单片机上机操作考试题及答案

1、单片机上机考试试题1.使得8个发光二极管循环点亮，采用定时器方式0使得每个发光二极管点亮的时间为0.5s。#include int count=0;int minute=0;int temp;char code style8=0x7f,0xbf,0xdf,0xef,0xf7,0xfb,0xfd,0xfe;void desplay() temp=minute%8; p0= styletemp;void toproc() interrupt 1 count+; th0=0x0c; tl0=0x78;void main() tmod=0;th0=0x0c;tl0=0x78;tr0=1; et0=1;

2、ea=1; while(1) if(count=100) minute+; count=0; desplay();2.完成下面电路所示的功能，k1，k2对应两个开关按键。p1口对应发光二极管的状态p1.0p1.1p1.2p1.3p1.4p1.5p1.6p1.7k1=0,k2=0k1=0,k2=1k1=1,k2=0k1=1,k2=1#include char code style4=0x0,0xf0,0x33,0xff;sbit p1_0=p10;sbit p1_1=p11;void main() p0=0xff; while(1) if(p1_0=0&p1_1=0) p0=style0; if

3、(p1_0=0&p1_1=1) p0=style1; if(p1_0=1&p1_1=0) p0=style2; if(p1_0=1&p1_1=1) p0=style3; 3.在一个数码管上循环显示“h”“e” “l” “l” “o” ,循环的时间为1s。#include char code style5=0x89,0x86,0xc7,0xc7,0xc0;int i;int count=0;int second=0;void t0pro() interrupt 1 count+; tl0=0xb0; th0=0x3c; void display() i=second%5; p0=stylei;

4、void main() tmod=0x01;ea=1;tr0=1;et0=1;tl0=0xb0;th0=0x3c; while(1) if(count=20) second+;count=0;display(); 4.在6个数码管上分别显示自己学号的后六位数字。 #includechar code code1=0x4f,0x4f,0x01,0x06,0x06,0x4f;sbit p1_0=p10;char num;void delay(int timer) while(timer) -timer; void main() int i; while(1) num =0xfe; for(i=0;i

5、6;i+) p1=num; p2=code1i;delay(1000); num=(num1)|1; 5.做一个简易30s的倒计时秒表，秒表的显示通过8个发光二极管显示出来。#include#includestdio.hint count;count=0;void t0proc() interrupt 1 th0=0x3c; tl0=0xb0;count+; if(count=10) p0=p0+1; count=0;if(p0=0xff)p0=0xe1;void main()ea=1;et0=1;tmod=1;th0=0x3c; tl0=0xb0;tr0=1; p0=0xe1;while(1

6、); 6.使用外中断0来控制，去实现下列功能。其中k1为按键，p1口对应8个发光二极管的状态p1.0p1.1p1.2p1.3p1.4p1.5p1.6p1.7无按键按下（循环）有按键按下#include /sbit k1=p20; int count=0;void delay(unsigned char i); void int0proc() interrupt 0count+;p1=0xf0;void main() ea=1;ex0=1;it0=1;p1=0xcc; while(1) if(count%2=0) if(p1=0xcc)p1=0x30;delay(500); else p1=0x

7、cc;delay(500); void delay(unsigned char i) unsigned char j,k; for(k=0;ki;k+) for(j=0;j255;j+); 7.通过a/d转换电路，将模拟电压值在两个发光二极管上显示出来。（查询和中断方式均可）#include#include#define a xbyte0xcfa8sbit p=p32;sbit shi=p34;sbit ge=p35;void sepr(unsigned char w);void disp();unsigned char i,x,chh,chl;void main()while(1)adc08

8、09=0;while(p);x=adc0809;sepr(x);disp();void sepr(unsigned char w)unsigned char ch;ch=w;chh=ch/51;ch=ch%51;,chl=(ch*10)/51;void disp()unsigned char led1=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f;unsigned char led2=0xbf,0x86,0xdb,0xcf,0xe6,0xed,0xfd,0x87,0xff,0xef ;shi=0;ge=1;a=led2chh;for(i=0

9、;i50;i+);shi=1;ge=0;a=led1chl;for(i=0;i50;i+);8. 采用定时器方式1使得8个发光二极管按如下方式点亮，循环的时间为2sp1.0p1.1p1.2p1.3p1.4p1.5p1.6p1.7#include char code style4=0x0f,0xf0,0xcc,0xff;int i;int count=0;int second=0;void t0pro() interrupt 1 count+; tl0=0xb0; th0=0x3c; void display() i=second%4; p0=stylei; void main() tmod=0

10、x01;ea=1;tr0=1;et0=1;tl0=0xb0;th0=0x3c; while(1) if(count=40) second+;count=0;display(); 9.在一个数码管上循环显示“0” “1” “5” 3个数字，循环的时间为1s。#include char code style3=0xc0,0xf9,0x92;int i;int count=0;int second=0;void t0pro() interrupt 1 count+; tl0=0xb0; th0=0x3c; void display() i=second%3; p0=stylei; void main

11、() tmod=0x01;ea=1;tr0=1;et0=1;tl0=0xb0;th0=0x3c; while(1) if(count=20) second+;count=0;display(); 10.在4个数码管上稳定显示出“a” “c” “e” “p” 四个字符。#include char code style4=0x88,0xc6,0x86,0x8c;void main() while(1) p0=style0; p2=style1; p3=style2; p1=style3;11.试采用定时方式2，在p1.0引脚上输出频率为1khz的方波 （可能有问题）#includeint coun

12、t;count=0;sbit p1_0=p10;void t0proc() interrupt 1 p1_0=p1_0;void main()ea=1;et0=1;tmod=2; th0=0x06; tl0=0x06;tr0=1;p1_0=1;while(1); 12.做一个20s的简易秒表，当按键k1按下时，秒表暂停计数，k2按下时，开始计数。 #include reg51.h #define uchar unsigned char #define uint unsigned int uint count = 0; uchar i; /0-9段码 uchar code time = 0xc0

13、,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90; void stop() interrupt 2 /int1中断 et0 = 1; tr0 = 1; void start() interrupt 0/int0中断 et0 = 0; tr0 = 0; void timer() interrupt 1 /t0中断 th0=(65536 - 50000) / 256; /恢复定时器0 初值 tl0=(65536 - 50000) % 256; if(+i = 20) /50ms*20=1s 转换状态 i=0; count+; p0=timecount/10

14、; p1=timecount%10; if(count=20) count=0; /满20s后显示00 void main() /初始显示00 p0 = 0xc0; p1 = 0xc0; /t0采用方式1 tmod=0x01;/中断总开关 ea = 1; ex0 = 1; ex1 = 1; it0 = 1; it1 = 1;/int0优先 px0 = 1; while(1); 14.使用外中断1来控制，当无按键按下时8个发光二极管循环点亮，循环点亮的时间为1s，有按键按下时，8个发光二极管全部熄灭。#includestdio.h#includereg51.hint count=0;void i

15、nterint1() interrupt 2p0=0xff;et0=0;tr0=0;void intert0() interrupt 1if(count=15)th0=0xbd;tl0=0xc0;p0=(p01)|1;if(p0=0xff)p0=0xfe;count=0;count+;void main()ea=1;et0=1;tr0=1;tmod=0x01;th0=0xbd;tl0=0xc0;p0=0xfe;while(1) if(p33=0) ex1=1; it1=1; 15.通过串口控制单片机产生1khz的波型，当pc通过串口发过来“k”时，开始产生波型，当发过来“s”时，停止产生波型，

16、fosc=12mhz。（没答案）15.通过a/d转换电路，将模拟电压值在两个发光二极管上显示出来。（查询和中断方式均可）#include#include#define a xbyte0xcfa8sbit p=p32;sbit shi=p34;sbit ge=p35;void sepr(unsigned char w);void disp();unsigned char i,x,chh,chl;void main()while(1)adc0809=0;while(p);x=adc0809;sepr(x);disp();void sepr(unsigned char w)unsigned char

17、 ch;ch=w;chh=ch/51;ch=ch%51;,chl=(ch*10)/51;void disp()unsigned char led1=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f;unsigned char led2=0xbf,0x86,0xdb,0xcf,0xe6,0xed,0xfd,0x87,0xff,0xef ;shi=0;ge=1;a=led2chh;for(i=0;i50;i+);shi=1;ge=0;a=led1chl;for(i=0;i0) time-; void main() /p1=0xaa; while(1

18、) if(p0_0=0) if(p0_1=0) p1=0x00; delay(); else if(p0_1=1) p1=0x0f; delay(); else if(p0_0=1) if(p0_1=0) p1=0xf3; delay(); else if(p0_1=1) p1=0xaa; delay(); 17.完成下面电路的功能，p1口对应发光二极管的状态，状态1显示的时间为1s，状态2显示的时间为2s，状态3显示的时间为3s，如此循环p1.0p1.1p1.2状态1状态2状态3#includestdio.h #includereg51.hint count=0;int flag=0;voi

19、d first() p1=0x02; flag=0; th0=0xbd; tl0=0xc0;void intert0() interrupt 1 p1=0x02;if(flag=0)if(count=15) flag=1;count=0;th0=0xbd;tl0=0xc0;count+;else if(flag=1)p1=0x01;if(count=15)th0=0xbd;tl0=0xc0;if(count=30)flag=2;count=0;th0=0xbd;tl0=0xc0;count+;else if(flag=2)p1=0x04; if(count=15)th0=0xbd;tl0=0x

20、c0;if(count=30)th0=0xbd;tl0=0xc0;if(count=45)first();count=0;count+; void main() ea=1; tmod=1; et0=1; tr0=1; first(); while(1); 18.彩灯系统，实现8个发光二极管从左到右点亮，每个发光二极管点亮的时间为2s，然后从右到左亮，每个发光二极管点亮的时间为1.5s.#include#include#define uchar unsigned charuchar code tab=0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80;uchar co

21、de tab1=0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01;uchar state=0;uchar t_count=0;uchar i=1;void t0proc() interrupt 1th0=0x3c;tl0=0xb0;switch(state)case 0:if(+t_count=20)p0=tabi;i=(i+1)%8;if(i=7)state=1;t_count=0;break;case 1:if(+t_count=15)i=(i+1)%8;p0=tab1i;if(i=7)state=0;i=1;t_count=0;break;void main

22、()tmod=1;th0=0x3c;tl0=0xb0;ea=1;et0=1;tr0=1;p0=tab0;while(1);19 在4个数码管上显示出当天的日期。#include#define uchar unsigned char#define uint unsigned intuchar code tab=0xc0,0xb0,0xc0,0x92;void delay(int x)uchar i;while(x-)for(i=0;i120;i+);void main()p0=tab0;p2=tab1;p3=tab2;p1=tab3;delay(500);20. 完成下面电路的功能，p1口对应发

23、光二极管的状态，状态1显示的时间为3s，状态2显示的时间为1s，状态3显示的时间为0.5s，状态4显示的时间为0.1s，如此循环p1.0p1.1p1.2p1.3状态1状态2状态3状态4#include#includevoid delay(int time) while(time) -time; void main() p1=0xf3; delay(136364); p1=0xf1; delay(45455); p1=0xf0; delay(22727); p1=0xff; delay(4545);21. 采用51单片机扩展一片ram 6116和一片eprom 2732要求6116既能作为数据存

24、储器，又能作为程序存储器使用，编写出对2732读，对6116读与写的代码。#includeeg51.h#includeabsacc.h#define uchar unsigned charvoid main() uchar i,j,a; i = xbyte0x00ff; / 0x00ff上的字符 for(j=0;j10;j+) xbytej+0x08ff =a + j; /向 0x08ff写入数据 a = xbyte0x0900 ; /读0x08ff上的字符while(1);22. 扩展一片8255，使pa口工作在方式1输入，pb口工作在方式0输出。给出初始化8255程序，读与写的程序。硬件电

25、路如图所示。23. 数码管数字显示控制程序设计。控制要求：用按键k1和k2分别控制数码管显示数字09的顺序，当按下k1键时按从0到9的顺序显示，当按下k2时按从9到0的顺序显示。时间间隔均为1秒。硬件电路如图所示。 #include#define uchar unsigned char#define uint unsigned intuchar code tab1=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f;uchar code tab2=0x6f,0x7f,0x07,0x7d,0x6d,0x66,0x4f,0x5b,0x06,0x3f;

26、uchar t_count=0;sbit k1=p10;sbit k2=p11;uchar i=0;void t0proc() interrupt 1th0=0x3c;tl0=0xb0;if(+t_count=10)t_count=0;i=(i+1)%10;void main()tmod=1;th0=0x3c;tl0=0xb0;ea=1;et0=1;tr0=1;p0=0x3f;while(1)if(k1=0 & k2=1)p0=tab1i;else if(k1=1 & k2=0)p0=tab2i;24. 89c51与pc通过串口通信，单片机采用方式3串行通信，晶振都采用12mhz，波特率为12

27、00baud。要求：当单片机收到pc发来的数据“s”后，将30h-3fh的16个字节发送给乙机，当单片机收到“p”h时就发40h-5fh的32个字节数据。(待验证)#include void delay(void);sbit p1_4 = p14;unsigned char i;unsigned char data ch;unsigned char data s;unsigned char data tab12 = hello server;int j; void delay(void)unsigned char i;for(i=10;i0;i-);void display(j) char *

28、ads=0x30; char *adss=0x40; if(j=1) ti=0; while(ads=0x3f) sbuf = *ads; +ads; while(!ti) ti = 0; delay(); if(j=2) ti=0; while(adss=0x5f) sbuf = *adss; +adss; while(!ti) ti = 0; delay();void intoproc()interrupt 4 while(1) ri=0; ch=sbuf; if(ch=s) display(1); if(ch=p) display(2); void main() scon = 0x50;

29、/8位可变波特率, 无奇偶校验 tmod = 0x20;/定时器1为8位自动重装计数器 th1 = 0xe6; tl1 = 0xe6;/十进制230 tr1 = 1;/启动定时器1 ea=1; et1=1; es=1; ti=1; ri=1; while(1); 25. 交通控制系统，如下图所示，是交叉路口，要求：绿灯亮9秒后，黄灯闪3秒，后红灯亮9秒，两个数码管分别显视各种灯所剩余时间。#includestdio.h#includereg51.hsbit p0_0=p00;sbit p0_4=p04;sbit p0_1=p01;sbit p0_2=p02;sbit p0_3=p03;sbit

30、 p0_5=p05;int count=0;int count2=0;int flag1,flag2; /red=0,yellow=1,green=2;int yellow1=0,yellow2=0; int array=0x40,0x79,0x24,0x30,0x19,0x12,0x02,0x78,0x00,0x10;/向上路口及路口1的黄灯闪烁函数int yellow1(int cou) if(cou%15=0) p1=array3-cou/15; if(p1=0x40) flag1=0; cou=-1; th0=0xbd; tl0=0xc0; return cou; if(yellow1

31、=0) p0_2=0;if(cou%2=0)yellow1=1;else if(yellow1=1)p0_2=1;if(cou%5=0)yellow1=0; return cou;/向右路口及路口2的黄灯闪烁函数int yellow2(int cou) if(count2%15=0) p3=array3-count2/15; if(p3=0x40) flag2=0; count2=-1; th1=0xbd; tl1=0xc0; if(yellow2=0) p0_5=0;if(cou%2=0)yellow2=1;else if(yellow2=1)p0_5=1;if(cou%5=0)yellow

32、2=0; return cou;void intert1() interrupt 3 /控制向右及路口2的红绿灯if(flag2=0) p0_5=1; p0_4=0; if(count2%15=0) p3=array9-count2/15; if(p3=0x40) flag2=2; count2=-1; th1=0xbd; tl1=0xc0; else if(flag2=2) p0_4=1; p0_3=0; if(count2%15=0) p3=array9-count2/15; if(p3=0x40) flag2=1; count2=-1; th1=0xbd; tl1=0xc0; else

33、if(flag2=1) p0_3=1; count=yellow2(count); count2+;void intert0() interrupt 1 /控制向上的路口1的红绿灯 if(flag1=2) p0_1=1; p0_0=0; if(count%15=0) p1=array9-count/15; if(p1=0x40) flag1=1; count=-1; th0=0xbd; tl0=0xc0; else if(flag1=1) p0_0=1;count=yellow1(count);else if(flag1=0) p0_2=1; p0_1=0; if(count%15=0) p1

34、=array9-count/15; if(p1=0x40) flag1=2; count=-1; th0=0xbd; tl0=0xc0; count+;void initial() flag1=2; et0=1; tr0=1; th0=0xbd; tl0=0xc0; flag2=0; et1=1; tr1=1; th1=0xbd; tl1=0xc0;void main() ea=1; tmod=0x11; initial(); while(1);26. 利用定时计数器t0计数，计满3个脉冲后，t1定时工作，定时间隔为500ms，并通过p1.1引脚输出周期方波， fosc = 12mhz.（可能

35、有问题）#include sbit p1_1=p11; int count=0; void t0proc() interrupt 1 th0=tl0=253; void t1proc() interrupt 3 count+;if(count=10)/50ms一个周期 p1_1=p1_1; count=0; th1=0x3c; tl1=0xb0; void main() p1_1=0;ea=1;et0=et1=1;tr0=tr1=1;tmod=0x16;th0=tl0=253;th1=0x3c;tl1=0xb0;tf1=tf0=1;while(1); 27. 用外部中断1实现加计数功能，并将计

36、数值输出到数码管上显示。#include#includesbit p1_0=p10;/k1sbit p1_1=p11;/k2char count=0;char utime=0;char code tab10=0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90;void delay(int time) while(time) time-; void display() p0=tabcount/10; /显示十位 p2=tabcount%10; /显示个位 void int1part() interrupt 2 /tr0=1; +count; if(

37、count99) count=0; display();void main() p0=0xff; p2=0xff; ea=1;/总开关 ex1=1; /中断开关 it1=1; while(1) 28. led灯要求亮2秒钟，灭2秒钟，要求使用定时计数器，要求写主程序与中断程序，fosc = 6mhz#include sbit p1_1=p11; sbit p2_0=p20; sbit p1_0=p10; int count=0; void t0proc() interrupt 1 /100ms p1_0=0; th0=0x3c; tl0=0xb0; p1_0=1; void t1proc()

38、interrupt 3 p1_1=p1_1; void main() p1_1=0;tmod=0x61;ea=1;et0=1;th0=0x3c;tl0=0xb0;tr0=1;tr1=1;et1=1; th1=236;tl1=236;tf1=tf0=1;while(1); 29. 要求使用74ls139驱动四个数码管，用两个显示从24到0的侄计时，到0时自动复位；用两个显求从0到60的正向计时，到60时自动复位；每隔1秒跳到显示值变化一次。（没答案）30. 利用外部中断0，每申请一次中断使p0口连接的发光二极管点亮一个，从低位到高位，同时使p1口连接的发光二极管熄灭一个，从高位到低位。#include#define uchar unsigned charuchar code tab=0x01,0x03,0x07,0x0f,0x1f,0x3f,0x7f,0xff;uchar i=0;/int1中断函数void ex_int1() interrupt 2p0=tabi;p1=tabi;if(+i=8)i=0;/主程序void