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1、实用文档第一章土的物理性质及工程分类(教材习题 ) 1-1 解( 1)a曲线:卵石或碎石( 20mm )占 10077=23% 砾粒(20-2mm )占 77 50=27% 砂粒(2-0.075mm)占 50 10=40% 粉粒( 0.075mm )占 10% ( 2)a 曲线较平缓,说明a 土土粒粒度分布范围广,颗粒不均匀,故级配良好;而b 土曲线较 a土曲线陡,说明其粒度分布范围窄,土粒均匀,故级配不良。( 3)a土08.0d106.0d303.6d6055408./06.3/dd1060uc25.10.08)/(3.6(0.6)/()(26010230cdddc在 1-3 之间,故a土级
2、配好 b土15.0d1035.0d3074.0d6059.474/0.15.0/dd1060uc1.100.15)/(0.74(0.35)/()(26010230cdddc只满足一个条件,故级配不良1-2 解:119gsm8g119-127mmmsw%72.6119/8/mswmw0.6371-760.0672)/1.(112.71)/(1wgews3cm/76g.172/127/vm3wssatcm/04g.2637).0(1/637).07.(2e)(1/)(eg3wsatcm/04g.1 3cm/65g.172/119/vmsd38.9%0.637)0.637/(1)/(1een5%.2
3、82.7/0.6370.0672/ewgssr比较密度:satd 实用文档1-3 解svvv , 1sv/vve3/4 .13)11/(1068.2)1/(mknegwsdwvvv3/4 .18)11/(10)168.2()1/()()1/()(mkneedevgwswvssat%3.3768.2/1/1/svwsswwswggvvwww1-4 解设31mvknvwds113407.0)107. 2/(11)/(mdwvwsss3593.0407.01mvvvsvswwww/kn5.5115 .0swwww355.010/5.5/mwvwww3043.055.0593.0mvvvwva1-5
4、解:饱和土sgwe)1/()(eegwssat即sge4.010)1/()(18eegs以上两式联立求解解得05.1e65.2sg1-6 解ssswwwwwww/)(/可求得%16w时,nw64.21时土粒的质量nwwws655.18)16.01/(64.21)1/(其中水量为nwwwsw985.2655.1816.0当%25w时,土中水量为nwwwsw664.4655.1825.0实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10
5、107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(
6、1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0
7、knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1
8、(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.
9、631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min
10、/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当
11、%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.
12、02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土kn
13、wwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29
14、/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.1131
15、4.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd
16、)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(
17、其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxmin
18、egwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw
19、547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(10
20、65.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.10
21、15.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14ma
22、xe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量
23、为knw64. 4547.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe
24、33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 454
25、7.1186.61-8 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16
26、/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8
27、 解:1esvvve/svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000
28、/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw547.1314.1015.0故增加水的重量为knw64. 4547.1186.61-8 解:1esvvve/
29、svvv31mv35.0mvvsvvwrvvs/34.05.08.0mvsvvrw当水蒸发掉一半时32.02/4.02/mvvww9 .0/2.0/rwvsvv%2.72722.09.0/2. 05.0v1-9 证:wwwwwwwwvwvwswssssd/)(1/1)/()/(1/1-10 解:663.011 .17/)073.01(1065.2(1/)1(wgews33min/9.14/0149.02000/85.29/mkncmnvwsd)1/(/maxminegwsd)1/(1065.29 .14maxe779.0maxe33min/3 .16/0163.02000/5.32/mkncmnvwsd)1/(/minminegwsd)1/(1065.23.16mine6 2 6.0mine实用文档因此增加的水量nww679.1985.2664.41-7 解:设饱和土为31mv1wsvvv饱和土6 .0/sswswgvvwww由上两式联立可得:382.0sv618.0wvkngvwwsss314.10107 .2382.0knwwwsw186.631.1060.0当%15w时,需要土knwwws86.11314.1015.1)1(其中水量knwwwsw54
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