宝典2C语言笔试冲刺复习资料.doc

4458250 093DDC C : 1): , (), (if switch)2)main(), (,)3) . .4)bit 0 1 byte , = .5) CCASCIICmainbreakswitch 1main define scanf printf IfIf22.333e-1 2.33310-1eee.3:1 1()0 ASCII48a ASCII97AASCII6565 1 0-0=48 A+32=a 324 , 41632, 45 int a = 0x6da 0x int a = 06d, x6d 0x141 010886 4458250 093DDC 7 inta intainta+b inta+b a+bab8a=b=5;5a=5+a6 a+5+a 1a+a6a+5a16a +aa+ aa6+ 234491 char a = 6, b;b = a2; a62 0 110 001. 10(1)(0)(1)3 21001888111%12) int a =1.6(int)a1/2 3/213)char a = 65 ;printf(%c, a); aprintf(%d, a); 651printf%d%c%f%ld long int%lf double2scanf&a ascanf(%d%d%*d%d,&a,&b,&c); 3putchar ,getchar char a = getchar() a 4458250 093DDC putchar(y)y4x y x=y ,y=x; t=xx=yy=t5 x = intx c001101 981210a) & | b) &| c) d) x 0100x100x 1001101 (0x)&(xa1 4 5 6 a2 7 8 9 *(a0+1)a01*(a1+2)a126 4458250 093DDC 3) int a=12 int a4=234 int a4=2344) int a12aa+1 *p2a0a1a0+1 *p25) a2 *a+2 a23 *a+23 *a+2+31 strlen() strcat strcmp strcpystrcat strcmp2strlen sizeof3define fxx*x define fx x*x 4int *pp = int *malloc2p = int *mallocsizeofintmalloc void *5mainint argcchar *argv 67typedef8*fint add(int x, int y).main() int *f;f=add; 4458250 093DDC add(23)f(23)*f239char a=a,b,c; sizeof(a)char a5= a,b,c sizeof(a)10scanf gets good good studyscanf(%s,a); good. gets(a); good good study! 11union TT int a;char ch2; sizeof (struct TT) = 2; TT t1 ; t1=0x1234; ch0=0x 34; ch1=0x1212)no1.c no2.cCno1.c o1.c#o1.cadd()no2.cadd()main no2.c.h no1.c#includeno2