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Chapter
2材料科学基础(II)Interfaces
in
materials-IIBrief
introduction
of
method
based
onmatrix
and
vector
calculations材料科学基础(II)Dislocation
model
for
semicoherent
interfacesD
b/
for
simple
small
angle
grain
boundariesD
=
b
/
for
Interfaces
with
1D
or
isotropic
misfitHow
to
determine
D
for
a
general
small
angle
grainboundary,
and
for
an
interface
with
anisotropic
misfit?Relations
of
two
lattices:
Rotation:
a
=
Ra
,General:
a
=
Aa
2.
O-lattice
model
for
general
interfaces普适计算工具,知道思路和基本概念即可材料科学基础(II)Definition
of
the
principal
O-lattice
vectorsFrom
张敏SRT
workProgramcan
befoundfrommywebpageO-element:
position
of
best
matching(zero
misfit)Principal
O-latticevectorO-cell
wall:
Positionsof
worst
matchingBollmann,
1970L
+
L
=O-latticeL
=
bcc
{1
1
0}L
=
fcc
{1
1
1}Programs
fromAnisotropic
misfit
in
general
systems
in
3D材料科学基础(II)材料科学基础(II)材料科学基础(II)The
intersections
of
the
O-cell
walls
with
an
interface
arepossible
position
of
misfit
dislocationsSquare
dislocation
network
ofscrew
dislocations
in
a
twist
grainboundary
in
SiDB
Williams
and
CB
Carter1996材料科学基础(II)Dislocations
in
small
anglegrain
boundaries
in
metalsand
in
Al-Al2O3
interfacesNbAl-Al2O3Pt材料科学基础(II)(by
Yang
Xiao-peng,
programavailable
in
my
homepage)Consistence
of
geometryof
O-cell
walls
with
misfitdislocations
in
a
1D
misfitsystemisotropic
dilation2D
O-lattice,
formed
by overlapping
rigidlattices
of
different
lattice
constants材料科学基础(II)Step
1:
Build
a
quantitativeRelationship
between
2
latticesx
=
Ax
x
,
x
:
vectors
in
lattice
and
A:
transformation
matrix,
misfit
distortion
matrixA
=
cos
sin
–
sin
cos
r1
//
x
axisr1
=
[r,
0],
([]
=
column
vector)r2
=
[rcos
,
rsin
]Matrix
calculation
of
O-latticeDetermination
of
misfit
displacement
x
=
x
–
x
=
(I
–
A-1)x
=
Tx
Step
3:
Find
misfit
displacement
associated
with
x
x
m
=
x
x
nwhere
x
n
is
the
nearest
neighbor
from
x
x
can
be
translated
to
x
by
n
x
=
x
+
∑b
n
iL∴
x
m
=
x
x
n
=
x
(x
+
∑b
iL)=
x
∑b
iLiIn
condition of
|
x
m|
<
|
x
m
–
b
L|x
x
n
x
mbax
Step
4:
Find
x
without
misfit
x
m=0
x
=
Tx
=∑b
iLDefinition
of
O-lattice
elements!!Step
2:
Calculate
relative
displacement
at
x
:x
=
Ax
T
=
I
–
A-1Configuration
of
periodic
dislocationsDefine
distribution
of
O-elements
(GMZ)
with
xOTxi
=
b
iO
LGiven
an
interface
normal
to
n
(unit
vector), containing
periodic
dislocations
with
Burgersvector
b
i
(related
to
b
i
)L
LDefineReciprocal
vector
for
O-cell
walls:
ciO
=
T
b
i*Dislocation
direction:Dislocation
spacing:D
=
1/|
i|Special
systems:
ci
=
bi*
=
b
i*
b
i*OBollmann’s
equation,
70
i
=
n
ciObi*
=
biL/|biL|2
=
reciprocal
Burgers
vectorSpecial
boundaries,
i
=
n
bi*,
n
bi*Rotation:
(|bαL|
=
|bβ
|
=
b)LβD
=
1/|
bi*|
=
b2/(bαL
–
b
L)
=
b/2sin(
/2)
b/
α
βIsotropic
deformation:
(b
L
//
b
L, |bL|
=
bL)D
=
1/|
bi*|
=
1/(1/bαL
–
1/bβ
)
=
bβ
/
L
Lbβ*
b*b
*
=
(bβL
–
bαL)/bαL
bbβLb
LZhang,APL2005D
=
1/|
b*|
=
1/|b
i*
b
i*|bi*=
b
L/|b
L|2i
iCosine
law:
D
=
bαLbβ
/[(bα
) +
(bβ
) –
2bα
bβ
cos(
)]L L
2 L
2
L
L
1/2Unified
expressions
for
formulas
in
textbooksRec.
vector
for
O-cell
wallsTest
of
the
formula
with
simple
casesO-lattice
model
for
general
interfacesO-element:
position
of
best
matching
(zero
misfit)O-cell
wall:
positions
of
worst
matchingFormulas
for
dislocation
geometry
(Unified
expression)3.
Models
for
other
singular
and
vicinal
interfaces(Up
dated
knowledge,
not
in
the
text
book)CSL/DSC
model
(for
large
lattice
misfit
&
Low
Calculation
ModelsEvidence
of
secondary
preferred
state
and
secondarydislocationsObservation
of
secondary
dislocationsVariation
of
dislocation
spacing and
energy
with
3.
Models
for
other
singular
and
vicinal
interfaces1)
CSL/DSC
model
(for
large
lattice
misfit)CSL:Coincidence
Site
Lattice(重合点阵)Variation
of
energy
with
misorientationFig.
7-14
on
P419材料科学基础(II)Key
parameter1/
=
density
of CSL
points
is
an
odd
number
for
cubic
systemsvolume
of CSL
unit
cellvolume
of crystal
lattice
unit
cell
Dense
CSL
points
maybe
favored
by
nature材料科学基础(II)材料科学基础(II)for
n
=
1,
m
=3S
=
(1+
9)
=10area
of
a
unit
CSL
cell
=
(m2
+
n2
)/2kn
=
1,
m
=
3,
=5
=
2tg-1(n/m)
=
2tg-1(1/3)
=
36.87
(3,1)(1,-3)(3,-1)(-1,-3)
5CSLDerivation
of
(forcubic
crystals)area
of
a
CSL
cell面积=斜边长2
=m2+n2Generating
expressionsThen,
for
cubic
systemFor
other
systems
one
need
to
modify
the
derivationE.g.
{hkl},
<uvw>
may
not
be
equivalent
vectors
(of
samelength)材料科学基础(II)Ranganathan
formula(for
cubic
crystals)The
area
of
square
unit
CSL
cell
=
m2
+
n2Generating
function
for
of
a
square
latticeRotation
axis
is
a
rational
vector
of
(h,
k,
l)plane
normalA
∑3
<111>twin
boundaryWhen
two
grainsshare
a
plane,the
plane
is
twinboundary
A
orsimilarly
C,BRotation
of
,
/3
around
as
axis
<111>
passing
a
lattice
point
in
plane
ABCBCCBProduced
by
shearProduced
by
rotationof
atoms
from
A
layerC
B
CBWhy
is∑3?材料科学基础(II)Possible
low
energyinterface
location:topassdense
CSL
pointsStepped
boundary
alongthe
plane
containingdense
CSL
points
11
<110>
CSL
boundary
forunderstanding
Fig
7-2
in
p41350.5
二次位错的台阶结构纯台阶DSCL柏氏矢量位移Dense
CSL
points
are
presenton
planes
of
particular
locationsCSL
pattern
tends
to
bereserved
locallySmall
deviations
will
lead
to
theloss
of
the
coincidenceTranslations
of
DSCL
vectorpreserves
the
patternDSCL:
Displacement
Complete
Pattern
Shift
LatticeSteps
associatedwithsecondarydislocationsDeviation
from
CSL
OR
withsecondary dislocation
modelBrandon
Criterion
max
-1/2
小角度晶界的上限~
AP
Sutton,
RW
Balluffi,
Interfaces
in
Crystalline
Materials,1995Preferred
state:Reference,
deviation
from
which
defines
misfitIn
good
matching
zone
(GMZ)
between
the
dislocationsPrimary
GMZSecondary
GMZBurgers
vector
=
vector
in
the
DSCLBurgers
vector
=
translationvector
in
crystal
latticesPrimary
dislocations
vssecondary
dislocationsGenerating
expressionsThen,
for
cubic
systemFor
other
systems
one
need
to
modify
the
derivationE.g.
{hkl},
<uvw>
may
not
be
equivalent
vectors
(of
samelength)Ranganathan
formula材料科学基础(II)(for
cubic
crystals)The
area
of
square
unit
CSL
cell
=
m2
+
n2Generating
function
for
of
a
square
latticeRotation
axis
is
a
rational
vector
of
(h,
k,
l)plane
normalPrimary
O-lattice
andprimary
dislocationsSecondary
O-lattice
andsecondary
dislocationsPrimary
O-lattice
vs
secondary
O-lattice材料科学基础(II)Dislocation
model
for
semicoherent
interfacesO-lattice
model
for
general
interfacesO-element/O-cell
wallFormulas
for
dislocation
geometryUnified
expression
of
D
for
simple
boundariesModels
for
other
singular
and
vicinal
interfacesCSL/DSC
model
(for
large
lattice
misfit
&
Low
formulas
for
cubit
crystals<uvw>may
not
be
equivalent
vectors
(of
same
length)Structure
unit
model
(atomic
calculation)Secondary
dislocations材料科学基础(II)Arial
13§3.
Structure
of
interfaces
and
geometrical
models§3.
Structure
of
interfaces
and
geometrical
modelsCSL(重位点阵):定量描述重位点的模型,用于计算可能的重位共格结构,该结构可以由少量几种结构单元重复构成
=CSL点密度:晶体位向关系(取向差)的函数,与界面取向无关半共格界面:界面上存在位错,位错之间是共格区(成片的共格点)重位共格结构:界面上存在间距很小的离散共格的点,可能存在二次位错,之间是周期性分布的重位共格(CSL)区DSCL(位移点阵):二次位错的柏氏矢量来自该点阵
O点阵:零错配位置的点阵,是计算好区/错配区分布及界面位错的普适工具,可以计算一次(一般柏氏矢量)或二次位错倒易矢量:代表正空间一组面,长度=1/面间距,方向=面法向,倒易点:倒易矢量定义的点,周期分布的倒易点=倒易点阵,倒易点所在空间=倒易空间材料科学基础(II)材料科学基础(II)CSL
may
not
represent
thetrue
atomic
structureunrelaxed,translatedRelaxed,
tends
to
maximize
distancebetween
black
and
white
atoms,different
(higher)
symmetry
formsRelaxation
from
CSL
structureABBABBAABABAABABFCC点阵以[001]轴旋转的对称倾转晶界的结构单元模型
5的CSL,黑点为重位点,虚线平行于面(210)
5晶界的松弛结构,晶界由B单元组成
17晶界的松弛结构,晶界由A和B单元以ABB顺序重复排列,平行于面(530)
37晶界的松弛结构,晶界由AABAB顺序重复排列,晶界面是(750)(e材)
1料(完科整晶学体)基的情础况,(平I行I于)(110)面构成的结构单元,以A表示余永宁,2000Structural
unit
model材料科学基础(II)Early
structural
unit
model以不同边长比(n:1)的镜面菱形构成界面的结构单元的材料科学基础(II)Variation
of
ratio
of
units
with
misorientationSutton
and
Vitek
11:
B
units
27:
A
unitsfcc:
r=
[110]材料科学基础(II)Structures
of
Interfaces
between
Cm
and
AHowe
and
Spanos,Phil.
Mag.,
1999Zhang
et
al.
Acta
mater.,2000Ye
and
Zhang,
Acta
mater.,
2002Small
DSCL
vectors
for
Burgersvectors
do
not
lie
in
the
planecontaining
dense
CSL
points闫佳易,2009基础(II)材料科学
g1
=
g(02-2)
g(062)s
g2
=
g(020)
g(002)sApplication
to
S
phase
(Al2CuMg)in
Al-Cu-Mg
alloys
(Rule
III)Radmilovic
et
al.
(1999)Reported
OR
(Type
II)
:[100]s//[100]
(0-21)s~//(014)
Reported
facet(0
4
3)s//(0
2
1)
Gu
and
Zhang,
2007Interfacial
structure
development
tendency材料科学基础(II)To
form
low
energy
structure,
by
establishing
lowenergy
bondsToform
coherentregions
asfar
aspossible
for
metallicsystems
(primary
preferred
state)To
form
low
energy
structural
units
(regularly
coherent)
ifthe
coherentmisfit
strainis
too
large
for
fullycoherent(secondarypreferred
state)Toform
amorphousif
high
energy
bonds
have
to
form,
e.g.
O-O
in
ceramicsIf
misfit
strain
is
too
large
fora
fullycoherent
(orstrictly
regularly
coherent)
one
to
form,misfitdislocations
will
present
in
a
semicoherent
(semi-regularly
coherent)
one§4.
Interfacial
energyPhysical
basisDislocation
modelNearest-neighbor
broken-bond
modelVariation
of
Us
with
interface
orientationSpecific
interfacial
free
energySurface
tension
(F/L)
and
surface
stress
tensor§5.
Equilibrium
boundary
segregation§6.
Equilibrium
shape
of
crystals,
grains
and
particlesThe
Wulff
plot
and
Wulff
ConstructionLocal
equilibrium
of
facetsForce
balance
of
surface
tensionParticles
at
grain
boundariesEmbedded
particles材料科学基础(II)§4.
Interfacial
energy
(
)材料科学基础(II)Physical
basisRise
of
energy
due
to
broken,
distorted,
and/or high
energy
bondsPossible
rearrangement
of
atoms
in
structure
and compositionsApplicationsMany
phenomena(wetting,
segregation,
absorption,
nucleation
insolidification
and
precipitation,
coarsening,
graingrowth,
microstructure
development,
catalysis)and
material
properties(embrittlement,
intergranular
fracture,
grain
slidingin
creep,
and
microstructure-related
properties)材料科学基础(II)§4.
Interfacial
energy
(
)2.
Dislocation
modelp419
Fig
7-14,
p301
eq
4-107,
p418
eq
7-10typicalMainly
for
low-angle
grain
boundaries,misorientation
angle
value
in
cubic
materials
is
15°.Read-Shockley
model:For
an
array
of
dislocations,
the
long-rangestress
field
depends
on
the
spacing.
Giventhe
dislocation
density
and
the
dislocationcore
energy,the
energy
of
thedislocation
wall
can
be
estimated
bysummation
of
the
dislocation
energy0.40.350.30.250.20.150.10.05003010
20Misorientation
Angle(degrees)Relative
Boundary
EnergyYang,
C.-C.,
A.
D.
Rollett,
et
al.(2001).
“Measuring
relative
grainboundary
energies
and
mobilities
in
an
aluminum
foil
fromtriple
junction
geometry.”
Scripta
Materiala:.(II)材料科学基础§4.
Interfacial
energy
(
)Energy
of
a
single
dislocation:0cGb2
RE
ln( )
E4
(1
)
rGb2
D
E
ln( )
c
0
(
A0
ln
)4
D(1
)
b
D0
Gb4
(1
)0cGb2E
4
(1
)A
D
bdislocation
number
=1/Dlength
=
1R
=
D/2or =
b/2Energy
of
dislocation
array
in
unit
area.:
Read-Shockley
1950A.
Otsuki,
Ph.D.thesis,
Tyoto
University,
Japan
(1990)Energy
depends
onrotation
axis&
boundary
planeFig.
7-14
on
P419上面假设同转轴,同柏氏矢量Misorientation
Axis
[uvw]
;
=
5oEnergy
(m
J/m
2),T=240o
C[001][101][111]Tilt
parallel
disl.190170148Twist
network
disl.200205155材料科学基础(II)§4.
Interfacial
energy
(
)Experimental
results
on
copper.Gjostein
&
Rhines,
Acta
metall.
7,
319
(1959)TiltTwistNo
universal
theory
to
describe
the
energy
of
HAGBs.材料科学基础(II)§4.
Interfacial
energy
(
)TiltPorter
and
Easterling,2001For
high
angle
boundaries,
use
a
constant
valueunless
they
contain
dense
CSL
points材料科学基础(II)§4.
Interfacial
energy
(
)TiltCoherent
vs
incoherent
twinboundariesPorter
and
Easterling,2001CalculationsHasson,G.C.an材d
C料.Go科ux(学197基1).
础“Inte(rfacIiaIl
e)nergies
of
tilt
boundaries
in
aluminum.Experimental
and
theoretical
determination.”Scripta
metallurgica
5:889-894<100>Tilts<110>TiltsTwinObservationsEnergy
valleyEnergy
cusp材料科学基础(II)More
“coherent”
the
interface,the
lower
gb.J.
W.
Martin,
et
al,
1996Some
remarks:材料科学基础(II)Homework
7-2:
whether
the
boundary
will
rotate
or
notdepends
if
energy
is
lowered
after
rotation.Refer
to
p420
for
the
rough
data
of
interfacial
energy
forboth
cases.Annealing:
provides
kinetic
energy
for
the
atoms
tomove
towards
lower
energy
state.Most
materials
are
not
in
stable
equilibrium,
but
in
metastable
statep417Nearest-neighbor
broken-bond
modelAssumptions:Neglect
energy
of
secondary
bondsNeglect
difference
in
atoms
(as
in
unary)Neglect
relaxation
&
reconstruction
Us,
is
not
function
of
T (T
=
0K)
Hs
(heat
of
sublimation)
U
ZNa
/2Us
=
(
ni
pi
/2)/As
spi
:
numbers
of
broken
bonds
per
atom
of
type
isni
:
number
of
type
i
of
surface
atomss§4.
Interfacial
energy
(
)i=原子断键类型断键数量因原子位置而不同材料科学基础(II)fcc
(111)
surfaceExample
of
fcc
{1
1
1}:A
=
enclosed
by
<1
1
0>ni
=
3/2
+
3/6
=
2,
i
=
1!spi
=
3sA
=
a2{
(2)
(2)
[
(3)]/2}/2
=
a2[
(3)]/2Us
=
(
ni
pi
/2)/A
=
2
(3)
/as
s
2§4.
Interfacial
energy
(
)材料科学基础(II)fcc
(111)
surface材料科学基础(II)fcc
(100)
surfacefcc
(110)
surfaceBroken
bonds
of
surface
atomsp1s
=
3??Diagramillustrating
bondsacross
different
(hkl)
planesni
and
pi
vary
with
{hkl}s
snote
different
types
of
surface
atomstop
layer,
two
broken
bondsunder
layer,
x
bond(s)材料科学基础(II)料科学基础(II)Simple
cubic,(0
-1
3)P418
(114)
Fig.
7-11Porter
and
Easterling,2001材Terrace-ledge-kink
(TLK)
broken
bond
model
forsurface
energy
(
)I)材料科学基础(IA
=
1
a,
>
0
ni
pi
=
(cos
+
sin
)/as
sUs
=(
n
sp
s
/2)/AFig.
7-12i
i=
(cos
+
sin
)
/(2a2)=
(2)sin(
/4
+
)
/(2a2),Because
of
4
fold
symmetry,
=
±
/4,Us
=
Us
=
/[
(2)a2]max
=
0,
±
/2, Us
=
Us
=
/(2a2),mineqn
(7-8)Variation
of
Us
with
interface
orientation
ksin
4+
)
ksin
ksin
4+
)
极坐标系极坐标系!直角坐标系sin(
/4)
=
cos(
/4)
=
1/
(2)cos
+
sin
=
(2)[sin(
/4)cos
+cos(
/4)sin
]p418containingSpecific
interfacial
free
energy:
(p347)Internal
energy
(total)
in
a
systeminterfaces,
unitary
system
(C
=
1)eqn(5-89)dU
=
TdS
–
PdV
+
dAG
=
U
+
PV
–TSdG
=
dU
+
PdV
+VdP
–
TdS
–
SdT
+
dAdG
=
VdP
–
SdT
+
dAAt
constant
T
and
P:
dG
=
dAIf
is
isotropic,
A
=
Gxs
p347,
eqn(5-91);
p417,
eqn(7-3)§4.
Interfacial
energy
(
)Definition:
(
=Gxs/A)is
the
excess(过剩)Gibbs
freeenergy
forming
per
unit
area
of
the
surface
(interface)
layerGxs
=G(有界面体系)
G(无界面体系)(Cahn
1977)材料科学基础(II)Reversible
work
to
increase
the
interface
area
by
dA
is dWT,P
=
d(
A)
=
dA
+
Ad
dWT,P
=
dA,
when
(
/
A)P,T
=
06.
Surface
tension
(F/L)
and surface
stress
tensor
(fij)For:
A
=
xL,
dA
=
Ldx, d
=
dx/x
W
=
G
W
=
dA
+
Ad
=
(
dx
+
xd
)
L
=
Fdx
F/L
=
+
d
/d
or f
=
+
/
,
(isotropic)General
case: fij
=
ij
+
/
eij, (eij=strain
tensor)即:因为液相表面和内部的原子可以自由交换,表面结构可随面积改变而基本守恒,
表面张力=(比)表面(自由)能L材料科学基础(II)If
/
A
=
0,
Surface
tension
f
=
f
=
F/L
(N/m)
equal
in
value
to
(J/m2)Average
surfaceenergies
of
selectedsolids
and
liquids.Incoherent
grain
boundary
energy
gb
isabout
1/3
of
the
solid-vaporinterfacial
energy.材料科学基础(II)From:
J
M
HOWE.
Interface
in
Materials,
1997Porter
and
Easterling,2001材料科学基础(II)§5.
Equilibrium
boundary
segregation1.
Equilibrium
solute
concentration
C
p420
(Eq.
7-12)Helmhozltz
free
energy
due
to
solutesand
their
configuration
of
an
alloy:F
=
(PUl
+
QUg)
–
kTln(W)Number
of
states:W
=
N!n!/[P!(N
–
P)!Q!(n
–
Q)!]In
(
F/
Q)P,T
=
0, (note
dP=-dQ)Ug
–
Ul
=
kTln{(n
–
Q)P/[Q(N
–
P)]}Define:
Co
=
P/N
P/(N-P)C
=
Q/n
Q/(n-Q)a
l
g
o
E
=
N
(U –
U
)
=
RTln(C/C
)One
gets
C
=
Coexp(
E/RT)
eqn(7-18)sitesolutelatticeNPgr.
b.nQ
E
>
0,
C
>
CoTwo
sites
areconceivable
toincorporate
a
solute
atominto
the
boundary:
The
atom
may
occupy
a
lattice
site(A)or
a
non-lattice
site
in
the
boundary
core(B)偏聚假设每个晶格位置体积相等,C和Co可理解为体积百分数等体积,等温假设材料科学基础(II)Segregation
enthalpy
of
Pin
-FeH.
Gleiter,
Prog.
Mater.
Sci.
33
(1989)J
M
HOWE.
Interface
in
Materials,
1997材料科学基础(II)Grain
boundary
engineering:
historicalperspective
and
future
prospectsIncreasing
grain
boundary
enrichment
withdecreasingsolidsolubility材料科学基础(II)Porter
and
Easterling,2001材料科学基础(II)保温7s时,试样中硼分布和对应的金相照片Cui
and
He,
2001§6.
Equilibrium
boundary
segregationGibbs
absorption
equation
(Gibbs
Model)Definition
for
system
C>1:dU
=
TdS
–
PdV
+
idNi
+
dABy
increasing
system
at
constant
T
and
P
one
gets
(Cahn
77)U
=
TS
–
PV
+
iNi
A
A
=
U
+
PV
–
TS
–
iNi=
G
of
the
system
–
G
of
the
materials
in
the
systemExcess
quantity
in
a
system
of
+
+
interfaceUs
=
Uxs/ASs
=
Sxs/A
i
=
nxs/AUxs
=
U
–
Uα
–
Uβ,Sxs
=
S
–Sα
–
Sβ,nixs
=
ni
–
nαi
–
nβi,Vxs
=
V–
Vα
–
Vβ
=
0材料科学基础(II)§6.
Equilibrium
boundary
segregationIn
terms
of
excess
quantity,
one
gets: from
dU
=
TdS
–
PdV
+
idNi
+
dAito
dUxs
=
TdSxs
+
idN
xs
+
dAAnd
from
U
=
TS
–
PV
+
iNi
Ai
ito
Uxs
=
TSxs
+
N
xs
AThen
from:dUxs
=
d(TSxs
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