2013年计算机等级考试三级PC技术上机（8） .doc

2013年计算机等级考试三级pc技术上机（8）请编制程序，其功能是：内存中连续存放着10个十六位二进制数，每个数的序号依次定义为0,1,9。统计每个数中位为0的个数n0,n1,n9(均用一个字节表示)，然后按序定义将n0至n9存入内存中，最后再用一个字节这10个数中为0的位的总数n(n=n0+n1+n9)。例如：内存中有 0000h,000fh,ffffh结果为 10h,0ch,00h最后为n部分程序已给出, 其中原始数据由过程load从文件input1.dat中读入source开始的内存单元中。运算结果要求从result开始存放,由过程save保存到文件output1.dat中。填空begin和end之间已给出的源程序使其完整(空白已用横线标出,每行空白一般只需一条指令, 但采用功能相当的多条指令亦可),或删除begin和end之间原有的代码并自行编程来完成要求的功能。对程序必须进行汇编,并与io.obj链接产生prog1.exe执行文件,最终运行程序产生结果(无结果或结果不正确者均不得分)。调试中若发现整个程序中存在错误之处, 请加以修改。试题程序：extrn load:far,save:farn equ 10stac segment stackdb 128 dup(?)stac endsdata segmentsource db n dup(?) ;顺序存放10个字节数result db n+1 dup(0) ;存放结果name0 db input1.dat,0name1 db output1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axlea dx,source ;数据区起始地址lea si,name0 ;原始数据文件名mov cx,n*2 ;字节数call load ;从input1.dat中读取数据;*begin*mov di,offset resultmov cl,nmov bx,0mov dh,0pro: mov dl,0mov ax,sourcebxmov ch,_count: _ jumpinc dljump: dec chjnz _mov di,dladd dh,dlinc diadd _dec cljnz promov _;*end*lea dx,result ;结果数据区首址lea si,name1 ;结果文件名mov cx,n ;结果字节数call save ;保存结果到文件retstart endpcode endsend 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