2026年青岛小升初数学小升初分班考卷：分班考全真模拟与附加题（校际联考版第1套）含参考答案、逐题解析与评分细则

青岛市校际联考版第1套·2026届小升初分班考数学试卷2026年青岛小升初数学小升初分班考卷：分班考全真模拟与附加题（校际联考版第1套）含参考答案、逐题解析与评分细则青岛市校际联考版（第1套）2026届小升初分班考数学试卷学校：班级：姓名：准考证号：满分：150分考试时间：120分钟试卷范围：小升初数学综合卷型：全真模拟与附加题注意事项1.本卷为2026届青岛小升初数学分班考全真模拟卷，满分150分，考试时间120分钟。2.请将选择题答案填写在指定答题栏内；解答题必须写出必要的文字说明、计算过程或推理步骤。3.单项选择题每题只有一个正确答案；多项选择题有两个或两个以上正确选项，全部选对得满分，漏选得部分分，错选或不选不得分。4.作图题或图形题若无图，请严格依据题干给出的文字关系作答；计算结果需要单位时必须写明单位。5.保持卷面整洁，书写规范。不得在密封线外填写无关内容。分值结构题型题号题量每题/小题分值小计单项选择题1—88题4分32分多项选择题9—124题5分20分填空题13—186题6分36分解答题19—224题14分、14分、16分、18分62分合计1—2222题—150分一、单项选择题（1—8题，每题4分，共32分）每题只有一个正确答案，请将所选答案填入答题栏。1.青岛某校2026届六年级进行分班考前人数统计，全年级人数为1728人。把1728写成质因数分解形式，正确的是（）。A.2⁵×3³B.2⁶×3³C.2⁶×3²D.2⁴×3⁴2.计算(3/5－1/4)÷7/10，结果是（）。A.1/4B.2/5C.1/2D.3/53.某套数学讲义原价160元，先按原价降低25%，分班考前又在降价后的价格上提高20%，现价是（）元。A.120B.136C.144D.1804.三所小学联合借阅图书，甲、乙、丙三校借阅册数的比是5:6:7，其中乙校比甲校多18册，三校一共借阅（）册。A.216B.270C.306D.3245.一个长方形操场的周长是64米，长是20米，这个操场的面积是（）平方米。A.220B.240C.260D.2806.小林5次数学小测的平均分是86分，其中一次是90分。去掉这一次后，其余4次的平均分是（）分。A.84B.85C.86D.877.从青岛北站到某校考点全程36千米，车辆先行驶全程的2/3用了30分钟，剩下路程以每小时48千米行驶。全程共用（）分钟。A.40B.45C.50D.548.一个盒子中有红球3个、黄球2个、蓝球1个，除颜色外完全相同。任意摸出1个球，摸到的不是红球的可能性是（）。A.1/3B.2/3C.1/2D.1/6单项选择题答题栏12345678二、多项选择题（9—12题，每题5分，共20分）每题有两个或两个以上正确选项。全部选对得5分；漏选且无错选得3分；错选或不选得0分。9.关于数1260，下列说法正确的有（）。A.1260既能被3整除，也能被5整除B.1260的最大质因数是5C.12和18的最小公倍数是36D.若n是奇数，则n＋2026仍是奇数10.一个长方形的长为8厘米、宽为6厘米。下列说法正确的有（）。A.它的周长是28厘米B.它的面积是48平方厘米C.它的对角线长是10厘米D.长和宽同时扩大到原来的2倍，面积扩大到原来的2倍11.下列关于分数、小数、百分数的判断正确的有（）。A.0.375＝3/8B.7/12＞5/9C.15%＝3/20D.2/3＋3/4＝5/712.在路程、速度、时间的数量关系中，下列说法正确的有（）。A.路程一定时，速度和时间成反比例B.速度一定时，路程和时间成正比例C.时间一定时，路程和速度成反比例D.速度和时间都扩大到原来的2倍，路程扩大到原来的4倍多项选择题答题栏9101112三、填空题（13—18题，每题6分，共36分）请把最终答案写在题中横线上；需要单位的答案必须写单位。13.计算：24×(5/6＋3/8)－18÷3/4＝__________。14.青岛海洋馆分班考奖励活动中，学生票48元，比成人票便宜20%，成人票是__________元。15.一个长12厘米、宽8厘米的长方形纸片，左下角剪去一个半径4厘米的四分之一圆形。若π取3.14，剩余纸片面积是__________平方厘米。16.数列2，5，10，17，26，……按规律排列，第20项是__________。17.从6名同学中选出2名参加校际联考志愿服务，共有__________种不同选法。18.甲、乙两队工作效率的比是3:2，两队合作12天完成一项整理任务。若甲队单独完成，需要__________天。四、解答题（19—22题，共62分，含压轴附加题）解答题须写出主要过程。只写答案不得满分；步骤清楚、单位正确、结论完整可按评分细则给分。19.计算与方程应用（14分）（1）计算：7.5×1.6－4.8÷0.6＋2/3÷4/9。（2）解方程：0.4x＋3/5＝2.8。（3）某班整理书籍，故事书和科技书原来的数量比是5:4。捐出18本故事书后，故事书与科技书的数量比变为7:8。原来两类书一共有多少本？作答区：________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________20.平面图形面积与比例（14分）长方形ABCD中，AB＝18厘米，BC＝12厘米。点E在AB上，AE＝6厘米；点F在CD上，DF＝8厘米。连接EF，四边形AEFD为阴影部分。（1）求阴影部分AEFD的面积。（2）求阴影部分与长方形中未涂色部分的面积比，并化成最简整数比。（3）点G在BC上，连接EG和CG，若三角形ECG的面积是30平方厘米，求CG的长度。作答区：________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________21.统计、平均数与概率（16分）青岛四所学校参加2026届小升初分班考前联合模拟，统计结果如下表。优秀率按“优秀人数÷参加人数”计算，平均分保留两位小数。学校参加人数优秀人数平均分甲校1203682乙校1003585丙校902780丁校1104483（1）四校一共有多少名学生参加？总优秀率约为多少？（2）求四校联合模拟的加权平均分。（3）从丁校参加模拟的学生中随机抽取1人，抽到优秀学生的可能性是多少？（4）若再有若干名补测学生加入，且补测学生全部达到优秀，要使总优秀率至少达到35%，至少需要增加多少名补测优秀学生？作答区：________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________22.压轴附加题：分班考组织与数的综合应用（18分）青岛市多校联合组织2026届小升初分班模拟。为避免错发，试卷总份数N满足：按24份一包分装剩6份，按30份一包分装也剩6份，且1000＜N＜1200。（1）求试卷总份数N。（2）若把全部考生安排在大、小两类考场中，大考场每场36人，小考场每场30人，且大考场数比小考场数的2倍少1，求大考场和小考场各有多少个。（3）监考安排为：每个大考场2名监考，每个小考场1名监考；另每6个考场配1名流动监考，不足6个也配1名。求共需监考教师多少名。（4）附加题讲评资料按每名考生1份、每个考场备用2份印制，按每袋50份密封，不足一袋也按一袋计。若每袋密封成本18元，求需要多少袋及总成本。作答区：________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________综合作答与检查区（不评分，可用于草稿、订正和验算）________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

参考答案与逐题解析、评分细则本部分用于教师讲评与学生订正。客观题给出答案与关键理由；解答题按步骤给出采分点。一、单项选择题答案与解析12345678BCCDBBBC1.答案：B。解析：1728＝12³＝(2²×3)³＝2⁶×3³。A少了一个因数2，C少了一个因数3，D虽然指数和相近，但2⁴×3⁴＝1296。2.答案：C。解析：先算括号：3/5－1/4＝12/20－5/20＝7/20；再除以7/10，相当于乘10/7，得到1/2。A、B是通分或倒数处理不完整造成的结果，D是把减法错看成加法后可能得到的干扰项。3.答案：C。解析：降低25%后价格为160×(1－25%)＝120元；再提高20%，现价为120×(1＋20%)＝144元。不能把“降25%再涨20%”直接合并成“降5%”。4.答案：D。解析：甲、乙、丙的比为5:6:7，乙比甲多1份，对应18册，所以1份是18册。三校总份数为5＋6＋7＝18份，总数为18×18＝324册。5.答案：B。解析：长方形周长64米，则长＋宽＝32米，宽＝32－20＝12米，面积＝20×12＝240平方米。6.答案：B。解析：5次总分为86×5＝430分，去掉90分后剩340分，4次平均分为340÷4＝85分。7.答案：B。解析：全程36千米，前2/3是24千米，用30分钟；剩下12千米，速度48千米/时，时间为12÷48＝1/4小时＝15分钟。全程共30＋15＝45分钟。8.答案：C。解析：共有3＋2＋1＝6个球，不是红球的有2＋1＝3个，可能性为3/6＝1/2。二、多项选择题答案与解析9101112A、C、DA、B、CA、B、CA、B、D9.答案：A、C、D。解析：A正确，1260各位数字之和为9，能被3整除，末位为0，能被5整除；B错误，1260＝2²×3²×5×7，最大质因数是7；C正确，12和18的最小公倍数是36；D正确，2026是偶数，奇数加偶数仍为奇数。10.答案：A、B、C。解析：A正确，周长＝(8＋6)×2＝28厘米；B正确，面积＝8×6＝48平方厘米；C正确，对角线与长、宽组成直角三角形，8²＋6²＝100，所以对角线为10厘米；D错误，长和宽都扩大2倍，面积扩大4倍。11.答案：A、B、C。解析：A正确，0.375＝375/1000＝3/8；B正确，7/12＝21/36，5/9＝20/36，所以7/12＞5/9；C正确，15%＝15/100＝3/20；D错误，2/3＋3/4＝8/12＋9/12＝17/12。12.答案：A、B、D。解析：A正确，路程＝速度×时间，路程一定时速度和时间成反比例；B正确，速度一定时路程随时间等倍变化；C错误，时间一定时路程和速度成正比例；D正确，路程＝速度×时间，两个因数都扩大2倍，积扩大4倍。三、填空题答案与解析13.答案：5。解析：24×(5/6＋3/8)＝24×5/6＋24×3/8＝20＋9＝29；18÷3/4＝18×4/3＝24；所以结果为29－24＝5。14.答案：60。解析：学生票48元相当于成人票的1－20%＝80%，成人票价为48÷80%＝60元。15.答案：83.44。解析：长方形面积为12×8＝96平方厘米；剪去的四分之一圆面积为3.14×4²÷4＝12.56平方厘米；剩余面积为96－12.56＝83.44平方厘米。16.答案：401。解析：观察数列：2＝1²＋1，5＝2²＋1，10＝3²＋1，17＝4²＋1，26＝5²＋1，所以第n项为n²＋1，第20项为20²＋1＝401。17.答案：15。解析：从6名同学中选2名，不区分先后，可列举为6×5÷2＝15种。18.答案：20。解析：设甲、乙每天效率分别为3份、2份，合作效率为5份/天。合作12天完成，总工作量为5×12＝60份；甲单独完成需60÷3＝20天。四、解答题参考答案、逐题解析与评分细则19.计算与方程应用（14分）参考答案：（1）5.5；（2）x＝5.5；（3）108本。逐题解析：（1）7.5×1.6＝12，4.8÷0.6＝8，2/3÷4/9＝2/3×9/4＝3/2＝1.5，所以原式＝12－8＋1