教程案例igcse数学

InternationalGeneralofSecondaryMARKSCHEMEfortheMay/June2012questionpaperfortheguidanceofteachers05800580Paper3umrawmarkThismarkschemeispublishedasanaidtoteachersandcandidates,toindicatetherequirementsoftheexamination.ItshowsthebasisonwhichExaminerswereinstructedtoawardmarks.ItdoesnotindicatethedetailsofthediscussionsthattookceatanExaminers’meetingbeforemarkingbegan,whichwouldhaveconsideredtheacceptabilityofalternativeanswers.Markschemesmustbereadinconjunctionwiththequestionpapersandthereportonthe CambridgeispublishingthemarkschemesfortheMay/June2012questionpapersformostIGCSE,GCEAdvancedLevelandAdvancedSubsidiaryLevelsyllabusesandsomeOrdinaryLevelsyllabuses. correctsolution followthroughaftererror ignoresubsequentworking orequivalent withoutwrongworking seenorimpliedPart12M1for2000÷(19+72M1for265seenoee.g.addingup37s3M1for54M1indepfor80 M2for100×200orM1for1004M1for(500×1.04)×(1.04)A1forM1depfor‘their540.8’–B1ftfor‘their40.8’roundedtoAltM1for[500+(500×0.04)]M1dep‘their20’+‘their20.8’A1for40.8B1ftfor‘their40.8’roundedto2(a)Imageat(–5,2),(–2,2),2B1correctreflectioninx=k,k≠(–3,4),(–3,3),SC1fortotallycorrectreflectioninx(Imageat(2,4),(2,6),(–1,6),2SC1for180°rotationnotabout(1,5),(Imageat(1,1),(3,1),(3,2SC1forcorrectsizeand(7,–1),(7,–3),(1,(b)Reflection,y=0orx1ft,Fttheir(41ft,Strict8Allow4rightand83(a)661(2,2,2),4,4,4,4,5,5,7,7,9seen3Felix’sprobability which lessthanJon’sprobability 64which 30°anglecorrect72°,48°41Accept0.167or16.7%or(1Accept1or0.333or33.3%or3(1Accept“one”or3B1for4,4,4,4B1for5,5AND7,7B1forONE91(d)3M1for360×fforone‘Number’A1for1correctIfzeroscoredSC1fortheirtwoanswers(1(13M12×15+4×20+5×5+7×12+9(allow1M1depfortheir4Ifxismorethan11then11–1wouldbenegative14+4x2M1for2x+3+11–x+accept2(2x+(c)4.53B1ftfor“their(b)”=M1ftforcollectingtheirliketermscorrectlygivesimplifiedexpressionofformax=bORM1ftx=(M1ftforclearattemptatsubstitutingtheirinto2ormoresidesof5(c)((Correctdiagram:4rows&6n+2n(n+2)oe11111Ft‘their(c)(i)’×nif(c)(i)Ftsubstitutionof20into‘their(c)(622M1for(changeiny)withtheirvalueschangeinxB1for(y=)–0.5x+korjx+6(j≠0)M1for3:12SC1forfinalanswerof4:1or–1:4orB1for‘6’and‘15’or‘6.5–6.9’andM1for0.5×6×15or0.5ד6.7”Fttheirpoint–0.5x+2212ratio3(g)Dcorrectlymarkedon1((9,7(a)1E.g.Theyarebothhalfwaybetweencaféand M1for3kmin10minsoeseen 3or6SC1for(10.30,3)to(10.50,5)onitsB1CorrecttimeseenfromtheirdiagramM1ft( )×60oe'their(TonipassesPoppy1(2(b)Straightline(10.30,3)to(10.50,1Straightline(10.50,3)to(11.10,1(Straightline(10.50,3)1(10.55,Straightline(10.55,1.5)1(11.15,(7.238(a)1Ftis'theirM1ft'their(a)()'(=32.5)M1ft34–'their(a)()'(34–4 M1‘tan’= or‘sin’=theiror‘cos’=their130180–‘their(d)(i)’M1‘50’ב120’figsseeninareacalculationA1for6000seen(impliedby0.006later)1000,6×10oeB1ftfrom‘their0.006’providedSFpoweris2SC1for0.6×10(25Saidby1.5(d)2(3649(a)226to226.2243M1πB1forunits:B11500M1ft3×their4M1ft3their4M1M2for2×4×5+2×4×6+2×5SC1for2×4×5oeor4×5+4×6+5impliedby40,48,60or74,orlistof20,20,24,30,Ft(d)(i)Ft(d)()(8cao45.09(5.092to21483(d)mv1(msv(1000msv20125/605800580/313（核心）IGCSE、GCE2012月/62IGCSE20125/60580caocsodepftiswoeSCwwwsoiQu(a)9502M12000(19+7cao2265M1oe37s663M154M1indep803367M2200M1200100100414M1(5001.04)1.04)oeA1540.8M1dep540.8”B140.8”41AltM1500(500×0.040.04M1dep'他们的20'+'他们的20.8'A1为40.8B1英尺，为'他们的40.8'四舍五入为41(a)i5,2)、(–2,2)、(–2,4)、(–3,4)、(–3,3)、(–5,3)2B1xk,k≠0上正确反射SC1在x轴上完全正确反射)(2,4)、(2,6)、(–1,6)、(1,5),(1,4)2SC1180° (1,1)、(3,1)、(31)、(7,1)、(73)、(1,3)2SC1b)(i)，y0x1，1Ft 4811483分方案：教师版IGCSE教学大纲试卷–2012年5月/6月0580313(a)(i)1oe61接受0.167或16.7%或更好)2oe611接受或0.333或33.3%更好 11(2,2,24,4,4,4,5,5,7,7,93B14,4,4,4B15,57,7B1ONE93Felix122Jon(of64121d)(i)120°,3072°,48°3360M1forf160A11案如果零分SC1代表两个答案总计120°30°72°、48°1英尺i)44.853M12154205×571298（1个错误）dep4(a)x1111xoeb)144xcao2(2x7)2M12x311x3xc(i)4.5cao3B1ft示“他们的(b)”=32M1ft用于正确收集它们的类似项给出ax=bbORM1ftx=a)6.52ftM1ftc)(i)24案：教师版IGCSE教学大纲试卷–2012年5月/6月0580315(a)：4635(i)n2n(n+2)oe1ftFt‘他们的(c)(i)’×nif(c)(i)线 i)4401ftFt20替换为‘他们的(c)(6(a)2cao2yM1xb)–0.5x62B1=)–0.5xkjx6(j1:42M1for3:12SC14:11:425°–29°（对应）oe（对应）oe453B1‘6’和‘15’或‘6.5–6.9’和‘13.2–13.6’M10.56150.5ד6.7”×(i)D1(9,6)D17(a)10 18231.5M1103oe10531(i)(10.303)(10.50,3)1SC1(10.30,3)(10.50,5)(10.503)(11.105)(10.50,3)10.55,1.5)(10.55,1.5)(11.150) 7.2cao3B13M1ft60oe5IGCSE20125/605808(a)1701302M1502+51ft(a)(i)'Ft用1.5秒3ft表示'他们的(a)()'M1ft(=32.5)4'他们的(a)()'M1ft34–32.5)4d)(i67.4°2120120M1tan’=‘sin’=5013050他们 113°112.6°1ft180–36×104M1'50'×'120'在面积计算A1中看到的数字为6000可见（稍后隐含为0.006）M110002、0.050.12–6×10oeB