2026年ssat小升初考试试题

2026年ssat小升初考试试题考试时长：120分钟满分：100分试卷名称：2026年SSAT小升初考试试题考核对象：小学六年级学生题型分值分布：-单选题（10题，每题2分，共20分）-填空题（10题，每题2分，共20分）-判断题（10题，每题2分，共20分）-简答题（3题，每题4分，共12分）-应用题（2题，每题9分，共18分）总分：100分一、单选题（每题2分，共20分）1.Inthenumbersequence2,5,10,17,26,thenextnumberis______.A.35B.37C.39D.412.Ifarectanglehasaperimeterof24cmandalengthof6cm,itswidthis______.A.4cmB.6cmC.8cmD.10cm3.Thesumoftheinterioranglesofahexagonis______.A.360°B.540°C.720°D.900°4.Whichofthefollowingisaprimenumber?A.12B.15C.19D.215.If\(x=3\)and\(y=4\),then\(2x+3y\)equals______.A.18B.20C.22D.246.Theareaofacirclewithradius5cmisapproximately______.A.15.7cm²B.31.4cm²C.78.5cm²D.314cm²7.Whichofthefollowingfractionsisequivalentto\(\frac{3}{4}\)?A.\(\frac{6}{8}\)B.\(\frac{9}{12}\)C.\(\frac{12}{16}\)D.Alloftheabove8.Theleastcommonmultiple(LCM)of4and6is______.A.10B.12C.14D.169.Ifatraintravelsat60km/hfor3hours,thedistanceitcoversis______.A.20kmB.30kmC.180kmD.360km10.Theoppositeof\(-7\)is______.A.7B.-7C.0D.14二、填空题（每题2分，共20分）1.\(5+3\times2=\)______2.Thesquarerootof49is______3.\(\frac{1}{2}+\frac{1}{4}=\)______4.Thecomplementof65°is______°5.If\(a=5\)and\(b=2\),then\(a-b\)equals______6.Thevolumeofacubewithedgelength4cmis______cm³7.\(0.75\)asafractionis______8.Thenextnumberinthesequence2,4,8,16,32is______9.\(10\div\frac{1}{2}=\)______10.Theperimeterofasquarewithside6cmis______cm三、判断题（每题2分，共20分）1.\(7\times8=56\)iscorrect.2.Thenumber0isaprimenumber.3.Atrianglehas180°intotal.4.\(\frac{1}{3}\)isgreaterthan\(\frac{1}{4}\).5.TheLCMof3and5is15.6.Theradiusofacircleishalfitsdiameter.7.\(-5\)islessthan\(-3\).8.Thesumofanglesinaquadrilateralis360°.9.\(2^3=8\)iscorrect.10.Asquareisatypeofrhombus.四、简答题（每题4分，共12分）1.ExplainhowtofindtheLCMoftwonumbers.2.Whatisthedifferencebetweenanequilateraltriangleandanisoscelestriangle?3.Howdoyouconvertafractiontoadecimal?五、应用题（每题9分，共18分）1.Astoresold15applesand12orangesinoneday.Ifthetotalnumberoffruitssoldwas27,howmanyofeachfruitweresold?Showyourwork.2.Arectanglehasalengthof10cmandawidthof6cm.Finditsareaandperimeter.Also,calculatethediagonallengthusingthePythagoreantheorem.标准答案及解析一、单选题1.D(Thesequencefollowsthepattern\(n^2+1\):2=1²+1,5=2²+1,10=3²+1,17=4²+1,26=5²+1,nextis6²+1=37)2.C(Perimeter=2(length+width)→24=2(6+width)→width=6)3.C(Sumofinteriorangles=\((n-2)\times180\),forhexagon\((6-2)\times180=720\))4.C(Primenumbers:19isonlydivisibleby1and19)5.C(\(2\times3+3\times4=6+12=18\))6.C(Area=\(\pir^2\approx3.14\times25=78.5\))7.D(Alloptionssimplifyto\(\frac{3}{4}\))8.B(LCMof4and6is12)9.C(Distance=speed×time=60×3=180)10.A(Oppositeof\(-7\)is7)二、填空题1.112.73.\(\frac{3}{4}\)4.255.36.647.\(\frac{3}{4}\)8.649.2010.24三、判断题1.Correct2.Incorrect(0isneitherprimenorcomposite)3.Correct4.Correct5.Correct6.Correct7.Correct8.Correct9.Correct10.Correct四、简答题1.LCMMethod:-Listmultiplesofeachnumber.-Findthesmallestcommonmultiple.Example:LCMof4and6→Multiplesof4:4,8,12,16...Multiplesof6:6,12→LCMis12.2.Equilateralvs.IsoscelesTriangle:-Equilateral:Allsidesandanglesareequal.-Isosceles:Twosidesandtwoanglesareequal.3.FractiontoDecimalConversion:-Dividenumeratorbydenominator.Example:\(\frac{3}{4}=3\div4=0.75\).五、应用题1.Solution:-Let\(a\)beapples,\(o\)beoranges.-Equation:\(a+o=27\).-Given\(a=15\)