程序设计部分试题及答案

1、第1题/*【程序设计】功能：从键盘为一维整型数组输入10个整数,调用fun函数找出其中最小的数,并在main函数中输出.请编写fun函数.*/#include""voidwwjt();intfun(intx,intn)/*Program*/*End*/main()inta10,i,min;for(i=0;i<10;i+)scanf("%d",&ai);for(i=0;i<10;i+)printf("%3d",ai);printf("n");min=fun(a,10);printf("%

2、dn",min);wwjt();voidwwjt()FILE*IN,*OUT;intiIN10,i;intiOUT,iCOUNT;IN=fopen("","r");if(IN=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen("","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(i=0;i

3、<10;i+)for(iCOUNT=0;iCOUNT<10;iCOUNT+)fscanf(IN,"%d",&iINiCOUNT);iOUT=fun(iIN,10);fprintf(OUT,"%dn",iOUT);fclose(IN);fclose(OUT);参考答案intmin,i;min=x0;for(i=1;i<n;i+)if(xi<min)min=xi;returnmin;第2题/*【程序设计】功能：从字符串s中删除指定的字符c*/#include<>voidwwjt();fun(chars,charc)

4、/*Program*/*End*/main()staticcharstr="turbocandborlandc+"charc='a'fun(str,c);printf("str=%sn",str);wwjt();voidwwjt()FILE*IN,*OUT;charsin80,cIN;inti;IN=fopen("","r");if(IN=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen(&quo

5、t;","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(i=0;i<10;i+)fscanf(IN,"%s",sin);cIN=getc(IN);cIN=getc(IN);fun(sin,cIN);fprintf(OUT,"%sn",sin);fclose(IN);fclose(OUT);inti,k=0;for(i=0;si!='0'i+)if(si!=c)sk+=si;sk='

6、0'第3题/*【程序设计】功能：求出二维数组周边元素之和,作为函数值返回.二维数组的值在主函数中赋予.*/#defineM4#defineN5#include<>voidwwjt();intfun(intaMN)/*Program*/*End*/main()intaMN=1,3,5,7,9,2,4,6,8,10,2,3,4,5,6,4,5,6,7,8;inty;y=fun(a);printf("s=%dn",y);wwjt();voidwwjt()FILE*IN,*OUT;intiINMN,iOUT;inti,j,k;IN=fopen("&qu

7、ot;,"r");if(IN=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen("","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(k=0;k<10;k+)for(i=0;i<M;i+)for(j=0;j<N;j+)fscanf(IN,"%d",&iINij);iOUT=

8、fun(iIN);fprintf(OUT,"%dn",iOUT);fclose(IN);fclose(OUT);参考答案ints=0;inti,j;for(i=0;i<M;i+)s=s+ai0+aiN-1;for(j=1;j<N-1;j+)s=s+a0j+aM-1j;returns;第4题/*【程序设计】功能：求一个四位数的各位数字的立方和*/#include<>voidwwjt();intfun(intn)/*Program*/*End*/main()intk;k=fun(1234);printf("k=%dn",k);wwjt

9、();voidwwjt()FILE*IN,*OUT;intiIN,iOUT,i;IN=fopen("","r");if(IN=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen("","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(i=0;i<10;i+)fscanf(IN,"%d&q

10、uot;,&iIN);iOUT=fun(iIN);fprintf(OUT,"%dn",iOUT);fclose(IN);fclose(OUT);intd,k,s=0;while(n>0)d=n%10;s+=d*d*d;n/=10;returns;第5题/*【程序设计】功能：计算并输出给定整数n的所有因子之和(不包括1与自身).注意：n的值不大于1000.例如：n的值为855时,应输出704.*/#include<>voidwwjt();intfun(intn)/*Program*/*End*/main()printf("s=%dn&quo

11、t;,fun(855);wwjt();voidwwjt()FILE*IN,*OUT;intiIN,iOUT,i;IN=fopen("","r");if(IN=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen("","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(i=0;i<5;i+)fscan

12、f(IN,"%d",&iIN);iOUT=fun(iIN);fprintf(OUT,"%dn",iOUT);fclose(IN);fclose(OUT);ints=0,i;for(i=2;i<n;i+)if(n%i=0)s=s+i;returns;第6题/*【程序设计】功能：编写程序,实现矩阵3行3列的转置即行列互换例如：输入下面的矩阵：100200300400500600700800900程序输出：100400700200500800300600900*/#include<>voidwwjt();intfun(intarray

13、33)/*Program*/*End*/main()inti,j;intarray33=100,200,300,400,500,600,700,800,900;for(i=0;i<3;i+)for(j=0;j<3;j+)printf("%7d",arrayij);printf("n");fun(array);printf("Convertedarray:n");for(i=0;i<3;i+)for(j=0;j<3;j+)printf("%7d",arrayij);printf("n

14、");wwjt();voidwwjt()inti,j,array33;FILE*rf,*wf;rf=fopen("","r");wf=fopen("","w");for(i=0;i<3;i+)for(j=0;j<3;j+)fscanf(rf,"%d",&arrayij);fun(array);for(i=0;i<3;i+)for(j=0;j<3;j+)fprintf(wf,"%7d",arrayij);fprintf(wf,"

15、;n");fclose(rf);fclose(wf);参考答案inti,j,t;for(i=0;i<3;i+)for(j=0;j<i;j+)t=arrayij;arrayij=arrayji;arrayji=t;第7题/*【程序设计】功能：判断一个整数w的各位数字平方之和能否被5整除,可以被5整除那么返回1,否那么返回0.*/#include<>#include""voidwwjt();intfun(intw)/*Program*/*End*/main()intm;printf("Enterm:");scanf(&quo

16、t;%d",&m);printf("nTheresultis%dn",fun(m);wwjt();voidwwjt()FILE*IN,*OUT;intc;intt;into;IN=fopen("","r");if(IN=NULL)printf("ReadFILEError");OUT=fopen("","w");if(OUT=NULL)printf("WriteFILEError");for(c=1;c<=5;c+)fscanf(I

17、N,"%d",&t);o=fun(t);fprintf(OUT,"%dn",o);fclose(IN);fclose(OUT);intk,s=0;dos=s+(w%10)*(w%10);w=w/10;while(w!=0);if(s%5=0)k=1;elsek=0;return(k);第8题/*【程序设计】功能：调用函数fun判断一个三位数是否"水仙花数".在main函数中从键盘输入一个三位数,并输出判断结果.请编写fun函数.说明：所谓"水仙花数"是指一3位数,其各位数字立方和等于该数本身.例如：153是

18、一个水仙花数,由于153=1+125+27.*/#include<>voidwwjt();intfun(intn)/*Program*/*End*/main()intn,flag;scanf("%d",&n);flag=fun(n);if(flag)printf("%d是水仙花数n",n);elseprintf("%d不是水仙花数n",n);wwjt();voidwwjt()FILE*IN,*OUT;intiIN,i;intiOUT;IN=fopen("","r");if(I

19、N=NULL)printf("PleaseVerifyTheCurrerntDir.itMayBeChanged");OUT=fopen("","w");if(OUT=NULL)printf("PleaseVerifyTheCurrentDir.itMayBeChanged");for(i=0;i<10;i+)fscanf(IN,"%d",&iIN);iOUT=fun(iIN);fprintf(OUT,"%dn",iOUT);fclose(IN);fclose(

20、OUT);intbw,sw,gw;bw=n/100;sw=(n-bw*100)/10;gw=n%10;if(n=bw*bw*bw+sw*sw*sw+gw*gw*gw)return1;elsereturn0;第9题/*【程序设计】功能：编写函数fun其功能是：根据整型形参m计算如下公式的值：y=1+1/3+1/5+1/7+1/(2m+1)例如：假设m=9那么应输出：*/#include<>voidwwjt();doublefun(intm)/*Program*/*End*/main()intn;printf("Entern:");scanf("%d&qu

21、ot;,&n);printf("nTheresultis%1fn",fun(n);wwjt();voidwwjt()FILE*IN,*OUT;ints,i;intt;floato;IN=fopen("","r");if(IN=NULL)printf("ReadFILEError");OUT=fopen("","w");if(OUT=NULL)printf("WriteFILEError");for(i=0;i<5;i+)fscanf(IN,"%d",&t);o=fun(t);fprintf(OUT,"%fn",o);fclose(IN);fclose(OUT);参考答案doubley=1;inti;for(i=1;i<