郭天祥单片机作业.docx

用位操作和总线操作两种方法完成以下题目1. 熟练建立KEIL工程2. 点亮第一个发光管.#includesbit D1=P10;void main()D1=0;#includevoid main ()P1=0xfe;2.8个发光管由上至下间隔1s流动，其中每个管亮500ms,灭500ms,亮时蜂鸣器响，灭时关闭蜂鸣器，一直重复下去。#include #include#define uint unsigned int#define uchar unsigned charsbit beep=P26;uchar temp;void delay();void main() temp=0xfe;while(1) P1=temp;temp=_crol_(temp,1);beep=0;delay();beep=1; void delay()uint x,y;for(x=500;x0;x-)for(y=110;y0;y-);3.8个发光管来回流动，第个管亮100ms,流动时让蜂鸣器发出“滴滴”声。#include #include#define uint unsigned int#define uchar unsigned charsbit beep=P26;uchar temp;void delay();void main() while(1)uint i;temp=0xfe; for(i=1;i8;i+) beep=0;P1=temp;delay(); beep=1; temp=_crol_(temp,1); for(i=1;i0;x-)for(y=110;y0;y-);4,用8个发光管演示出8位二进制数累加过程。#include /52单片机头文件#include /包含有左右循环移位子函数的库#define uint unsigned int /宏定义#define uchar unsigned char /宏定义void delay(uint z) /延时函数,z的取值为这个函数的延时ms数，如delay(200);大约延时200ms. /delay(500);大约延时500ms. uint x,y; for(x=z;x0;x-) for(y=110;y0;y-); void main() /主函数 uchar a; while(1) /大循环 a+; P1=a; delay(1000); 5.8个发光管间隔200ms由上至下，再由下至上，再重复一次，然后全部熄灭再以300ms间隔全部闪烁5次。重复此过程。#include#include#define uint unsigned int#define uchar unsigned charvoid delay(uint);uchar temp;void main() while(1) uint j; for(j=0;j2;j+) uint i;temp=0xfe;for(i=1;i8;i+) P1=temp; delay(200);temp=_crol_(temp,1);for(i=1;i8;i+) P1=temp;delay(200);temp=_cror_(temp,1);for(j=0;j0;i-)for(j=k;j0;j-);3. 间隔300ms第一次一个管亮流动一次，第二次两个管亮流动，依次到8个管亮，然后重复整个过程。#include#include#define uint unsigned int#define uchar unsigned charuchar temp;void delay();void main()uint i,j;while(1)temp=0xfe;for(j=0;j8;j+)for(i=0;i8-j;i+)P1=temp;delay();temp=_crol_(temp,1);temp=_crol_(temp,j);P1=0xff;temp=temp0;i-)for(j=110;j0;j-);4. 间隔300ms先奇数亮再偶数亮，循环三次；一个灯上下循环三次；两个分别从两边往中间流动三次；再从中间往两边流动三次；8个全部闪烁3次；关闭发光管，程序停止。#include#include#define uint unsigned int#define uchar unsigned charvoid delay();uchar temp;void main() uint i; uint j; for(i=0;i3;i+) P1=0x55;delay();P1=0xaa;delay();for(i=0;i3;i+)temp=0xfe;for(j=0;j7;j+)P1=temp; delay();temp=_crol_(temp,1);for(j=0;j7;j+)P1=temp;delay();temp=_cror_(temp,1); for(i=0;i3;i+)P1=0x7e;delay();P1=0xbd;delay();P1=0xdb;delay();P1=0xe7;delay();for(i=0;i3;i+)P1=0xe7;delay();P1=0xdb;delay();P1=0xbd;delay();P1=0x7e;delay(); for(i=0;i0;x-)for(y=110;y0;y-);1、 利用定时/计数器T0从P1.0输出周期为1s的方波，让发光二极管以1HZ闪烁，设晶振频率为12MHz#include sbit D1=P10;#define uint unsigned int;#define uchar unsigned char;uint tt;void main() TMOD=0x10;TH0=(65536-50000)/256;TL0=(65536-50000)%256;EA=1;ET0=1;TR0=1;while(1);void exter() interrupt 1TH0=(65536-50000)/256;TL0=(65536-50000)%256;tt+;if(tt=20)tt=0;D1=D1;2、利用定时/计数器T1产生定时时钟,由P1口控制8个发光二极管,使8个指示灯依次一个一个闪动，闪动频率为10次/秒(8个灯依次亮一遍为一个周期)，循环。#include#include#define uint unsigned int;#define uchar unsigned char;uchar tt,temp; temp=0xfe;void main() TMOD=0X10;TH1=(65536-50000)/256;TL1=(65536-50000)%256;EA=1;TR1=1;ET1=1;while(1);void time1() interrupt 3TH1=(65536-50000)/256;TL1=(65536-50000)%256;tt+; if(tt=2) tt=0;if(tt1)P1=temp;elsetemp=_crol_(temp,1);P1=temp;2、 同时用两个定时器控制蜂鸣器发声，定时器0控制频率，定时器1控制同个频率持续的时间，间隔300ms依次输出1，10，50,100，200,400,800,1k（hz）的方波。 #include /52单片机头文件#include /包含有左右循环移位子函数的库#define uint unsigned int /宏定义#define uchar unsigned char /宏定义sbit beep=P26;uchar tt;uint fre,flag;void main() /主函数 fre=50000; beep=0; TMOD=0x11;/设置定时器0,定时器1为工作方式1 TH0=(65536-fre)/256; TL0=(65536-fre)%256; TH1=(65536-50000)/256; TL1=(65536-50000)%256; EA=1;/开总中断 ET0=1;/开定时器0中断 ET1=1; TR1=1; TR0=1;/启动定时器0 while(1);/等待中断产生 void timer0() interrupt 1 /定时器0中断 TR0=0; /进中断后先把定时器0中断关闭，防止内部程序过多而造成中断丢失 TH0=(65536-fre)/256; TL0=(65536-fre)%256; tt+; if(flag=6&flag=12&flag=18&flag=24&flag=30&flag=36&flag=42&flag=48&flag54) tt=0; fre=156; beep=beep; TR0=1;void timer1() interrupt 3 TH1=(65536-50000)/256; TL1=(65536-50000)%256; flag+; if(flag=54) flag=0; fre=50000; 4、用定时器以间隔500MS在6位数码管上依次显示0、1、2、3.C、D、E、F，重复。 #include #include#define uint unsigned int #define uchar unsigned char uint aa;uchar num;uchar code table=0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e;void main() P1=0xf0;P0=0xc0; TMOD=0X10; TH1=(65536-50000)/256; TL1=(65536-50000)%256; EA=1; ET1=1; TR1=1; while(1); void timer0() interrupt 3 TH1=(65536-50000)/256; TL1=(65536-50000)%256; aa+; if(aa=10) aa=0;if(num=16)num=0; P0=tablenum; num+; 1. 利用动态扫描方法在六位数码管上显示出稳定的4321#include#include#define uint unsigned int #define uchar unsigned charuint num=0,tt=0,num1=0;uchar code table=0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e;uchar code table1= 0x0e,0x00d,0x0b,0x07 ;void main()TMOD=0X11;TH0=(65536-50000)/256;TL0=(65536-50000)%256;EA=1;ET0=1;TR0=1;while(1) if(tt=1)tt=0; num+;P0=tablenum;if(num=4)num=0;P1=table1num1;num1+;if(num1=4)num1=0;void timer0() interrupt 1TH0=(65536-5000)/256;TL0=(65536-5000)%256;tt+;2. 用动态扫描方法和定时器1在数码管的前三位显示出秒表，精确到1%秒，即后两位显示1%秒，一直循环下去。#include#include#define uint unsigned int #define uchar unsigned charuint bai,shi,ge, tt,num,temp=0;void display(uint bai,uint shi,uint ge);void delay(uint);uchar code table=0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e;uchar code table1= 0x0e,0x00d,0x0b,0x07 ;void main()TMOD=0X11;TH0=(65536-5000)/256;TL0=(65536-5000)%256;EA=1;ET0=1;TR0=1; while(1)if(tt=2)tt=0; bai=temp/100;shi=temp%100/10; ge=temp%10; display( bai, shi, ge);temp+; if(temp=9