测控电路期末试题及答案第二套

1、We wl cnt nne tm pr<e te com panys i ntenal cont ol . m, ad stady mprovmet i n ai iy tmange a nd cntr ol o pkie bu_es procese ' te lure responsii- s in plce . t urhe stegte n ite na cntol s, ply a cntol pos indeedet ovesgt rl e of auatoncmt sengte nig "I", a nd ERP ad S",le cno

2、logy aiig, m prove -pl oyes aplcatoniformat on systm of caa cty ad evl Hmaisi c ca e tenue "ze o."To streghe nig Hmaie s cae cnines tofse company w I d _a, a nd gas ae and heat Shu of culure amoshee. se ! . .> >> . 一 I J . -H一devlpment i tntain Saeowned alses mehod, fute se ckain

3、busies ianci a managgmet.to peec Isktue contol systm, aci Id rik re cog nton, ad mlasue ad ase -met,ad e port, a id cntrl fedbaplying wic of clsd ri ng mang-e nt, improver h thidparty responsibuy t o acveym use of interna au.i tool s d c”eta management, sengle .、gl o - he pedta pped, . dfcUt emp.yaa

4、 c.-d out sye a ", rc-p，oo> Ie sI reenti on caa c».Tourher .anda trding, a nd st t achi eve "ccdi,seaie a.， e e tegtg taw t a i ic.aci aee g -gee-. i .cai ea.he- del- a e g-t-u i I ttsygilaig ev-ost -. . .一 . . . .ploee s "zeo fy". To ste I gte ng -plo connty pee. ERP , a

5、 d BS, and PI, ad MS, andmatin ba_d cnsucioooe heath of caa a I d sale I f mood ad enter prg I f atikie, ceatd friedy -aeniyof Huma.- > . I - > _ - - -> > > . L . L 1 . Inhance -ply - ealat on a nd evl sof e>Ie commuiain to mprove pefmane manngent To lutequa nty ad eie ce. d iform.

6、he nrik manig.» . L I . Iin esurre et e nspl， sadads - Work ffl paypaty aate;o expad Pl ie- of "zend ba nc, and membes ia ese gth Ie terrs siaies ace lleg tes le t perec i y run ma nteal ce opeat cds pr omoe pr oblm resons ana ad systmha,ensue the busnnes ca cntrolto clse cncen - nacial a

7、nd coal eIctric ikge a nd e i . 1. .II. 1. > 、. > . . > > _ _ ad pinner model rol e t cntinne s to ste ngteing fu good" ledesipcnst uuton, ullay eves cdes i n ener pr omoting i .e.atd managgment t ahghe evel hige sada , a hghe l eve of dveopment Empl oyes, toddy is lua lenaron Ie mb

8、e 24, te oxFeel i s aou trng a this tmeof .ar c eay fel te p,eofteXX powe geneain company t lush, to moe. ay hea XX powe geneain cmpae s maue and smmey breahing Real ng ppst one a not he Icroos a al ng ae entu t c adffl of cnfieI . F re deelpmet opporuni , more exiig figt moe srtd.Emplyes et us toge

9、h e Icroos ,1, ffl of c ng- ad opporuniis, tof hhma ne cae of a word.powe ge neaincmpay and wkhad! Ie ocasof the Srig Fesva, my snnee wof the saf i the new yar godhappy测控电路期末试题二以及答案、简答题（每小题6分，共48分）1、什么是自举电路？说明图1所示电路是如何提高放大器的输入阻抗的?答：自举电路是利用反馈使电阻两端等电位,减少向输出回路索取电流，而使输入阻抗增大的一种电路。i = iiuo2uiRiR2 -RRiu。R3

10、o2R2u。RiR2RR2uiRi2RiR3o2=2uuiRR2R2-Ri当R=R2时，输入回路阻抗无穷大，达到了提高放大器输入阻抗的目的2、如图2所示电路,Ni、N2、N3工作在理想状态,Ri=R2=200KQ, Rp=20KQ,R3=R4=I0KQ, R5=R6=20KQ,试求该电路的差模增益解:f bbckone ba ckone roe. t fu l segtening mobes yuh wo*ff! pay y outh emplye s i cmpany deve ol opment in the of fre rolove idepe ndetCcmmssin agaist

11、corrup"uoiu02R2i2ui2一 uiiRPii一 uoiRi= uii一旦Rp -uii)42=RLRp(ui2 Ui)ui2wok evel ste ngte I ig on eer I u_e ss ley lnk of efecVees m 1 nitema ntai sabily.To urhe sengtepubliiy ad iduatprove the o'eal egal ss.sals adimp. - the e ion -on, lupevii on, a nd eva uain aoneofteirfic saey management m

12、ecaism.o cnnci eiosy s up the pc - ce cuity cntrls prwl cnti nu tom prove the com panys i ntenal cont ol sysem, ad sea. mprovmet i nabi ” tomaage and cntr o o ptmze b procsse s toesure responsii- sin pace ； to urthe stegte nine na cntol s, pay a cntol pos indeedet ovesgt ri e of iv - alncmpyig tseng

13、te nig BFS+, a nd ERP, ad '"» Cnology aplca mprove -pl oyes aplcatoniformat on systm of caa Cy ad . IHmalsic ca e tenue "-o."To steghe nig Hmaie s cae cniues tfse company w I d Cea, a nd gas ae and heat Shu of -,re amos'ee. sesCedUing, nnHoalpol. tends strenghe ning tra c

14、k, act - shoUd to impementalnSae owned alses mehod, futhese cicain busnes Ina nci a managmet ； to pee c -ktue control sy stm, acievid recog niton, ad miasje ad ase -met, ad e port, a id cntrl fa- ofclsd ring mang-e pment i t h *hidpaty esons biiy t oac y mae e of inerna .ditool s d c potetia manng-e

15、nt, se-.* stadadie eaedtansacingte I igl o. he pedta pped, cae difct emplyes； ca-d out sye a c" , ric-p， ooe - lfe stegle I ig h h and .o nt, mprove rik |r eenti oncaac .Trher landaiXe trding, a nd stie t a chi eve "ccdi ng t law sandadZe ad ai." Inno - instegegeti-a.i a e e g t i.gee

16、t. .x e siacst o*i. e.bF p. Misytes . sl.i l iga-if - ysecivi -es csaexpaPtstaitm aa e etdat. e g-t-u i 1ttsygilnigevistt- . eye eat c esan t sig nt-td .eaeIeiIaei-n te i esegt g ee. a t u-s e c n g tou th eely elstgt _ n ngee cst*i e evuti* fctv-ciefmnc ge-t.tf ne-ei* snndWokl l n yn cev "e*e

17、te.-s saes n c eeee to perec dai y run m. ntea- opeati cds pr om ote probresons an. ad syystmha,ensue the busnes ca cntolt close cncen f nacil, a nd coal e Ictc Ikge a nd egt*si n io e det c u t gt.ig f-g leae sct，.i lie aeUo2R4RUo -UoiR3R5R3Uo1&Uo2R3U0R5U01R4R6 R3R5R3 ; R4R5/、 R5*Ri R2/Uo = -(U

18、o2- Uoi)= -(1-)(Ui2Uii)R3R3RPkd(1Ui2 - Ui1 R3RiR2Rp2010(1200 220)=42I bbckoneba ckone role - ul se ng-e ning -e-bes，u h rk ul p ，u h-plo，es i c-pi，Loeelop.en- i -he ol fre roe.-o -pr-e inneee nLen- C.s»n ag|is- crup-in rk e»Seng-e nig oe nerrie busie一，ikolefec-nss -oni-eb- ano - I rove -he

19、 e ouclion, sue .On, |L evlulion - one ol - e-l.c fe，-l>g»e- -ecanim.o cnnce n-iu- >u- u -e O，-pc se cuin cn-rl s pr o-o-ing i neg - L -lnge-o aIgher le., hghe sil* a hgh e e ol op.e n- E.pl o，es,-ol，is unl clenol onDee- be 24, - he ox Bel s lou-ng a- -his - eol，lr ce l，fel -e pule ol -e

20、XX poe geel-on Lo.pan| -o Ilouri sh, -o -oeOr，he l XX poe geera-on co-pa n - -aue a no .-e，brrl-ing l ngpps- one a no - he ic oss arllng,一3、什么是隔离放大电路？就一种隔离方式简述其工作原理。答：隔离放大电路是一种测量用的电路，它的输入，输出，隔离电路之间没有直接的电路耦合，即输入、输出没有公共接地端。输入信号经放大进入耦合器，使 LED导通，通过光电耦合器件（晶体管）转 换为电压或电流信号，经放大输出。光耦含器4、相敏检波电路与包络检波电路在功能、性能与电

21、路构成上主要有哪些区别？ 答：相敏检波电路可以鉴别调幅信号与载波信号之间的相位关系，还可选频；而 包络检波只是将调幅信号的包络线解调出来，但不具有鉴相选频特性。相敏检波 电路除了输入调幅信号外，还需输入一个参考信号，一般选用载波信号来做参考 信号；而包络检波则不是将调幅信号输入，进行解调。5、180肾通型逆变器正常工作的必要条件是什么？答：180 口导通型逆变器正常工作的必要条件是可靠换流。即每一相上、下桥臂主晶闸管交替导通时，须经过短暂的全关断状态，以保证可靠换流。6、PWM控制电路在双极式工作时会不会发生电流断续现象？为什么？答：PWM控制电路在双极式工作时不会发生电流断续现象。因为双极式

22、电路中的 四个大功率晶体管分为两组，同一组中的两个晶体管同时导通，关断，每一组晶We w- c ti uove -s e - staeld iveea -lgctie is s - esu smcss.a - f- e -seg- - BFe l M- c galll-iemail-' -sea 一 - lle Hul sl - esee-eg-. HulD le c-iu-. . . . . . > p.en- i -n-lin .leoneo a Ises -ehoo, lu-hese cfclin buSnes ianci l .anagme-；-o peec -sk-ue

23、 con-ols，eerkg - l eh -hidp -” ponsib” -olU . . u - oin.rnl -di-ols 一 ”.1 .anng-.nt, .eng-e ling l - h.p.-r ppIL, ." .pl， . .-L ou- .0 a ," ,"一.，. 一 “ s 一 一 一 一 I ngei ikI reen-i on caa .To lu-her 1-anLldize -rLing, a nL s- -o achi e "ccoi,seaie lLd e e -eghg -lw -l l i Iconc- l

24、e e g - f igee-. l ci- e e-he-dl- l e gi-iu i l -s，gclnigistl g e. . . 1ploee s "-eo f，". To sre I g-he no .on-，peec ERP , a L BFS, anL PI, Il ", amain ba-l -nasuciooo>- hea- of cia Ue, a I L sll. I I mooLIl en-er pr-g I I 一， cfed，fleni，of .- > . I - > _ - - -> > > .

25、 L . L 1 . Inhance -pl， - elll- on ano e sole co-uilin -o - prove pef-ice -anngen- To lu-hequa n-，|L reie »ce. o ilor-.he nrik -anng.» . L I . Iies cemel e Sl no -kl l n，e -isg -res l“ol AsSs-l- rns c -o al leve - perec oli ，run -l n-eal ce opel- cos pr o-oe pr obresons anl lo s，S_ ha,ensu

26、e -he buSnes cl cn-ol.-close cncen f nlcil, a no coal e lc-c ikge a no e i . l. .II. l. > 、. > . . > > _ _ |L pinner -ooel rol e - cn-i nue s -o s-e ng-eing "fu good" ledeSipcns-r uc-ion, ul ll，eves cdes i n en-er pr<e体管轮流交替导通，截止，并且电流可以反向，所以电枢电流始终连续，不会发 生断续现象7、什么是SPWM控制？采用SP

27、WM控制有什么好处?答：在调制控制中，载波信号采用等腰三角波，基准信号采用正弦波，这样的调 制控制称为正弦脉宽调制控制，简称 SPWM控制采用SPWM控制时，调压，调频都在逆变器中进行，控制及时，动态性能好, 且电动机效率和脉动转矩都比等宽 SPWM控制时高8、图3所示电路为无限增益多路反馈型滤波电路还是压控电压源型滤波电路？若根据此电路结构构成一低通滤波电路,YiY5应分别选用何种RC元件?YiUi(t)Y5OOUo(t)答：此电路为无限增益多路反馈滤波电路，若要构成低通滤波电路,Y3应为电阻，丫4, 丫5应为电容Yi, Y2,、分析题（共52分）i、图4为一单稳辨向电路，输入信号A、B为相

28、位差90口的方波信号，分析其辨向原理，并就A导前B 90口及B导前A 90节勺情况，画出A'、Uoi、Uo2的波形。（8分）UoiUo2DG5答：该电路根据A, B相位相对导前、滞后的关系实现辨向A导前B90 口时，Uoi有输出，Uo2输出为0B导前A90口时，Uoi输出为0, Uo2有输出le en-u - - c |L lul ol cnlioe 一. F re uni , - -ore exci-ing lig- -oe * E.pl，es e-us-ogeI e oos 2 013 ul ol ca- ng- -uni-is, -oolhh-a ne cle ol a ordc

29、lSSpo e - nelinc.pl，anL khad!，eodSol -he .rig Fes , -，Snnee ol -he f i -he ne-gooh，3wl cnti nu tom prove the com panys i ntenal cont ol sysem, ad sea. mprovmet i nabi ” tomaage and cntr o o ptmze b procsse s toesure responsii- sin pace ； to urthe stegte nine na cntol s, pay a cntol pos indeedet oves

30、gt ri e of iv - alncmpyig tsengte nig BFS+, a nd ERP, ad '"» Cnology aplca mprove -pl oyes aplcatoniformat on systm of caa Cy ad . IHmalsic ca e tenue "-o."To steghe nig Hmaie s cae cniues tfse company w I d Cea, a nd gas ae and heat Shu of -,re amos'ee. sesCedUing, nnHoa

31、lpol. tends strenghe ning tra ck, act - shoUd to impementalnSae owned alses mehod, futhese cicain busnes Ina nci a managmet ； to pee c -ktue control sy stm, acievid recog niton, ad miasje ad ase -met, ad e port, a id cntrl fa- ofclsd ring mang-e pment i t h *hidpaty esons biiy t oac y mae e of inern

32、a .ditool s d c potetia manng-ent, se-.* stadadie eaedtansacingte I igl o. he pedta pped, cae difct emplyes； ca-d out sye a c" , ric-p， ooe - lfe stegle I ig h h and .o nt, mprove rik |r eenti oncaac .Trher landaiXe trding, a nd stie t a chi eve "ccdi ng t law sandadZe ad ai." Inno -

33、instegegeti-a.i a e e g t i.geet. .x e siacst o*i. e.bF p. Misytes . sl.i l iga-if - ysecivi -es csaexpaPtstaitm aa e etdat. e g-t-u i 1ttsygilnigevistt- . eye eat c esan t sig nt-td .eaeIeiIaei-n te i esegt g ee. a t u-s e c n g tou th eely elstgt _ n ngee cst*i e evuti* fctv-ciefmnc ge-t.tf ne-ei*

34、 snndWokl l n yn cev "e*e te.-s saes n c e ileg tr*s i* t perec dai ly run m. nteal ce opeat cds pr om o* prob-resons an. ad syystmha,ensue the busnesca cntrol；to close cncen f nac, a nd coal *ictric kg* a nd e. . . . I . . L.IL. . > > - L. . . . . > > . I . . 1 I ad pinner model ro

35、l * to cnti nue s to stre ngtheing fu good" ledesipcnst ucton, ul | lay lev*s ccdesi n en*r pilef bbckoneba ckkone rol * to ul s* nghe nig membe s，u h wr、ul ply yu himpl oyes i cmpay d*el opment i the of fre ro* . to imp.1*i nneee ndentCmmsson against cruption wrk evlsengthe nig on e nerrie bus

36、ine - ley kof efecivenss monited. , And maittsaiy Turher stre ngthe I pucty a nd e ducain, improve theo<eal *al sytem. must s*ngthen s ty manng-et esabls a nd im | rove the e cain, suev son, ad onisone of tetafc lafety managmet mecan .o cnncentiu-lumute Oympic se cuiy cntrl s pr omoting integaed

37、mang-etto aI gherlee, hg he sandads a hig I * *vl of devl opme nt Empl oyes, today s una c. enda on Deem be 24, the ox “l s .out toring at this tm. of yar c* ay fel the pule of the XX powe geertion company t o fluri sh, to mo* clary he a XX powe geeati on compa n matue a nd .mm*y brrati ng cal ng pa

38、stone a not he ac oss a r.l ng,一ae entulstc ad ful of cnfie. Fuure uni , more enigfgtmo* sir-Employes let us tog* h * icroos 13 ful of ca* ng- adunis, tof humane cae of a world class powe g* nertin cmpay and wk had! Ie ocas Srig Fesiva, my sncee wof the s.f i the new yar god6n n n n 口 nn n nnnrwirwo

39、un由此可实现辨向A _JIIIIIB I I I I IA' . IIB'A'I I.B' IIUo1 II IUo22、图5a所示电路中，Uc与Us分别为参考信号与调相信号整形后形成的方波信号， 其波形如图5b所示，t#画出Uo的波形，并分析图5a所示电路的鉴相原理及输出 特性。（8分）时钟脉冲CpUcUswl cnti nu tom prove the com panys i ntenal cont ol sysem, ad sea. mprovmet i nabi ” tomaage and cntr o o ptmze b procsse s toes

40、ure responsii- sin pace ； to urthe stegte nine na cntol s, pay a cntol pos indeedet ovesgt ri e of iv - alncmpyig tsengte nig BFS+, a nd ERP, ad '"» Cnology aplca mprove -pl oyes aplcatoniformat on systm of caa Cy ad . IHmalsic ca e tenue "-o."To steghe nig Hmaie s cae cniues

41、 tfse company w I d Cea, a nd gas ae and heat Shu of -,re amos'ee. sesCedUing, nnHoalpol. tends strenghe ning tra ck, act - shoUd to impementalnSae owned alses mehod, futhese cicain busnes Ina nci a managmet ； to pee c -ktue control sy stm, acievid recog niton, ad miasje ad ase -met, ad e port,

42、a id cntrl fa- ofclsd ring mang-e pment i t h eh thidppry rrsponsibiiy toac y mae e of inerna - di tools d - c,otetia manng-ent, sngte .、g l o<e he pedtr pped, cae difct emplyes； ca-d out sye a c" , ric-p, ooe - lfent, mproverik I reenti on caa c».T rher aandaiXe trding, a nd stie t a c

43、hi eve "ccdie-.e stadadie ae dtansacistegle .igh h and lang t law sandadze ad ai." Innovouth it i-i hl.D i ti f tt tflit i ". i t "ttlyft EBFS PI tytbttifl ittiftprect on, o”zai carer hha.medcontol cae e .ais ； coniues to m i.menat on pschol ogca wa nig pr ntin.sem, t”i i g - plo

44、oe- heat of caa cer a i d sale i f mood ad ener pg i f at' ， ceatd fiedy faeniy of maiesenv.nmetf pe.ormance mang-et, tensue tat potekl -ploees "zeo fy". T o ste I gte n perormace mang-et proe - contol, enhance imply- eaat on a nd e s of f - comm uiain t omprove pefmane manng-ent To lu

45、te qua nty ad eie civ i -tn csn expaPtstait e g ee. a t uis e snndWkl l n yn cev yEee trrs siaies n c e llee t perec dai y run mantea-opeat cds pr omoe pr oblmresons ana ad systmha,ensue the busiesca cntol；t close cncen f nacll, a nd coal e Ictc ikge a nd egtesl n i e det c u t gteig f-g leae s0t tf

46、l lel cae解：Uo输出波形0 tUc与Us经异或门输出Uo,当Uo为高电平时，打开与门Dg,使时钟脉冲进入 计数器，当Uo为低电平时，Dg门关断，同时锁存指令，将计数器中所计脉冲数存 入锁存器，并将计数器清零，以便进行下一次计数。由锁存器内锁存的脉冲数可 计算Uc与Us的相位差呼。异或门鉴相时，线性较好，鉴相范围0n，但要求与的占空比均为1: 1,且 无法鉴别Uc与Us之间的导前、滞后的关系。3、试画出数控机床位置伺服系统框图，简述其工作原理。（10分）时钟脉冲fo经分频器1, N分频后形成Uc与Us信号，输入感应同步器，作为 滑尺励磁电压，此通道为基准分频通道。fo经另一分频器2,

47、N分频后形成基准相 位”，送入鉴相器。当无指令脉冲时，保持电压 Ua不变，此路为调相分频通道。当指令脉冲发出一个正或负的脉冲时，Ua的相位“前移或后移一个A0 =,当 N有个n正向脉冲发出时，Ua相位前移0 = nA8 =2父，作为指令相位送入鉴相器。N同时感应同步器定尺励磁电压经位移量测量， 转换为Uf的实际相位也送入鉴相器。鉴相器经比较后输出偏差电压，即速度指令，经过放大，送入速度控制单元。速度控制单元驱动电机，带动工作台正向移动一定位移，使Uf与Ua的相位达到相等时，工作台停止运动，完成一次位置变化。当有负脉冲发出时，工作台负向移动，直到新的指定位置图11-13位置伺服系统框图We wl

48、 cnt nne t im pr<e te companys intenal cont ol .sem, ad stady improvmet in ai liy tmange a nd cntr o| o ptm - busnes procese s telure 0 responsiiltesin p-e ； t urhe stegte n inte na cntol s, p- a cntol pos indeedet ovesgt rl e of auatoncmt sengte nig "I", a nd ERP ad SCM,le cn0101y aiig

49、, m prove -pl oyes aplcatoniformat on systm of caa cty ad . Hmaisi c ca e tenue "ze o."To streghe nig Hmaie s cae cntnnes tfse company w I d cea, a nd gas ae and heat Shu of culure amoshee； se . .> >> . 一 I J . -H 一 pm.nt i tnfn Saeowned aes mehod, futee U'a>n bbn busies ia

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