR?RF1RF-RF-RIUoFF-U|1(1-

4、F-)4U|-R R?R? &R,后得：UOUO(1+邑U|2R3 &R33要距R4RF2RF1_)4U|2-RR3R4若RF1 = R1,耳2 &，13 R4+ U|-) +(5/3)( U|3+U|4)原理求之：1805Uo =3(U|3U|4)(1 -0-U|332035-2(U|1U|2)(U|3U|4)UO=(1UO= 2(U|1点：用叠加UO= _2U|1 _2U|2因此：uO=uO- UO2、R4U|- cnR?R1贝yU|1U。二U|2-uii却4UoTR/RROZW)要点骨334要点:i1=iRic =3940Uoi -UO_CdUodTR15dt35UO因此RFC= 0.05U01=Lt RCydt0.0555=0.05 10-F 105R = R1/RF- 33 k；.05 uFRi= 50 k:.二1/(RiCJ.UidtUOUOUO1R1C1UdtUO= -U01uo =R1C1uidt37uo -u13Uo1 =1, RC 1 2 u利1o用叠加原理UOUo38UORCundtUo1u11u12dt求之：1U12dt RCU13dtF rilff ji|PW=UUo Uo= U13十RC1.11.2U13 UH山2dtCFRF(duO/dt-(RF/R1)uIii