EDA电路仿真实习报告.docVIP

电控学院EDA电路仿真院 （系）： 电气与控制工程学院 专业班级： 10级测控1班 姓 名： 张坡坡 学 号： 1006070127 2013年 1月 17日直流仿真11直流电路如图所示，试求节点电压V(2)。程序：* 01/15/13 14:06:40 * PSpice Lite (Mar 2000) * 1006070127 * CIRCUIT DESCRIPTION*R1 1 2 6R2 2 3 6R3 3 4 6R4 4 5 6R5 5 0 6R6 1 0 6IS1 1 0 DC 25IS2 4 5 DC 25IS3 3 4 DC 50.DC IS1 0 25 25.PRINT DC V(2).PLOT DC V(2).PROBE.OP.END* 01/15/13 14:06:40 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C* IS1 V(2) 0.000E+00 -1.500E+02 2.500E+01 -2.500E+02* 01/15/13 14:06:40 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C* IS1 V(2) (*)- -2.5000E+02 -2.0000E+02 -1.5000E+02 -1.0000E+02 -5.0000E+01 _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 0.000E+00 -1.500E+02 . . * . . 2.500E+01 -2.500E+02 * . . . . - - - - - - - - - - - - - - - - - - - - - - - - - - - * 01/15/13 14:06:40 * PSpice Lite (Mar 2000) * 1006070127 * SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C* NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE( 1) -200.0000 ( 2) -250.0000 ( 3) -300.0000 ( 4) -50.0000 ( 5) 50.0000 VOLTAGE SOURCE CURRENTS NAME CURRENT TOTAL POWER DISSIPATION 0.00E+00 WATTS* 01/15/13 14:06:40 * PSpice Lite (Mar 2000) * 1006070127 * OPERATING POINT INFORMATION TEMPERATURE = 27.000 DEG C* JOB CONCLUDED TOTAL JOB TIME 0.00运行图：2. 电路如图所示，试验证基尔霍夫电流、电压定律。（试证明，流入节点0的电流代数和为零；节点0，1，2，3，0构成的回路电压降代数和为零。）程序：* 01/15/13 15:29:09 * PSpice Lite (Mar 2000) * 1006070127 * CIRCUIT DESCRIPTION*R1 1 2 8R2 1 2 4R3 2 3 6R4 1 0 2R5 3 4 3R6 0 4 3IS 4 0 DC 3VS 0 3 DC 16.DC IS 0 3 3.PRINT DC I(R6) I(R4) I(VS) V(R2) V(R4) V(R3) .PROBE.OP.END* 01/15/13 15:29:09 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C* IS I(R6) I(R4) I(VS) V(R2) V(R4) 0.000E+00 2.667E+00 -1.500E+00 -4.167E+00 4.000E+00 -3.000E+00 3.000E+00 4.167E+00 -1.500E+00 -2.667E+00 4.000E+00 -3.000E+00* 01/15/13 15:29:09 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C* IS V(R3) 0.000E+00 9.000E+00 3.000E+00 9.000E+00* 01/15/13 15:29:09 * PSpice Lite (Mar 2000) * 1006070127 * SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C* NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE( 1) -3.0000 ( 2) -7.0000 ( 3) -16.0000 ( 4) -12.5000 VOLTAGE SOURCE CURRENTS NAME CURRENT VS -2.667E+00 TOTAL POWER DISSIPATION 4.27E+01 WATTS* 01/15/13 15:29:09 * PSpice Lite (Mar 2000) * 1006070127 * OPERATING POINT INFORMATION TEMPERATURE = 27.000 DEG C* JOB CONCLUDED TOTAL JOB TIME 0.00证明：由以上运行结果可得： 流入节点0得电流代数和：I=2.667+（-1.500）+（-4.167）+3.000=0 则：流入节点0得电流代数和为0.回路0-1-2-3-0的电压降为： U=(-4)+(-3)+(-9)+16=0则：回路的电压降为0直流仿真2上机作业：3.非线性电路如图所示，其中非线性电阻的电阻大小和温度的关 系为，求在27度、38度和50度时电路节点电压V(2)。（程序：ex-2-1）* 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * CIRCUIT DESCRIPTION*R1 1 2 3R2 1 0 4R3 2 2 RMOD 1KV1 1 0 5V.MODEL RMOD RES (R=0.8 TC1=0.016 TC2=0.004).TEMP 27 38 50.DC V1 LIST 0 5.PRINT DC V(2).END* 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * Resistor MODEL PARAMETERS* RMOD R .8 TC1 .016 TC2 4.000000E-03 * 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C* V1 V(2) 0.000E+00 0.000E+00 5.000E+00 5.000E+00* 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * TEMPERATURE-ADJUSTED VALUES TEMPERATURE = 38.000 DEG * * RESISTORS R3 R 8.672E+02 * 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 38.000 DEG C* V1 V(2) 0.000E+00 0.000E+00 5.000E+00 5.000E+00* 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * TEMPERATURE-ADJUSTED VALUES TEMPERATURE = 50.000 DEG C* * RESISTORS R3 R 1.107E+03 * 01/15/13 15:51:32 * PSpice Lite (Mar 2000) * 1006070127 * DC TRANSFER CURVES TEMPERATURE = 50.000 DEG C* V1 V(2) 0.000E+00 0.000E+00 5.000E+00 5.000E+00 JOB CONCLUDED TOTAL JOB TIME 0.004如图所示直流电路中的RL可变，试问RL为何值时它吸收的功率为最大，此最大功率为多少? （程序：ex-2-2）程序：1006070127R1 1 2 3R2 1 0 6RL 2 0 rrIs 1 0 5.PARAM rr=10.DC Lin PARAM rr 1 100 1.PROBE W(RL).END运行结果：交流仿真上机作业：5. RLC串联电路如图所示，试求电路的幅频特性和相频特性，频率特性，复阻抗的相频特性。（程序EX-3-1.cir）说明：复阻抗频率特性观测在ADD_TRACE命令下键入分别表示阻抗模的表达式V（1）/I（R1）、V（1）/I（R2）、V（1）/I（R3）、V（1）/I（R4）。复阻抗的相频特性观测在ADD_TRACE命令下键入分别表示阻抗角的表达式VP（1）/IP（R1）、VP（1）/IP（R2）、VP（1）/IP（R3）、VP（1）/IP（R4）。不同Q值下Z的实部的频率特性观测：在ADD_TRACE命令下键入分别表示阻抗实部的表达式R（V（1）/I（R1）不同Q值下Z的虚部的频率特性观测：在ADD_TRACE命令下键入分别表示阻抗实部的表达式IMG（V（1）/I（R1）Q为回路的品质因数，当发生谐振时，回路的感抗和容抗相等。把谐振时的回路感抗值（或容抗值）和回路电阻的比值称为回路的品质因数。Q=0.5，Q=1时是低通滤波，Q=2，Q=4时是带通滤波。程序如下：1006070127V1 1 0 AC 1L1 1 2 10ML2 1 4 10ML3 1 6 10ML4 1 8 10MR1 2 3 200R2 4 5 100R3 6 7 50R4 8 9 20C1 3 0 1000000PC2 5 0 1000000PC3 7 0 1000000PC4 9 0 1000000P.AC DEC 10 25HZ 250MEGHZ.PROBE.END运行结果：6.在图示电路中，已知，Xc=500, XL=1000, RL=2000,f=50HZ,求电流。(程序EX-3-2.cir)* 01/15/13 16:44:45 * PSpice Lite (Mar 2000) * 1006070127 * CIRCUIT DESCRIPTION*RL 2 3 2KC1 1 2 6400000PC2 3 0 6400000PL1 1 3 3.18HL2 2 0 3.18HVS 1 0 AC 100.AC DEC 10 50HZ 500HZ.PRINT AC I(RL).PRINT AC IP(RL).END* 01/15/13 16:44:45 * PSpice Lite (Mar 2000) * 1006070127 * SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C* NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE( 1) 0.0000 ( 2) 0.0000 ( 3) 0.0000 VOLTAGE SOURCE CURRENTS NAME CURRENT VS 0.000E+00 TOTAL POWER DISSIPATION 0.00E+00 WATTS* 01/15/13 16:44:45 * PSpice Lite (Mar 2000) *1006070127 * AC ANALYSIS TEMPERATURE = 27.000 DEG C* FREQ I(RL) 5.000E+01 1.060E-01 6.295E+01 8.301E-02 7.924E+01 6.958E-02 9.976E+01 6.183E-02 1.256E+02 5.726E-02 1.581E+02 5.450E-02 1.991E+02 5.281E-02 2.506E+02 5.176E-02 3.155E+02 5.110E-02 3.972E+02 5.069E-02 5.000E+02 5.044E-02* 01/15/13 16:44:45 * PSpice Lite (Mar 2000) * 1006070127 * AC ANALYSIS TEMPERATURE = 27.000 DEG C* FREQ IP(RL) 5.000E+01 4.473E+01 6.295E+01 2.994E+01 7.924E+01 2.137E+01 9.976E+01 1.590E+01 1.256E+02 1.213E+01 1.581E+02 9.398E+00 1.991E+02 7.350E+00 2.506E+02 5.781E+00 3.155E+02 4.564E+00 3.972E+02 3.611E+00 5.000E+02 2.862E+00 JOB CONCLUDED TOTAL JOB TIME 0.00结论：I（RL）幅值为5.044A，相位为2.862度即暂态仿真上机作业：7微分电路如图所示，是观察在改变电容参数下的输入信号和输出信号V（2）的波形图。电容参数分别为0.1F、0.5F、1F。（ex-4-1.cir）vs 1 0 pwl (0 3 2 3 2.01 0 4 0 )1006070127VS 1 0 PWL (0 3 2 3 2.1 0 4 0)R1 2 0 1C1 1 2 0.1.TRAN 0.1MS 4S.PROBE V(2).ENDC1=0.5F时1006070127VS 1 0 PWL (0 3 2 3 2.1 0 4 0)R1 2 0 1C1 1 2 0.5.TRAN 0.1MS 4S