课件1第4章4习题1下面代码是否正确如果运行后输出什么否则解释出现错误的原

classMystery2String3publicstaticvoidmain(String[]args)4Mysterym=new 5}6voidMystery() s= 7voidgo() 8}publicclassTestintpublicstaticvoidmain(String[]for(inti=0;i<3; publicclassTestpublicstaticvoidmain(Stringargs[]) a=new b=newSystem.out.println("ais"+a.v+";bis"+ staticvoidswap a,MyClassb) t=a; 12 v this.v= 16class{voidmyMethod(inti){System.out.println("intvoidmyMethod(Strings){System.out.println("Stringpublicstaticvoidmain(String{MyClassobj=newintch= classpublicstaticvoidmain(Stringargs[]) a=new private publicstaticvoidmain(String[] publicstaticvoidmodify()inti,j,i=j=i*System.out.println("Thevalueofjis"+jk=k+} class privateintprivateintpublicMyClass(){x=1;y=publicMyClass(intx,inty) publicvoidshow(booleanflag)if System.out.println("x="+x+"y="+ System.out.println("y="+y+"x="+ publicstaticvoidmain(StringMyClassmyobj=new 1.publicclass publicintaMethod()staticinti=return publicstaticvoidmain(Stringargs[])Testtest=newintj= privateDemovoidstart()d=new voidtakeDemo(Demodemo) publicstaticvoidmain(String[]Testt=new classint publicclassstaticintpublicstaticvoidmain(StringintPassp=new publicvoidamethod(int} publicclassAvoidA() publicstaticvoidmain(String[]args)new publicclassXintpublicstaticvoidmain(String[]args) publicstaticvoidmodify(inta) publicclassTestpublicstaticvoidmain(Stringargs[]) a=newintSystem.out.println("ais"+a.v+";bis"+ staticvoidadd a, b) v this.v= publicclassMyClassintintvoidintSystem.out.println(“xis”+xSystem.out.println(“yis”+y publicstaticvoidmain(String[]args)MyClassmy=newSystem.out.println(“xis”+my.x packagepublicclassTest1staticintx= packageimportpublicclassTest2publicstaticvoidmain(String[]args)System.out.println("x="+ publicclassTeststaticintvoidfor(inti=0;i<3; publicstaticvoidmain(String[] t1=new publicclassMyClassintintvoidintSystem.out.println(“xis”+xSystem.out.println(“yis”+y publicstaticvoidmain(String[]args)MyClassmy=newSystem.out.println(“xis”+my.x （double类型方法中创建一个品牌为“benz2、定义一个类Book，要求如下name（String类型author（String类型（d