ProcessControl20110511AwithSolutionBasictheory_第1页
ProcessControl20110511AwithSolutionBasictheory_第2页
ProcessControl20110511AwithSolutionBasictheory_第3页
ProcessControl20110511AwithSolutionBasictheory_第4页
ProcessControl20110511AwithSolutionBasictheory_第5页
已阅读5页,还剩1页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

1、命题人: 组题人: 审题人: 命题时间: 教务处制学院 专业、班 年级 学号 姓名 公平竞争、诚实守信、严肃考纪、拒绝作弊封线密重庆大学Process Control课程试卷20092010学年 第一学期开课学院:自动化学院 课程号:17001825考试日期:2009-05-18 考试时间:120分钟题 号一二三四五六七八九十总 分得 分一、 Basic Concepts (30 points) You are designing controls for the CSTR in the figure. What are some of the disturbances that the co

2、ntrol system should compensate? (4 points). Feed composition (Yes or No)Yes,(the control system should compensate for changes in feed composition. Corrective actions could affect the temperature or residence time in the reactor.) Lack of perfect mixing (Yes or No)No, (lack of perfect mixing will usu

3、ally lead to very irregular behavior that would be difficult to control. The tank should have a properly designed stirrer - which can be designed by a chemical engineer who knows about fluid mechanics!) Error in the level sensor (Yes or No)Yes, (small errors in the level affect the conversion. These

4、 errors could be compensated by changes to the temperature.Note that large errors in level could lead to overflowing the vessel and hazards to people.) Feed temperature (Yes or No)Yes,(changes in feed temperature affect the conversion. These disturbances can be compensated by changes to heating or c

5、ooling to the tank.) Poor understanding of reaction engineering by the engineers (Yes or No)No, (control does not compensate for ignorance, only for lack of exact information. Every graduate engineer understands the basics of reaction engineering!) The tank level control system is analytically model

6、ed by a nonlinear function and approximated by a Taylor expansion in linear fashion. The figure shows that level response for a large step input. What can you describe for the analytical model and the Taylor linearized model(3 points) From the figure, when in the region from the step change to 1.5 h

7、ours, the linearization serves as a very good representation of the physical system. After approximately 2.5, the linearized curve indicates a negative level hours. This certainly defies the physical properties of a tank.At this point, the linearized model is no longer able to predict the behavior.

8、the gain and time constant for the overall dynamic model of a series of first order systems can be calculated in terms of following equations (3 points). The overall gain Koverall = K1 ´K2´´Kn (true or false)True, (this equation can derived from standard series capacity process) The o

9、verall time constant toverall = t1+t2+tn (true or false)False, (the systems with larger numbers of first order systems experience some degree of apparent dead time, thus the overall time constant is usually estimated by toverall = t63% » (t1+td1)+(t2+td2)+(tn +tdn) using the Sigmoidal shaped cu

10、rve of a step response)4. Find two methods to reject the reset windup in integral action (3 points). The Jacketing rule that simple limits the controller output in the range of the actuator (e.g., valve) Velocity form of PID controller that only uses the current error for the current calculation of

11、controller output.5. In common chemical process, we usually take the sample time Dt according to the process time constant t as follow (2 points) Dt £ 10t Dt £ 0.1t (correct choice) Dt > 0.1t Dt > 10t6. To obtain the transfer functions of a process, you can either use mathematical mo

12、delling that follows the process mass balance, or data modelling that is obtained from system identification. (3 points)7. When evaluate the control performance from the view of error, we can certainly say that the minimum error results in the best performance (2 points)(True or False) False, (becau

13、se the response time and the stability of the system should also be considered) 8. Give some tuning relations that are of aggressive, moderate and conservative when you tune the controllers based on PRC (3 points). a. Cohn-Coon is of aggressive tuning relation b. Ziegler-Nichols is of moderate tunin

14、g relation c. Ciancone-Marlin is of conservative tuning relation 9. Describe your procedure considerations when you design a control system for a process (5 points) a. investigate the background of the process, b. select the control instruments and process instruments for the plantc. model the proce

15、ss using either mathematic or empirical approaches d. select and tune the controller parameter based on the viewpoints of error, stability and time response (e.g., empirical tuning relations, step and impulse and sinusoidal response of the system, model error, sample time) e. reconsider the facts th

16、at impact the performance of the control system, such as, where there is the possibilities to construct the cascade control, feedforward and feedback control, ratio control, MIMO and decoupling control. f. synthesize the above steps until the performance of the control system is acceptable for the d

17、esign specification 10. For a process that takes x1 and x2 as manipulated variables, y1 and y2 as the controlled variables, interpret the RGA and pair the input-output variables while (2 points) a. paring y2 with x1, and y1 with x2, since the strong interaction among the respective pairs due to the

18、value of 0.91 b. avoiding the paring of y1 with x1, and y2 with x2 since the weak interaction among the respective pairs due to the value of 0.09 二、 Basic Theory (40 points)In this part, we consider the temperature control of a stirred-tank heater,The mathematic model of this process is:1.Use a feed

19、back Control structure for the stirred-tank heater as the following diagram,:1) Derive the closed-loop transfer function equation(8 points)Solution:At the summing point:For the process: Substituting E into C, we have: Rearranging the equation above: 2) What is the offset if we consider the servo pro

20、blem with (8 points)Solution:The difference between controlled variable and set pointSuppose then If (P-controller), we have If (PI-controller), we have If (PD-controller), we have 3) Build a P-only controller and a PI controller for the regulatory problem with (10 points) Solution:a. the P-controll

21、er can be design as time domain controller: where es =0 at t=0 is the steady state error. s-domain controller : We have the transfer function for the p-only control system using the block diagram: b. the PI controller can be as time domain controller: s-domain controller We have the transf

22、er function for the PI controller using the block diagram: We can solve for this nonlinear system using Pader approximation or Taylor series for linearization (not required for the exam).4) Describe General qualitative features of PI control From Practical Perspective(6 points).Solution: a. Using PI

23、 controller when offset is unacceptably bigb. Offset elimination results a more underdamped processc. Lowering the proportional gain Kc while integral used2. With respect to the Feedforward-Feedback (FF-FB) Control structure as the following block diagram(a): What affect the system stability (why?),

24、 why the feedforward control doesn't affect the system stability? (10 points)Solution:According to the block diagram (a),we can get the following algebraic equation:Substitution of E leads toRearranging the equation above:The closed-loop characteristic equation isFrom the closed-loop characteris

25、tic equation we know: the feedback controller (GmGc) and the cascade controller (GV*) affect the closed-loop system stability, but the feedforward controller GFF does not affect the system stability 三、 Basic Application (30 points) When the controller is placed in service, what should be performed a

26、s part of the initialization? Also interpret what is the bumpless transfer (10 point) Solution: a. Before you put the controller into action, the following system parameters should be properly initialized in order to have a better bumpless transfer controller output: p (controlled variable CO) proce

27、ss variable: PV (controlled variable CV) set point: SP disturbance D b. the bumpless transfer means that the process to be changed from auto to manual without upsetting the process. For example, in a PLC, in the auto mode, loading the controller output register value into a spare register will call

28、register value, resulting in a smooth running fine of the system. When switched to manual mode, the register value is loaded into the controller output register, keeping the same vale for the auto-manual switch. That is, the auto-manual modes start their control from the same output value2. Given a PI controller Gc(s)=Kc1+1/(tIs) for a process, Derive its magnitude and phase lag (5 points) Solution: One of the simple ways to find the magnitude and phase lag is to substitute directly s=jw into the transfer function, resulting

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论