




版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、Review of the last class,8.4.3 MSI Counters and Applications4位二进制计数器74x163,74x161异步清零,Connections for the 74X163 to operate in a free-running mode(P715) 74x163工作于自由运行模式时的接线方法,A free running divide-by-16 counter,a free-running 163 can be used as a divide-by-2, -4, -8, or -16 counter, by ignoring any
2、unnecessary high-order output bits.,Other MSI counters,1bit BCD counter 74x160 Synchronous clear 、 74x162 Asynchronous clear,74x160、74x162,the counting sequence is modified to go to state 0 after state 9. In other words, these are modulo-10 counters, sometimes called decade counters. the QD and QC o
3、utputs have one-tenth of the CLK frequency, they do not have a 50% duty cycle, and the QC output.,Other MSI counters,74x169-up/down counter,UP/DN,UP/DN = 1 counts up (升序) UP/DN = 0 counts down(降序),SDATA, application of the counter,Timing diagram for a modulo-8 binary counter and decoder,showing deco
4、ding glitches.,若在一次状态转移中有2位或多位计数位同时变化, 译码器输出端可能会产生“尖峰脉冲” 功能性冒险,More better way 。,A modulo-8 binary counter and decoder with glitch-free (无尖峰)outputs.,Modulo-m counter,Use SSI device Clocked Synchronous State-Machine Design Use MSI counter using n bit binary counter as a modulo-m counter in two cases
5、: m 2n,Although the 163 is a modulo-16 counter, it can be made to count in a modulus less than 16 by using the CLR_L or LD_L input to shorten the normal counting sequence.,using the 163 as a modulo-11 counter(用4位二进制计数器74x163实现模11计数器),清零法,计数到1010时, 利用同步清零端 强制为0000。, m2n,思考: 如果是74x161 (异步清零) 可以这样连接吗?,
6、 利用1011状态异步清零,会出现“毛刺”,Modulo-m counter,This circuit uses a NAND gate to detect state 10 and force the next state to 0. Notice that only a 2-input gate is used to detect state 10 (binary 1010). Although a 4-input gate would normally be used to detect the condition CNT10 = Q3 Q2 Q1 Q0, the 2-input gat
7、e takes advantage of the fact that no other state in the normal counting sequence of 010 has Q3 = 1 and Q1 = 1. In general, to detect state N in a binary counter that counts from 0 to N, we need to AND only the state bits that are 1 in the binary encoding of N.,using the 163 as a modulo-11 counter,置
8、数法, m2n 情况,计数到1111时, 利用同步预置数端 强制输出为0101,using the 163 as a modulo-11 counter,置数法, m2n 情况,计数到1111时, 利用同步预置数端 强制输出为0101,A 74x163 used as an excess-3 decimal counter 74x163用作余3码计数器,1 1 0 0,A 74x163 used as an excess-3 decimal counter 74x163用作余3码计数器,Q3 has one-tenth of the CLK frequency .the Q3 output h
9、as a 50% duty cycle,Cascading 74x163s(计数器的级联),Modulo m counter( m 2n),先进行级联,再整体置零或预置数 例:用74x163构造模193计数器 两片163级联得8位二进制计数器(0255) 采用整体清零法,0192 采用整体预置数法,63255 25619363 若 m 可以分解:m = m1m2 分别实现m1和m2,再级联,6310 = ( 0011 1111 )2,What is the modulo of the circuit below?,QD QC QB QA 0 0 0 0 0 1 1 0 0 1 1 1 1 0
10、0 0 1 1 1 0 1 1 1 1,Modulo 12 counter QD:12分频 占空比50,What is the modulo of the circuit below?,A shift register is an n-bit register with a provision for shifting its stored data byone bit position at each tick of the clock.,8.5 Shift Registers,8.5.1 shift register Structure (,a serial-in, serial-out
11、shift register (串入串出移位寄存器),可以使一个信号延迟 n 个时钟周期之后再输出,A serial-in, parallel-out shift register 串入并出移位寄存器结构,可以用来完成 串并转换 serial-to-parallel conversion,a parallel-in, serial-out shift register. 并入串出移位寄存器结构,多路复用结构,SERIN,parallel-in, parallel-out shift register 并入并出移位寄存器结构,SERIN,8.5.2 MSI Shift Registers(MSI
12、移位寄存器),an MSI 4-bit bidirectional, parallel-in, parallel-out shift register (4位双向移位寄存器74x194),left-in 左移输入,right-in 右移输入,left means “in the direction from QD to QA,” right means “in the direction from QA to QD.”,Function table for the74x194 4-bit universalshift register,保持,Qi* = S1S0Qi + S1S0Qi-1 +
13、S1S0Qi+1 + S1S0INi,The 74x194 4-bit universalshift register,CLK CLR S1 S0,移 位 寄 存 器 的 扩 展,8.5.3 Shift-Register Counters,Serial/parallel conversion is a “data” application, but shift registers have “nondata” applications as well. A shift register can be combined with combinational logic to form a sta
14、te machine whose state diagram is cyclic. Such a circuit is called a shift-register counter. Unlike a binary counter, a shift-register counter does not count in an ascending or descending binary sequence, but it is useful in many “control” applications.,8.5.5 Shift-Register Counters(移位寄存器计数器),D0 = F
15、 ( Q0 , Q1 , , Qn-1 ),一般结构:,1000,8.5.6 Ring Counters (环型计数器),D0 D1 D2 D3, 非自启动的,无效状态,D0 = Qn-1,self-correcting counter,self-correcting counter is designed so that all abnormal states have transitions leading to normal states. Self-correcting counters are desirable for the same reason that we use a minimal-risk approach to state assignment : If something unex
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2025版采砂工程安全生产责任承包合同
- 二零二五年度餐厅员工劳动权益保障与绩效评估合同
- 二零二五年产权式商铺返租管理及收益分成协议
- 2025版幼儿启蒙教育辅导中心专项培训合作协议
- 2025版烧烤店餐饮合作租赁合同范本
- 2025版P2P借贷业务风险管理咨询与评估协议
- 2025版科技馆产品陈列与科普教育合同
- 2025版电子合同管理系统定制开发合同
- 二零二五年度车辆租赁合同规范租赁管理
- 二零二五年度创新研发厂房建设施工合同范本
- R32环保(可燃)制冷剂空调器安装维修工艺操作手册(海尔)
- DB13-T 5907-2024 油莎豆栽培技术规程
- 祛痰药的使用指南及注意事项
- 样板引路实施细则
- 快速诱惑-中文版-Speed-seduction中文版-罗斯-杰弗瑞
- 宗教教职人员备案表
- 植物分类学植物系统与分类基础知识课件
- 人教版 数学 八年级上册 全册 同步练习
- 2023年八少八素图形推理测试真题精选
- 浅析图书发行企业在新形势下的财务管理策略
- GB/T 6478-2015冷镦和冷挤压用钢
评论
0/150
提交评论