文档简介
in a in a 6 of is as as is in of is if is in of is by be in an it be so it in it be to I. is an It is a in of it is an of of of a be or in in so is of as of or of is in a at be of do of or is to is in at be to so of is In be or is an of m/s be 1 in 2-4. of of to to of 5. is to of a a on of of or 6-9. of of is of be of to of of of be of is 1) 2) in I. to in 10 a on In be is at of is of 10. et 11 u et 12 a of on of be 13. is a of a 4 4l. be is or or or in of to be is on an at a of A of a is at a 2 % by In to of in a 9 2009610 to be is 13-14. be to of it to of in 4, to of as as 7, 15-17, to of 18 of 3, 5 to of 2 or to of 19. of to a to a to F he of is as of by = (1) is is 20. in to as in of of in of to by in a As in in of is by to 21. It is a et 11 in to in 2) is as is in 11, 20 B = ) is a is 2) be or on is In is is so be 2) of is in of of a 1. of of 12. 1 of on in an , , 5 of in a of in of a on 11, of a is of is It of a by as 085 to a 75 in s 22. It be of a of 23. of on 23. an on of in of of on is in a 12. of be at If of is a of is is at of is is At a in is 24. If a s is 9 2009611 50 of is 9. of of in of An of in of in a in is 24. an on in of 23. a 30 C 30 C, of on to be 23. of be if is 12, in In of at be of 25. of as as of a 10. of on be if in a 12. of a if it of 23. of 26, of of a on in of on he of 2 , by a at 2, 12( 3) is in m m. 12m m, A by of a a of a so of a A an in so be in so so of on is as in so be to be a a so be to be as .2 .1 45 of 4 . a at a a 0 a 616 50 kS/s) a P, 5 024 2 3 of 4 of at of 9 2009612 5 as be by he of be 3) 27 Q = )(128214(3) d is is l is at at . .5 m) or to m). is on is .2 l/.4 m/s) at a 8 C on is to in a by an of at 74 kg/a 8 C 64 kg/a 0 C. at 21 cP 2 a F 45 of .9 1377 m/s. of 6, of in .2 6 of as is to of 100011001200130014001500160017001800190020000123456m/s6 545 ll so is to an .1 of in is of is by a 3). is in p), of in +is in (n) of at in (a). 7. T P = F N = F = M/S p n a p n a p n a 1313 1383 1375 1366 1331 3 1377 5 1295 0 1383 1387 4 1326 1411 7 1388 1368 3 1359 1365 1360 4 1390 1388 2 1348 1405 7 1383 1390 7 1384 1389 0 1357 1371 1393 1360 0 1393 1397 1400 3 1373 1389 9 1379 1423 0 1393 1390 9 1393 1447 7 1360 1390 - 1407 6 1396 1365 5 1371 0 1384 1374 1391 1390 1374 1350 0 1391 1374 0 1377 1384 1403 7 1387 3 1382 1397 45 1377
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2025年棉花采购退出协议
- 2025年在线健身课程开发可行性研究报告及总结分析
- 2025年绿色交通出行服务创新项目可行性研究报告及总结分析
- 2025年罗非鱼苗合作协议(2025年)
- 《电子商务物流管理》高职全套教学课件
- 2025年零食产品采购合同
- 2025年老年食堂承包合同协议
- 2025年智慧城市建设及运营项目可行性研究报告及总结分析
- 2025年南方地区电动汽车推广项目可行性研究报告及总结分析
- 2025年智能供应链管理系统研发可行性研究报告及总结分析
- (正式版)JBT 5300-2024 工业用阀门材料 选用指南
- 职业健康体检报告
- 水文比拟法估算年径流量举例 (1)讲解
- 水稻育种第6节-分子标记辅助选择和转基因育种-2012年课件
- 信息技术单招考试重点知识点
- 低压柜试验报告
- 天津高考英语词汇3500
- (土壤学教学课件)第一章-土壤矿物质
- 外籍人员基本情况登记表
- 水尺计重的资料
- 中小学(中职学校)学生餐饮保障突出问题台账
评论
0/150
提交评论