




已阅读5页,还剩4页未读, 继续免费阅读
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
COMUNICATIONS IN STATISTICS 1996,25(6),1325-1334CONVERGENCE RATES FOR EMPIRICAL BAYES ESTIMATORS OF PARAMETERS IN LINEAR REGRESSION MODELSHengqing Tong Department of Mathematics and PhysicsWuhan University of TechnologyWuhan,Hubei,430070,P.R.ChinaKey Words and Phrases: empirical Bayes ;convergence rate;joint estimation; inverse stretch operation; variance component model. ABSTRACTIn this paper, the convergence rates of the estimators of the regression coefficients and the error variance in a linear model are obtained. The rates can approximate to arbitrarily. The convergence of the estimators of the regression coefficients and the variance components in a variance component model is also investigated. The investigation makes use of the results concerning the convergence rates of the estimators of the parameters in multi-parameter exponential families.1. Introduction Wind (1972) investigated the empirical Bayes () estimators of the regression coefficients in a multivariate linear model. Of course, at that time the convergence rate could not be given. Singh (1977, 1979) obtained the rates of convergence of the estimators in one-parameter exponential families. Tong (1996) studied the convergence rates of the estimators of parameters in multi-parameter exponential families. Now we investigate the convergence rates of the joint estimators of the regression coefficient and the error variance in a linear model, then we investigate the convergence of the estimators of the regression coefficients and the variance components in a variance component model.Let and be i . i . d. samples with density . and its partial derivatives are locally bounded. is the dimension of an orthogonal polynomial space in which the kernel estimators of the density are constructed. The parameter of has a prior distribution .Its Bayes risk and risk were defined by the author (1995). We have proved:THEOREM Suppose ,and (1.1) (1.2) (1.3)Then (1.4)2. Convergence of the kernel estimator of density and its partial derivative in multi-parameter exponential familiesFirst, we consider a linear model with a nomal distribution: (2.1)The columns of the design matrix are full rank. and are unknown. denotes the least square estimation of . The conditional density of is (2.2) Where .Second, the density (2.2) is transformed into a multi-parameter exponential family. Let is a nonsingular matrix. The transformations of parameter are defined as follows: (2.3) (2.4) (2.5)The transformations of sample are: (2.6) (2.7) (2.8)Then, (2.9)The density of is (2.10)Obviously, is a random variable with the distribution of exponential family. Its conditional density is (2.11)Third, we give the prior distribution of parameters and verify the conditions of the Theorem in the introduction. Suppose , (2.12)Where =. Let , (2.13) (2.14)According to the measurable transformations from (2.3) to (2.8), the prior distributions of the parameter of have also been given. Let , then (2.15) (2.16)By using the characteristic function, we have , denotes a suitable polynomial. Therefore, (2.17)The condition (1.1) is satisfied. Moreover, (2.18)Let , then (2.19)It is easy to calculate (2.20)Therefore, (2.21)For the derived measure of transformations, (2.22) (2.23)Because the negative exponentials in (2.22) and (2.23),(1.2) and (1.3) are satisfied. Now the number of parameters is , therefore, the rates of convergence of the joint estimators of the regression coefficients and the error variance in the linear model are . (2.24)When approximates to infinite, the rates can approximate to .3. The convergence of the estimators of parameters in variance component modelFirst, we consider a variance component model (3.1)Where is matrix. are matrixes. is a fixed effect vectors. are random effect vectors. Suppose (3.2) All are independent. Let (3.3) (3.4) Where and all are matrixes. Let (3.5) (3.6)Where is a matrix. is a vector. Then the model becomes (3.7)And , ,where is a matrix: (3.8) The fixed effect and the variance components are to be estimated. (3.9) Where is an vector.Second, the parameters to be estimated are transformed into a multi-parameter exponential family.Because (3.10)The conditional density of is (3.11)Because (3.12)The transformations of the parameters can be defined as follows: , (3.13) , (3.14) (3.15)Where is a vector, . Let , (3.16) , (3.17) (3.18)Where is a vector. Let (3.19)Then the conditional density of is (3.20) If the estimator of is obtained, then and can be estimated, moreover, can be estimated.Third, we consider the convergence of estimator of , .Let be the estimator of and be the Bayes estimator of . From the results of the Theorem in the introduction, we have (3.21)That is, (3.22)and (3.23)Because the mean square convergence certainly leads to probability convergence, we get (3.24) (3.25)Now we define an inverse operation of stretch operation: inverse stretch operation. Because this inverse stretch operation is not unique, we must explain the matrix by the foot note. If (3.26)We define (3.27)Putting the inverse stretch operation to , we obtain (3.28)And (3.29)Namely . Let (3.30) inconsistent equations (3.31)Are obtained. Their least square solution is (3.32)Because has been obtained, it follows that (3.33)Because has been obtained, it follows that (3.34)Because the function in (3.33) and (3.34) are continuous, having proved , we have (3.35)Noting and (3.28), we have (3.36)The least square solution of the is (3.37)Because and are obtained, we have (3.38)Because and are obtained, we get (3.39)Similarly, because of continuous function in (3.38) and (3.39), we have (3.40)From (3.35) and (3.40), we complete the proof of the convergence of the estimators of parameters in the variance component model.ACKNOWLEDGEMENTSThis work was supported by the National Natural Science Foundation of China. The author wishes to thank Professor Yaoting Zhang Associate Professor Yunxia Ma. Gratitude is expressed also to the Editors and the Referees for their com
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 鹿邑烧烤活动方案
- 集体活动喂香蕉活动方案
- 航空物流考试题及答案
- 韩国国旗考试题及答案
- 骨科高级考试题及答案
- 幼儿园教学教案设计:报纸时装周环保材料立体裁剪
- 产品质量跟进保障承诺书9篇范文
- 企业品牌推广及形象宣传材料制作标准模板
- 服装手绘考试题及答案
- 法语口语表达与交际技巧教学教案
- 2026年中考语文专项复习:新闻考点+答题方法知识点 讲义(含练习题及答案)
- 病房环境清洁与消毒PDCA课件
- 【《A公司电线电缆产品营销策略浅析》5800字(论文)】
- 公司注册登记培训课件
- 2025 年小升初上海市初一新生分班考试语文试卷(带答案解析)-(人教版)
- 2025康复医学考试题库(含参考答案)
- 26个字母卡片大小写A4打印-版
- 博物馆反恐安全知识培训课件
- 儿科高危药品与急救药品管理指南
- 《电机与拖动基础》课件(共十一章)
- 2024版中国难治性全身型重症肌无力诊断和治疗专家共识解读课件
评论
0/150
提交评论