计算机组成原理题目库

1、第一章问题 1The computer has experienced 4 generations, which are ( ).A. Transistors, SMI, Laser device, Optical mediumB. Vacuum Tubes, Transistors, SSI/MSI circuit, Laser deviceC. Vacuum Tubes, Digital tube, SSI/MSI circuit, Laser deviceD. Vacuum Tubes, Transistors, SSI/MSI circuit, LSI/VLSI circuit 问题

2、2The components of CPU do not include ( ).A. Arithmetic unitB. memory C. register D. controller问题 3CPUcanprocess informationof externalmemorydirectly.A. 对B.错问题4MFLOPSis a performanceindex forexpressthe speed of processing thefloating point number.A. 对B.错问题 5Although computer science and technology h

3、ave changed tremendously both in hardware and in software, the basic model for computers has remained essentially the same, which was presented by ( ).A. EinsteinB. Von NeumannC. EdisonD. Newton问题 6In 8-bits micro-computer system, multiplication and division are realized by ( ).A. dedicated chipsB.

4、firmwareC. softwareD. hardware问题 7Software is equivalent to hardware in logic function.A. 对B.错问题 8Resources management of computer software and hardware is the duty of ( ).A. Operating SystemB. Language process programC. Database Management System D. Application program 问题 9The reason of binary repr

5、esentation for information in a computer is it can easily process the information.A.对B.错问题 10The basic feature of Von Neumann computer is ( ).A. access memory by address and execute instruction in sequenceB. access memory by contentC. Multiple Instruction Stream Single Data Stream (MISD)D. operate s

6、tack问题 11Data and instructions are stored in ( ) when the program is running.A. memory B. disk C. datapath D. operating system 问题 12The operating system is appeared in ( ).A. the 4th generation computersB. the 2nd generation computersC. the 3rd generation computersD. the 1st generation computers问题 1

7、3The so called“ PC belongs to ( ).A. Medium computers B. Mainframes C. Micro-computers D. Mini-computers 问题 14Computer hardware consists of calculator, memory, controller and I/O devices.A. 对B.错问题 15( ) is not belonged to system program.A. Database system B. Operating system C. Compiler program D. t

8、he above all 问题 16The vast majority of computer systems used today are constructed on ( ) computer model.A. intelligent 问题 17B. Von NeumannC. parallelD. real time processingThe use of (A. software 问题 18) signified the development of micro-computer. B. diskC. MicroprocessorD. OSThe use of microproces

9、sor signified the development of micro-computer.A.对B.错问题 19The reason why the binaryA. computing speed fastC. saving components 问题 20system of representation is widely adopted in computer is ( ).B. convenience for information processingD. the restriction of the nature of physical devicesA. host and

10、PeripheralB. calculator, memory and controllerC. host and programD. hardware and software system问题21Hostconsists of CPUandI/O devices.A. 对B.错问题22In acomputer basedonthe von Neumann model, instructions and data are allstoredin memory, andCPUdistinguish them according their address.A. 对B.错问题23A fullco

11、mputer shouldconsists of ( ).System software is purchased, and applied software is edit by ourselves.A.对B.错问题 24Which of the following languages can be implemented directly and edited by Mnemonic( 助记符 ): Assembly language; machine language; High-level language; Operating system primitives; Regular l

12、anguageA.， B.， C.， 问题 25In computer terminology， CPU consists of calculator and controller.A. 对B.错第二章 问题 1If X 2' s complement= 0.1101010， then X sign-magnitude = ( )A. 0.0010110 B. 1.0010110 C. 1.0010101 D. 0.1101010 问题 2( ) is used to represent address in computer.A. 1's complementB. unsig

13、ned numberC. 2's complementD. sign magnitude问题 3Numbers X1， X2 are integer， and 【X1】2's compl= 10011011 ， 【 X 2】 2's compl= 00011011， then their true value of decimal form are _-101 and _27。问题 4The sign- magnitude representation of0' is unique.A. 对 B.错 问题 5Plus two 2' s complemen

14、t numbers that adopt 1 sign bit， overflow must occur when ( ).A. carry signal is generated from the sign bitB. XOR operation for carry signal generated from the sign bit and carry signal generated from thehighest numerical bit is 0'C. XOR operation for carry signal generated from the sign bit an

15、d carry signal generated from thehighest numerical bit is 1'D. XOR operation for carry signal generated from the sign bit and carry signal generated from thehighest numerical bit is 1'问题 6The range of representation for a 1 ' s complement number system of 64 bits (including the sign bit)

16、 is ( ).A.0<|N|W263-1 B.OW|N|< 262-1 C. 0< |N|w 264-1 D.0<|N|w263问题 7Fixed point number can be classified into pure decimal( 纯小数 ) and pure integer( 纯整数 ).A.对 B.错 问题 8In fixed point calculator， whether adopted double sign bit or single sign bit， it must has ( )， which is often implemente

17、d by ( ).A. Decoding circuit， NAND gateB. encoding circuit， NOR gateC. overflow detection circuit， XOR gate D. shift circuit， AND-OR gate 问题 9Arithmetic shift 2' s complement of a positive， sign bit remains unchanged， and the blank bit fillsin 0' . Arithmetic slehfitft 2' s complement of

18、 a negative, sign bit remains unchanged, and the lowbit fills _ _0_. Arithmetic right shift 2 ' s complement of a negative, sign bit remains unchanged, and the high bit fills_ _1, and truncat low bit.问题 10Let the word length is 8, the fixed point integer with 2' csomplement representation of

19、 -1 is _11111111.问题 11In fixed point operation, it will be overflow when the result exceeds the represent range of the computer.A. 对B. 错问题 12For a 8-bit 2' scomplement representation integer number, its minimal value is_-128_, its maximal value is_ 127_.问题 13A fixed point number is composed of s

20、ign bit and numerical part.A. 对B. 错问题 14The range of representation for a 2' s complement number system of 16 bits (including the sign bit) is ( ).A. -2 15 + (2 15 -1) B. - (215 -) + (2 15 -) C. -215 + 215 D. - (2 15 +1) + 215问题 158-4-2-1 BCD code of a number is 0111 1000 1001 ， then its true va

21、lue is_ 789.问题 16The addition/subtraction algorithm for sign magnitude representation is rather simple.A.对 B.错问题 17 Which of the following numbers is odd parity?A. 010110011 B. 001000111 C. 110100111 D. 110100111问题 18The number represented in the computer sometimes will be overflow, the fundamental

22、reason is the limited computer word length.A.对 B.错问题 19For fixed point binary calculator, subtraction is implemented through ( ).A. 2's complement binary subtractorB. 2's complement binary adderC. sign magnitude decimal adderD. sign magnitude binary subtractor问题 20In 2 ' s complement add

23、ition/subtraction, using 2 sign bits for overflow detection, when the 2 sign bits1S2S' equals10', it means that ( ).A. result is positive, with no overflowB. result is negative, with no overflowC. result is overflowD. result is underflow问题 21The 2 ' s complement representation -o1f27 is

24、10000000.A.对 B.错问题 22The minimal number of the following numbers is .D. 62516s complem-e1n't r.epresentation ofA. 1001012B. 100010BCDC. 508问题 232' s complement representation of 0' equals to 1A. 对B. 错问题 24If X 2' s complemen=t 1.1101010，then X sign-magnitude = A. 1.0010101B. 1.001011

25、0 C. 0.0010110 D. 0.1101010问题 25For sign magnitude representation, 1' s complement representation, 2' s complement representation,_ sign magnitude representation and_ 1' s complement representation_has2 representations of . 0 ' 问题 26The use of 2' s complement operation is adopted

26、 to simplify the design of computer.A. 对B. 错问题 27Fixed point calculator is used for .A. fixed point operationB. floating point operationC. fixed point operation and floating point operationD. decimal addition问题 28When -1<x<0, x sign-magnitude = A. 1-xB. 2-2 -n-|x|C. 2+x D. x问题 29The maximal nu

27、mber of the following numbers is .A. 227 8B. 9616C. 10010101 2D. 143 5 问题 30 8-4-2-1 code is binary number.A. 对B. 错问题 31A decimal number is 137.5, then its octal form is _ 211.4, its hexadecimal form is_ 89.8_.问题 32For a 8-bit 1' scomplement representation integer number, its minimal value is_-1

28、27, itsmaximal value is_ _127_.问题 33The representation of 0' is unique.A. sign magnitude and 1' s complementB. 1' s complementC. 2' s complementD. sign magnitude 问题 34The range of representation for a unsigned binary number system of 16bits is_0_65535_.问题 35Given 【x1】 2's compl =

29、11001100， 【x2 】sign mag =1.0110, the decimal value of x1 and x2 are _-52_ and _-0.375_.第五章问题 1Calculator has many components, but data bus is the key part.A. 对B.错问题 2In an adder, the carry generate variable (G) of bit i ' is ( ).A. Xi® YiB. Xi Yi CiC. XiYiCiD. Xi Yi问题 3The carry look-ahead

30、circuit chip 74182 realizes the carry logic between groups in parallel.A. 对B. 错问题 4The subtraction algorithm of fixed point binary is realized by ( ).A. subtraction for sign magnitude representationB. addition for binary code decimalC. addition for 2' s complement representationD. subtraction fo

31、r 2's complement representation问题 5The main function of ALU is ( ).A. arithmetic operationB. only addition operationC. logic operationD. logic and arithmetic operation问题 6In a ripple-carry adder, the key factor affecting the speed of the adder is ( ).A. Gate-level delayB. speed of componentsC. v

32、arious speed of each full adder for bit iD. carry propagation delay 问题 7A calculator consists of many components, but the key component of calculator is ( ).A. arithmetic and logic unitB. data busC. accumulate registerD. multi-switch问题 8An arithmetic-logic unit is the heart of the CPU, and it belong

33、s to ( ).A. controllerB. registerC. sequential logical circuitD. combinational logic circuit 问题 9The commercial ALU chip 74181 is a 4-bit parallel adder with carry look-ahead circuit.A. 对 B.错问题 10ALU usually has a ripple-carry adder in order to improve the speed.A. 对 B. 错问题 11The commercial 4-bit AL

34、U chip 74181 can only perform 16 different arithmetic operations.A. 对 B. 错问题 124-bit Arithmetic Logic Unit 74181 can perform ( ).A. 16 possible logic operationsB. 16 different arithmetic operationsC. 4-bit multiplication/division operationsD. 16 different arithmetic operations or 16 possible logic o

35、perations 问题 13ALU belongs to ( ).A. calculator unitB. control unitC. memoryD. register 问题 14Using four 74181ALU chips and one 74182CLA chip can achieve the following carry propagation circuit: ( ).A. carry look-ahead of all 16 bitsB. ripple carry inside each 4-bit group and carry look-ahead across

36、different groupsC. ripple-carry circuitD. carry look-ahead inside each 4-bit group and ripple carry across different groups斥民 、:第六章问题 1Exponent unit in floating point calculator can realize addition, subtraction, multiplication and division operations.A.对B.错问题 2In addition/subtraction operation on t

37、wo floating requires exponent equalization before arithmetic shift_ Mx ; if Ex=Ey, no shift.问题 3The mantissa of floating point number uses 2 mantissa before normalization is 1.10101. It needs 问题 4point numbers, x = Mx -2Ex and y = My-2Ey, itoperation. If Ex>Ey, shift_My_; if Ex<Ey,'s compl

38、ement representation, the binary code of the _ left_ normalization, and it should shift_ 1_bit.( ) representation is used in mantissa of floating point number.A. biased code or excess-2q codeB. sign magnitudeC. 2' s complementD. 1' s copmlement问题 5In the representation of floating point numb

39、ers, () is implicit( 隐含 )A. exponentB. the radix of the number system to represent the mantissaC. mantissa D. sign bit 问题 6) representation.For a IEEE 754 standard Floating-Point number, its mantissa uses (A. biased code or excess-2q codeB. 1' s complementC. sign magnitudeD. 2' s complement问

40、题 7Which of the followings is correct:A. Exponent unit can realize addition, subtraction, multiplication and division operations.B. Mantissa unit only realize multiplication and subtraction operations.C. Exponent unit only realize addition and subtraction for exponent.D. Floating point calculator ca

41、n be implemented by exponent and mantissa units. 问题 8The maximal positive number in IEEE754 standard for 32-bits format isA. + ( 2 - 2-23)x 2+255B. + (2 -2-23)x 2+127D. 2+127 + 227C. + (1 _2-23)X 2+127问题 9Exponent unit in floating point calculator can realize operations of addition, subtraction and

42、compare.A.对B.错问题 10Which is normalized Floating-Point number, if its mantissa is represented by 2'scomplementformat?A. 0.01110 B. 1.00010C. 0.01010D. 1.11000问题 11In IEEE 754 standard, a floating point number is composed of sign bit s, exponent e, and mantissa m.A.对B.错问题 12The sign bit the number

43、 for_ 1' of a biased code number represents the num非负数 _, while 0' represents_ 负数 _.问题 13In IEEE754 standard floating point, mantissa is coded as_ 原码 _, exponent is coded as_移码. 问题14In IEEE 754 sta ndard, the value of exp onent is represe nted in excess-128 code.A. 对B.错问题15In a algorithm for

44、 normalized float-point number, a number is 25x 1.10101, with 2 ' s complementreprese ntati on for man tissa. Then it ().A. needs left shift 2 bits of mantissa for normalizedB. needs left shift 1 bit of mantissa forno rmalized.C. n eeds no no rmalizedD.n eeds right no rmalized问题16The exponent, E

45、, of a floating point number usually uses biased code representation, which is more convenient for compari ng size or exp onent equalizatio n.A.对B.错问题17The mantissa of a Floating- Point number is represented by 2' complement, then whether theFloati ng-Po int nu mber is no rmalized is decided by

46、().A. mantissa ' s sign bit and the first bit ofantissa ' s numerical part are identicalB. the sig n bit of exp onent and man tissa are ide nticalC. mantissa ' s sign bit and the first bit of mantissa' s numerical part are differentD. the sig n bit of exp onent and man tissa are diff

47、ere nt 问题18In the represe ntatio n of float ing point nu mbers,基数 is implicit and in visible to thecomputer hardware.问题19The purpose of using no rmalized floati ng point nu mber is ().A. to expa nd the range of data represe ntati onB.to avoid for overflowC. convenient for floati ng point operati on

48、D. to en sure maximum accuracy of represe ntatio n 问题20()represe ntati on is used in exp onent of Float in g-Po int nu mber.A. biased code or excess-2q codeB. 1' s complementC. sign magnitudeD. 2' s complement第七章问题1In direct address ing mode is desig ned to facilitate the access of data arra

49、ys.A. 对B.错问题2In structio n set is a key factor to represe nt the performa nee of a computer.A. 对B.错问题3Register-Register (RR)address ingmode is slowertha nRegister-Storage(RS) address ing mode.A.对B.错问题4The function of programcontrolinstructions is ().A. to perform arithmetic and logic operati onsB. t

50、o move data between I/O and CPUC. to move data betwee n memory and CPUD. to cha nge the program execut ing order问题5Accord ing to storage positi on of opera nd, the in struct ion set usually supports SS address ingmode.A.对B.错问题6An in structi onword con sists of Opcode and addresses part.A.对B.错问题7Form

51、at and function of in struct ion set only affect the hard structure of a computer.A.对B.错问题8In registerin directaddress ing mode, the opera nd is in ().A. PCB. stackC. memoryD. gen eral register问题9Theopera ndis in a register, thisaddress ingmode is called ()A. register direct addressing modeB. direct

52、 addressing modeC. indirect addressing modeD. register indirect addressing mode问题10Theaddress part in aprogram control instruction represents the addressofnextinstruction thatneeds transfer.A.对B.错问题 11In the instruction addressing modes the fastest way to get the operand is ( ).A. register addressin

53、g modeB. direct addressing modeC. indirect addressing modeD. immediate addressing mode 问题 12In order to implement one-address instruction, one instruction, another operandpart ofarithmetic operation between two operands for operand is indicated by addresses is specified by ( ).A. immediate addressin

54、g modeB. implied addressing modeC. stack addressing modeD. indirect addressing mode问题 13By using different addressing mode, the instruction set can ( ).A. reduce the instruction length, expand addressing space, improve programming flexibilityB. realize program store and program controlC. access exte

55、rnal storage directlyD. extend OPcode and decrease the trouble of instruction decoding. 问题 14For the number of instructions, addressing mode and instruction kinds, RISC is less than CISC.A.对B.错问题 15There are two in struct ionaddress ingmodes, one is seque ntial, and theother is jump. Jumpaddress ing

56、mode can perform ().A. con diti onal branch of programB. con diti onal or uncon diti onal branch of programC. uncon diti onal branch of programD. stack address ing问题16The purpose of using extending Opcode ininstructionformat is ()A. to keep the len gth of in structi ons, while in crease the address ing spaceB. to in crease the len gth of in struct ionsC. to keep the len gth of in struct ions, while in crease the kinds of in structi on operateD. to reduce the len gth of in struc