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1、资料收集于网络如有侵权请联系网站删除谢谢第二十三章必做题:4,10,12,19,224:tn1hepolenlialatIliesiufaceofachareedspliereisderivedinExample2>-4.Q=-TP=4许j*->4呻f旦二冬二Aiea 4;T,j4 斤%为(680 V)停 £5 Ml二 C:Nn)2)10 16m)二二 761 xlVc/uJ精品文档之B-gxlO*'c/in2(切ThepoieufiAlawayfromthesurfaceofachargedsphereisalsoderivedinExample23-4理T】)

2、软。、)-,嗝10:Thepotentialatthecomeri$thesumofthepotentialsduetoeachofthecharge孔usingEq.23-5,心】(”iq!ii-2p(?r1t4工易区14-w0f4飞I耳12:Wefollowthe4exe1npinenTofExample23-9bwirljFigure23-15,ThechaigeonaThinrinofradiusRnndihickiidRw岗=cdA_irlRdR).UseEq.23-6btofindfhoporominof口contiinLoiischargedistiibution.一c=F4G十

3、'一W+屋)19:升HieelecTroiiacceleiiiTedilnongtiaporenrialdifieienceof1.33(movingfianilowpotentialtohi必potcntinlmgcuiuig1.33keVofkineticenciy.Thepioton居accelciatedthrouizlitheoppositepotentialditfeienceastheeleciron.andtheexactoppositechnige.Thusihepiotougainarhesamekinericenergy,133kgV.3)Butli山t?pil4

4、ohduddieeleclullhde山dsamt?KE.I_e山MloEndLheiliool山dspeeds.±2.2vefriTfl.67x)O-;g二->不也.I产4二Tlie1iabterelectronismovingabout44timesfasterthantheheavierpicton.22:Iet,representrhedistincefromThelefrchargetopointb.nndleTd、representtliedistancefromthenglileLaitopcinib.Lei0lepie-eui(bepositivechaiiie

5、s.andlei</tepitbeintheueiiainecliargethatmoves.TheclmngempctuntialenergyisgivenbyEq,23-2b.4=l27+147cm-1.41cmd.=J14'十2cui=27.744cmL;-Li-T)=(/-江+0J2m U.241H*,4fLi0.1£44山0.27784gl 110,1844 hl 0J778 in / V 0.12ui 0.24 m j=(g.99xl0*NtmVc1)(-L5x1OC)(33xlOCjf-S4TTm_1)=1547J|1.5j|第二十四章必做题:5,7,9,

6、11,185:We apply Eq. 27-5 to encli eireunisTnnee. and solve toi1 (lie magnetic field. LeT B =i + 瓦j + 区kFor the firt ci rcn in stance, / = f i.Fa=J/xB=(8.2A)L.0in 0一0116 4Ann) Rj + (16,4A*m)5¥k =T纥=0 : (-16.4A*in) 二-LfNFor the second circilinst.nice. / = f j.Fi - J/xB-|8.2A| 0 2,01H 及。-> B -

7、= 0.1524T + B unknownfi.4A*mk0-(2.5N)i + -J64A*ui)5 k -(2.5i-5 0k|N ->0.1524T=-5.0N-50N> B = 0.3049 T16.4A-111Thus B-(030i + 0,15k)T7:The velociry of the ion caq be tbiuid eiieiy cousei valion. The ekcii ical jJoteiiTial energy nF The i(in becomes kineiic enei gy aq it 】x occelerated Tlien, si

8、nc<? ihe ion is niitviug peLpeudienlLU to die iLuiietK IlekL Ilie inagneiiu fence will be a uiiixiuiiiiii. fhai force will cause the icu Io move in a cuculai pith.Fj-中R-mflIf®511l2(6,6x102700V)i.天勺力丁一诉小网Jc);国逅TIk period cnn Ik fbiuul ft om the speed and tlic ridiiK. Use the expressions fbi t

9、Ik i门山in mul the speed Hom abo c.Um9:TheforceonrheelectronisgnenbyEq.二7*5乱MAI'JkR二6xB二一e7,0x10"M与一6一0父10上口1/$0二一炉(42-4.8)x10,T*m/sk-0.80T0-60T0=-(.60x10-,?C)(-0.6xT*m/sk|=9.6xkmIx!01;Nk11:1'lietotal,frrceouthepretonisgivenbytheLorentzeiiatioii.Eq2-|PAA+NIJ?(E+vxB)=e(3.0i-4.2j)xl03V/iu+&

10、amp;0xlY叫人3.0xl05ni/s0.45T0.38T-(1.60x10TPc)(a0i-42j)+(L9i-2.25j+0.93k5x10$N/C(l60x10JQC)|4.9i-6.45j+0.93kx10TN/C=7,S4xlO|4ii-l.O3xlO-j+149xlOl*k)N/<,(O.7Si-l.Oj+0.15k)|xl0-,-N-5.0xl05ins18:9)3)GThemagneticmamentofthecoilisgivenbyEq.27-10.SincethecurrentflowsintheclockwisedirecrioiLrherihrlinndnd

11、eshowsthnrtIiqmaaiKtKinomeinisdown,orinrhenetafivcz-direction.jim=15(76A)T|-k)=-l.JMkA-m2-4.3kA*m2WeuseEq.27-1JtofindthetorqueonrhwcoilF=口*=(T,334kA-m3)x(0,55i+0.60j-0.65k)T-(2.6i-2.4j)ni-NWeuseEq.27-12tofindthepotentialenergyofthecoilr=-(-4334kAn2|(0.55i+0,<50j-0T65k)T=-(4334A-nr1(065Ti第二十五章必做题:

12、6,12,13,15,16,246:Ihemngueticfieldattheloopduetothe1口口?wjieisintqtliepage,amicanbecalculatedbyEq.:X-I.Theforceonthesegmentoftheloopclosesttothewireistowardsthewiic.sincerhecuituiiKareinrhestniiedirection.Tli!?forceonflic&总gmontofrbehopfnnhesrftomfhwire"nwayfionirhowire,sincetheciuieutsarein

13、theoppositechiecrion.BecausethemagneticfieldvarieswithLljhkince,ilismoredifficulttocalculatethetoialforceontheleftandlightsegm?utsoftheloop.UsingtherightliAiidrule,theforceoneachsmallpieceofTbekfisegmentofwire话totheleftandtheforceoneach帛innllpieceofflurightsegmentofwireistotheright.Ifkitandrightsmal

14、lpiecesarechosenthatareequidistantfrom(helongviie,ilienetiorceoutwot山h11piecesiszero.Ihu>thetolalibivccuthelejftandimhl>etiiiuhotue1、zero,andsoonlytheparallelsegmentsneedtobecousidereriinthecalculationUseEq.2g-2.=*WAf助I12开I0月30m0.080m!=5.1x10*N,towardswire12:WcusetheresultsofFxampk28-10tofindt

15、hemaximumandLiiiibiinnmfields.pg(4不乂1。"IA|(637)(25.QA)匕了丁2(0270m)lx_喇_(4xO'7T-nrA)(687)(55.0A)''''J.b/LILLX,1*imn2,t(0.250in)12.7mT<.5<.13.7mT13:Becauseofthecylindrical$yium<tiy.ihemagneticiiddswillbecirculaiIncndic:i优,caijdvtainiiicThemognikheldgingAmpere'shuwi

16、thconceiniicloopsThecurrentdeiisitiestnth?wiresareinenbythetolatfiuieutdiitlei.lby(lit*cioss-sev'tioiKilaiea./_Atj_Aja一就g,一从段一理)I。)Luside山eUiiieiwne比ht-nclosedkiimeuiisdeteiminedbythecniTenldensityoftheLimeixviii?.§通濡=炖411tl=马人阳厅五一)B("R卜"絮T毁(7>jBenveeu山/wires由小cuieiueuclosedi$t

17、hecuhmhoniheinnerwik:何疝=死411dT5(2,Tfi)-/D7flT(c)Inside(heoui«wiiethecuiieiirenclosedisthecurientfiomtheiuuerwiieaAdpoitioDofthecunenrtroiniheouliwire.豆曲二死=餐,c+J-terR炉-Ril_3二小(用一川)2叫&-后)."rn五,一四)R为H/#(传-生)B r/s =0ci =0> B LtR) - 0>B = 0SiOutsidetheouterwirethenetcurrentenclosedisz

18、ero.(e<Seerhesdjcctitgraph.Thespieiidsheelusedtbr山i+piebltfiucanbefoundonthehJediaManagerwithfikmmePSEljSM_CH28,XLS.'onlabProblem2b.31e"15:Silica也残pointCisalongrhelineofth片twostraightsegmentsofrheciinenr,seginenlsdoucicoutiibutelu(lieindiziieticlieldurC.cakulaklited£ xf& 47j足l闻d

19、id尹i M 5 J4砒magneticfieldbymtegiatiiigEq.2S-5alotigthetwocunedsegineuts.AloneeachinreerationthelinesemeiiTisperpendicuhrtotheradialvecknnndtheradialdistanceisronwm._v/QRn/®金_咫16-M16:Sincetheciiifentinthetwostraightsegmentsflowsradiallytowardandawayfiointhecenteroftheloop,theydonotcoutiibuietorh

20、emagneticHeldat(heceoter.WecalculatethemagneticfieldbyintegintinoiEq2S-5nlongtIjcnvocurvedsegments.XiongeachiiiTcgmtionsegtiint.Theciurenf包peipeudiculattotheradialjectoiandtheradialthstanceiaconstant.Bythelight-hjud-rulethemaguetiefieldfromIJieupperportionwillpoiniintotliepageandthemasneticfieldfiom

21、thelowerponion will 如nt out nffhe page襄'4於1ik(O.35Z-OS/) =4RIG(G24:Wesetthemnwnutisforce,ushikEq-2S-2.equaltotheweightofthewjieaixls(?lpe161th号ufcesaiyslukhLThecuneiitmustflowiuthesamediLectionastheuppticthichI.fordietimnetLClorcctoh?iipwAid.360 A. uglit/g/r/|S900kg/n?)(9r80inJ/sJ).?J(0.050m)(1.

22、00x10'山广2-4g2(4.7X10TT*m/A)(4SX)A)一Th心LowerwireisinhiKkibh它quilibriiuWsinceifitisrnisedslightlyfromenihbniini.theiiiagneticforcewouldbeincreased,causingIhewireIcinoeiurtliei'fiomeqiiiltbiicun.ftheivireissuspendedaboyeihetiiAiwirearihesamedistance,thesamecuneutisneeded,butinrheoppoiredircctin

23、iLasrhewiremuybe子目而(1佗cunthelowwwiretoremainineqiiilibiium.ThciufbiuIlieciureinmuslbe3604【utheleftTinsi&aequiHbiiuui|fbiveilKilldisplacementsuieeif山e相lieLmovedshulitlvc>lT山?eqiiilibmiuipoiiH山?inagiietiewilliiicreaecrtopushthewnvbackiotIkequilibriumhidit.第二十六章必做题:2,3, 15, 162)We choose up as t

24、he positive diiection. The m induced emf is given by the diiJerence" veion of Eq. 29-2a3:A/.7 (U,54in)? I-0.251 - 0.6ST)0J6s(ei hen the plane of tlie loop is jKipundiciilar To the field linc. the ilnx is pivei) by the iiiaxuiiiiiii nf Eq. 29-la,=B且= Bn" =(0.50T)t(0.080inf10乂10“加3) The anal

25、 is - 5?c_(e) Us*? Eq. 29-1.中占二及代x8 = (0.50T)(0.0S0ni)?cos= .8x £Wb15:The magnetic field inside the solenoid is givn by Eq. 28-4, B = "7/ Tse Fq 29-2a to calculate the induced cnif The flux causing the einf is the flux through the small loop.d力招& - - *1"df由用.、i:=一昌=-44/乂 一3人sin d)

26、= 如。$in酬 di16:(加Because the elocih_ is peipeudjulai t<? ihe luaguhc field and the rod. ive find the induced eiuf from Eq. 29-3.£ =86 = (V 35T)(0.250mHl 3m/s = O.113S lo.ll VFind the indiKtid cun'eut from Olmfs hvb(i$iug iheresistance0.J1SSV2S oq . 2 soir)Theiuditcedciui'eulinthetodwi

27、lbedown.Becausethisciuiefitisinan却wardmflgiietktleld,rheiewillbeamagnetictbretorhekfr.Tokeepfilerodiiiovine.theremustbeaneqiuilexternalforcetctheright,givenbyEq.27-1.A=2=(1.13810+A|(U250tn)(U.35TI=3.621xlu4Ni|036iiL>'第二十七章必做题:3,5,10,153:Viiin<UtheinotualniducLui<eoftlitliiueiloopfweassu

28、iuetLtouietsoleiiuklisciinyuiifcutienl.V/rtlieiithemasneticfieldinsidetheoiitersoletiaidisH-IyThemagneticfinstlirousheachN并汹J也泄dMH5ui(?八一A"floopofrh&sibaIIcoili%thetnagnertcfhldrimesrheirenperpendicnhrtorhefield.TheinunnliutiIKlanceisgivubEq.30-1.jV上中非=£*与inH11名与inH;M5:Wedrawtbecoilast

29、woelementsinserihandpureresistanceandapureindnclanceThereisavoltagedropduetotheresisranceofThecod.givenbyOhmshw,anda口inducedemfduetotheiudiittimceofthecoil.enb>Eq.SO-5.SinceItiecmieutisiucleasing,tlieindiiciancewillcreate?apolentiaJdifteiencetoopposetheincreasingcurrentnndsoilieicj$adropinrhepote

30、ntialdl 二尔* L dtdue(o(heiiLdiKUince.Thepotentialdifleieuce在thecoilisUw、iiiuofdietwopotential山。p$.(3.00A)(5.25Q)+(o44H)(3.60A/s)二113V10:(口)WhenconnectedmseriesThevoltagedropsacros:;eachinductorwilladd.whilethecurrentsine;idiiiidncti;nethesanit(Z>)coimectedmpuLel(becimeiihiueachiiKluctoizddtotheeqi

31、uxakuicuueui.whilelitevcllnyedicpacrosseachinductoiisthesame前、theeqiiivaJeiilroJtagethup.TlitKtbie, nulucioii iu %由ie% ;Hiilp;ih山臼;iJdfhe 5ame leMiruii m ±efie% Jud p unlld.15:WecieateanAmpeieatiloopofidiusrtocalculatethemagneticfieldwiThinthewiteitsiugEq,283.SincetheresuliuiQmagneticiiejdonlyd

32、epends0口iadiu$,weuseEq.30-fortheLumiyydensityiu(hediffereotiMvolumed尸二2andintegrateHoazerototheradiuscfthewire.1R疝-户"t别|=%2mfr =用'4 ( /赤=4湾£ &第二十八章必做题:1 , 5, 8, 101:Thu ciuient in th wiies miit also bu tbt displanient ciuint in tlic capacitor; Use Hwdisplacement current to find the

33、 rate at which the electric field is changing.f dE GE %(2.8 A)7rj =%且 > =-出 由 小(S, 85 x 10-12 C2/ N * nr ) (0.0160 m P1.2xO15 m»s5:(mj If we write the argument of the cosine function as iz + H 二 制二 + ct). we see that the wave isn iehng in Thedirection., or 民(b) E aud B aie perpendicular to c

34、'ticb other and to thu duectiou of propagaUou. At die on am, theelectiic field is poiuuug in the positive x diieviiou. Siuee E B must point iu Ilie negative rdiiection. B imisT point ui the thedirection、or |-j |. The inaninide of the nmpnetic field isiuiiud tioiu Eq. 51-11 as & =.8:2*(月)Theg

35、eneralformofaplanewaveIciveninEq.31-7.Forthiswave,E、=EQsin(Ar臼I.°二n-SL60m|82in|0.077m-11J2.3 x lO7rad/3.661x102 工 3 7MHi工工1.71NotethatA/=(81.60iii)(3.661k10Hz)=2,987x1(1*11/9«gbHieinacnimdeofrhemasneticfieldiseivenbyH.二E、/c1hewaveisTravelinainrhektlneclitju.andsotheruavuelicfieldmuslbemihe

36、jdiieclion,suiceihedutetiouofisgivetibydirectionofEBB:一=”57m°3Q0xl0fimAB-j|7?0x1(FT卜山”0.07711rlz-(2Jx10'rad/s)zi10:Themergvperuimareaperunitrimeisgiwnbyrheuwgnimdeot(hePoyufuii;ector.LetjicprescjitrheenergyThatcrossesareaAiwntimeH¥% HA/也r-W)。,匾加工4小皿(l.OOxlOn)'!(3.00x10*in/s)(225x10

37、“T-二Fm10'sm?21da户第二十九章必做题:5,8,12,14,16,26,27,31,33,365:Forccmstmctiveinterference,thepathdifferencekamultipleofthewaveleneth.asgn-enbyEq.34-2a.Thelocationonthescreenisgivenby丫=f幅】包asseeninFig.34-7(c).ForsiufdlJingles,wehave%in&=lau0=r/.Secondordernieaiijh-,.,r,和雇梆fnshipmA>tihiA>.v:1二一:

38、V,>£1(/d汕frr20-660)xl0ml(2K1.0m)一ix=Jr,I=j1.76丫10-1mt0.2niiud(6.8xl0iu)Thisjustifiesusnistliesmallanaleappioxuiiation,sincetyt8:Fnccnsti'ncfiveinterieiire,thepnthdififenenceisajiuiliipkofthewaelencstlj,龄giv即byEq,M-2a.ThehcationonHiescreei)isgivenby.r-/愠n也摘seeninFig.34-7(c).Forsmallangks.

39、wehae5iu廿三Umt)土与F.山昌,力,A展(680xl01)(3)(2.6iu).(7帛mi0-mATa=tnATa=H-L4x1。mf汇38xO-3m12:Weequatetheuxp邱siotiiivmEq.34-2aibrthesecondord(?rbluelighttoEq34-2b.sincerheslitsepnitionandanglemustbeThesameforthenviicondiriontobemetntthesmnelocation.d&in&=rtfAt=(2)(480nm)=960nm;Msin»=(川+1)儿"=0

40、.L2."+;%0nm-0>k-920nm:W=tA640mntuf-2f/I=384nmTheonlyoneisibleis640um384nmgnem山白lo-wa(?leugthlnmttbiisil>klidn.14:AnexpiessioiiisderivedfbitheslitsepfiLEitionHornthedata£bithe500hihlight.Thalexpi'essioilisthenusedtoluidihelotatiouofJhi:maxiuiatorIlie651Juinlinlit.Foicontii.ictivem

41、terieieiice,(he>athdiHeiviiceis#nuiltipleofthewavekngtli.asGivenbyEq.3-V2a.Thelocfiiiononthescreeiiisgivenbyl二f冶n仇ns$«eninFig34-7(_c)rForsnillnpks.wehavesintf胃片9舞邛,d=fr/At"二ntXtd=/U%sJ650nm)(2),-,产x'2=12iiun)=10,4mm至10mm12sie.tie.)Ti16:Tochangethecenterpointfromeanstnictiveinterfere

42、ncetodestructiveinterferenceTliephase*hiftpiodueedbytheiiHioductiQUofThepla5tlsmustbeeqnivakut(chalfawavelength.Tliewavekugibofthelightisshorterintbeplasticthaniutli«air,sothenumberofwavelengthsintheplasticmustbe1?RreMeith、iithenutubeiinthesaiuethicknessofair.Thenumbei'ofwaveleuathsintheJr-

43、"-,-"'"''''一“日diitancrequaltoth?thicknessoftheplateistbcthicku?sEofthepht«dividedbytheappropiiatewnvelength=R70nmfrSOntn2(1.60 1)26:An liicideiil Wiixe tliai lelkcts lioni the top ut l;ice of Ike coating lias a phase change of 矶=开. An incident wave that reflec

44、ts fiom the 口1wa ,盯 * I 5) at rhe Iwltori surface of the coaling 1% a pluise chaiige dikr Io LmIIi ihe adcLilioiial path 1 己ngth and a phase change or ton reflecrion. so(h "冉二 - 2x + zr. For constructivewith a41m jtlutkutfss of culling, llie uel phasein list bu 2.t.IlieleuteileisthemostfurA-57U

45、mnHiemuimiuiunon-zeio±icknesi-口nur*fbr加一1:A <570 nuil 2 2(1.25)22 S ini jSincerhemiddleofthe>pectmiiisbeingseleciivelyreflected,thennEismiitedlightwilllesnongcrintheredandblueportionsofthevisiblesvectrunL27:(f7)5'henilhmiLiitedfromaboveatA.alightrayreflectedfromtheair-oilinterfaceunde

46、rgoesaphaseshiftof/=n.Arayreflectedatrheoil*waterinterfaceundergoesnophaseshiftJftheailthicknessalAisnegligiblecomparedtothewavelengthofthelight-thenthereisnoafgnificaiitshiftinphasedueto.pathdistancetraveledbyamyintbe<nLThusthelightreflectcilhonithehvubUiSuemuildchtii)ctivulyinteiletefbiallvisib

47、lewavelenstlis.andtheoilwillappearblackwhenxlewedfiomsbove.3)rromthediscussioninpail(a),thslayreiletkdHumthtuu-oilinletiaceimdeigceshplisseshifrnf*=匚AraythaireflectsfromThet>il-waTerinterlaceh"nophas.echangedueroreflecdou,buthasaphasechangeduetotheadditionalpathlengthof也construeHvi?niieifere

48、nce.thenetpha&echangemustbeamultipleof2t.21T"3)T ""阳斗芳瑞二找"外j oFromthediaciam.weseethrupointBisthesecondthicknessthatyieldsconsmictiveinterferencefbt5SOiii】landsoweuse»i=J.(ThefirstlocahontliatyieldscoustnieTieinterferenc?wouldbetorm=0.)580111111.50290nm31:With inspect to

49、 the ujcideni wave, Hie iva e that retlecis iroiii tbe air M the top surface of the air layer has a phase chauge of 4=0. With i*especf io the incidcut wave, the wave thai reflects &om the glass at The bottom sm face of the air layer ha& a phase change due 10 both the additional path length a

50、nd/ 2八refleeliou. so 典=; 1汽 + 穴.Forccmstiiiche iwerfeieuee.:4/the net phase chauite must be au evt-u non-zerti mtejei unUlipie of t.172八1限二内一我二W 2芯* 靠-0 = 2抑方> x =- y)4n tff 2,Hie nniiiiiiiitri tlikkutiiis is wnh 的 一 1.=4(450nmXl -1)= 113nmFor detinctive interferenceh the net phase change twist b

51、e an odd-inreaer multiple of tThe miniimiTTi Don'zero thickness is J = 4( 450nii )(l)= 225nni33:参见课件相应内容36:WeuseTlieequationderivedinProblem33,whereristlieradiigofthelens(J.7cm)tosolvefortheradiumofcmrti1urcSmcediecuteredgeGthe4-1*brightlius.vkhichwouldlialfvaybetweenthe44&and45*daftfirines.

52、westr?/=44.510,017m(44.5)(580*109m)WecalculatethefocalleagthoftheleusUsmgEq.33-4(thelensiuaker'sequation)withtheindexofrefiacrionofhicnetakenth理nTahitIfii1i-(J/-1)i=(11-1)+-0.0455m1f&网)(11.2in第三十章必做题:1,5,10,15,17,18,231:TheantorliefiisTniaiinuinisabcmrhalfwaybetweenrheanalestorhefirstandseco

53、ndniinima.Wcu(ieEq35-2tocakubtetheangulardistancetothefirsta】dsecondminimaThenweaveragethc$etohiitsto怆finingtheapproximatelocMionofthefiisTinxinium.Finally,usingtiigoiiciiielry.seitheluiemdistHiiceEqualIcthetLislaiicetotbeseieenunlitiplietlbythetciiigeiiloftheangle.-sm-1生人".2J.38x1 (Fin口二 sin12

54、j<58010 q m3 8x10 m= 17.7740«+四8.678fi+17.77468二一-13.23°v=n<ui61=(100UIItani13.23°)=2,25m5:GivenlightwithA=605mupa&siuthroughdoubleslilswitkseparatioud=0.120min.weuseEq.34-2atofindth<highestiutescitnvaluefortheinterfeiencefiiugethatoccursbefbietbenuck”900.0120x10如口90Mdsin

55、H_inAt"/-厂198605x0TgSo.inchidingtlh?球-0hinge.dudThesyumieiricpatiemufiiikifeieuceiiiugesoneachsideof0=0thereaiepoleutmllyaTotalof198+198+1=397Hinges.However,sincesliishavewidtha=0.040mm.thepotentialmterfereucefnnges(haccoincidewiththeslitsdiflractianminiinawillb。abicnr.Ltthedii¥raciionnimi

56、nibeindexedbyni-1.2.3.ere.11飞thenset山白diffractionanideginEq一34-2omidEq,37-2年qu虱tosolveforrliejuahiesofthe1absenltnnge$,wflmAui D 0 040 inmsinu-=DdUsingrtf-1,2,3,etc.,the66interferencefringesoneachsideof0=0withm=3,6.9,.198willbeabseniTLiuslliemiinbeiolInaye5ontlieseieeuis297-2(66f26?|.10:ATefindthesl

57、itseparationfromEq.35-1?.rhensetthenumberofLinespercentimeterequaltotheoftheslit$ep<u(ition,N=:d一*-,y151n闩sin15.0°7777;一dsmv=j/iA>Jv=7、=131X)Imes-cmdmA3(650x107cin)15:WeuseEq.35-20.with,=L14.0 口-,工(1)(0.13811111)77/x-Idsin°>协二sin=smId2(0.285niii)17:TheciiTicalangleexiMswhenligbtpassesfromatuAterutlwithahigdierindexofreiractiou(%intoaiiKiTenalwithaloweiindex

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