2020-2021学年山东省菏泽市牡丹区八年级(下)期末数学试卷

学年山省菏泽市丹区八年（下）期数学试卷一选题共8小，每题分共24分）A

B

C

D

A6x2

y22

33

B2y+1+1Cmambm+b

D1aabA22

B

C2a2Dam2

+m

xy3A3C

B6Dy+30x0A2BxxBDABCD

ABCDABCDABCDABC90B30ACMNMNPAPBCDAADBACBADC60CDD

DAC

1ABCDBDODEADCE60ADOE①

AD②DB③DE④BDA1

B2

C3

D二填题本题个题每题3分共分只求最结填在题的应域）P52

104511xm12a+1aa+a+113CFAEFABDF14ABCBCAGEAAG1/s3cmst

sACEF三解（大共8个题，共分请把答证过写在题的应域）151a22+2x+2+2216

17

+

18

a+1a12

11111112221219ABCxOyA211eq\o\ac(△,A)eq\o\ac(△,)BC2eq\o\ac(△,A)eq\o\ac(△,)BCeq\o\ac(△,A)eq\o\ac(△,)3ABeq\o\ac(△,A)eq\o\ac(△,)B20AB7200A21A2B1800B21BC1PACB110BACPPHABHAHAC

22ABCDDDFACABFDEACE1DBC①+DF2DBC②DEDF3D③DEDFAC

参考答案一选题本题8个小，小分，共24分，每题出的个项，个项正的请正选的号在题的应置）A

B

C

D

ABCDCA6x2

y22

33

B2y+1+1Cmambm+b

D1aABCDC

abA22B

C2a2Dam2

+mb2BabCb12a2Da2

+m

+m2

D

xy3A3C

B6DD

y+30x0A2Bxxx2yx0x

DBDABCDABCDBDAOBODOAOBODOABC90B30ACMNMNPAPBCDAADBACBADC60CDD

DAC

160BAD30BBDADB

ABCABCDABCABCDABCDC302CDBD2CDCDDBACAC90BAC30909060BBADDADBDABCeq\o\ac(△,Rt)ACD30ADBDADBDCDDDABCDBDODEADCE60ADOE①

AD②DB③DE④BDA1

B2

C3

DADEADAEADB90ADBDS

BD60BDE30DBCDEeq\o\ac(△,Rt)AODAOADAODEOEAD

ABCD111ABCD111BADBCD60ADC120DEADEDAEADABDEBDEAEDADB90ADBD

①60BDE30BDECDE②eq\o\ac(△,Rt)AODAOADAODE③BDOEABDOEADADB90EOBEODBOE④C二填题本题个题每题3分共分只求最结填在题的应域）P528P2P424P7

871045458211x

14m3mmx1xmm+4+41m3m312a+1aa+a+1aa[1+a+aa+12++2020

]a+1

[1+a+2aa+1]a+1

[1+a+2aa+1]a+12022a2022

13CFAEFABDF

2.5

CFABCGACAGCFABGGAFCAFAGDBCDFDFBGAG2.514ABCBCAGEAAG1/s3cmst

4sCEFCFCFACEFCBFCFBF83AGAECF

ttFCAE3CFBFBCtcmAGAECFt3tt2sACF三解（大共8个题，共分请把答证过写在题的应域）151a22+2x+2+22a2aa22a1

2x+++22+y23x+33+16

x

xx317

+

+1xx+2x+111+2+2x1x1x1x118

a+1a12aaaa

11112211112221211122221122231419ABCxOyA211eq\o\ac(△,A)eq\o\ac(△,)BC2eq\o\ac(△,A)eq\o\ac(△,)BCeq\o\ac(△,A)eq\o\ac(△,)3ABeq\o\ac(△,A)eq\o\ac(△,)BACAB2eq\o\ac(△,A)eq\o\ac(△,)C3eq\o\ac(△,A)eq\o\ac(△,)B1eq\o\ac(△,A)eq\o\ac(△,)C2eq\o\ac(△,A)eq\o\ac(△,)3eq\o\ac(△,A)eq\o\ac(△,)B3

20AB

7200A21A2B1800Bx+0.772005000B2x2BmA1x+0.7

2xx1.8xA260001.86000m2.5m1800mB21BC

1PACB110BACPPHABHAHACPBC的PCBPPACPBCPAC+PCAACBHeq\o\ac(△,Rt)PBHeq\o\ac(△,Rt)1PBCPCBPACPCAPBC++360PBC+PAC2ABAHABPDACH

PHABPDACPHPDAPAHADeq\o\ac(△,Rt)PBHeq\o\ac(△,Rt)eq\o\ac(△,Rt)eq\o\ac(△,Rt)BHAHAC+AD22ABCDDDFACABFDEACE1DBC①+DF2②DEACDF