「数据结构-矩阵的压缩存储程序【定稿材料】」.doc

实验报告课程名：数据结构（C语言版）实验名：矩阵的压缩存储姓 名： 班 级： 学 号： 时 间：2014.11.23一 实验目的与要求1. 掌握并实现稀疏矩阵的压缩存储的方法2. 在该存储方法上实现矩阵的操作二 实验内容 判断一个用二维数组存储的矩阵是不是稀疏矩阵 将其转化为压缩存储的形式 在压缩存储上实现矩阵的乘法和转置操作三 实验结果与分析压缩转置程序：#include/判断该矩阵是否为稀疏矩阵#define m10#define n10int amn=1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,7,0,0,0,0,0,0,0,8,0,0,0,0,0,0,0,0,0,0,0,0,0,;struct threeint i,j;int value;struct three stu100;struct three1int i,j;int value;struct three1 stu1100;int jiance()int x=0;/赋初值为0for(x=0;x=99;x+)stux.value=0;float t=0;float v;for(int i=0;im;i+)for(int j=0;jn;j+)if(aij!=0)t+;if(v=t/(m*n)=0.05)printf(该矩阵为稀疏矩阵%fn,v);return 1;elseprintf(该矩阵不是稀疏矩阵n);return 0;void yasuo()int t=0;for(int r=0;rm;r+)for(int c=0;cn;c+)if(arc!=0)stut.i=r;stut.j=c;stut.value=arc;t+;void display()int x=0;printf(压缩矩阵的三元组为:n);for(x=0;x=99;x+)if(stux.value=0)break;printf(%d,%d,%d ,stux.i,stux.j,stux.value);printf(n);void zhuanzhi()int x=0;/赋初值为0int t=0;int num10=0,0,0,0,0,0,0,0,0,0;/每一列非0的数目for(x=0;x=99;x+)stu1x.value=0;for(int j=0;jn;j+)for(int i=0;im;i+)if(aij!=0)numj+;t+;int cpot10=0,0,0,0,0,0,0,0,0,0;cpot0=0;for(j=1;jn;j+)cpotj=cpotj-1+numj-1;int col=0;int q=0;for(int k=0;kt;k+)col=stuk.j;q=cpotcol;stu1q.i=stuk.j;stu1q.j=stuk.i;stu1q.value=stuk.value;+cpotcol;void display1()int x=0;printf(转置以后的三元组为:n);for(x=0;x=99;x+)if(stu1x.value=0)break;printf(%d,%d,%d ,stu1x.i,stu1x.j,stu1x.value);printf(n);void display2() int d,b; for(d=0;dm;d+) for(b=0;bm;b+) printf(%d ,adb); printf(n); void main()display2();if(jiance()=1)yasuo();display();zhuanzhi();display1();图1：压缩转置程序运行结果矩阵的乘法程序：#include#define m13#define n14#define m24#define n22int a1m1n1=3,0,0,5,0,-1,0,0,2,0,0,0,;int a2m2n2=0,2,1,0,-2,4,0,0,;struct three1int i,j;int value;struct three1 stu1100;struct three2int i,j;int value;struct three2 stu2100;struct three3int i,j;int value;struct three3 stu3100;int ar1posm1=0;int ar2posm2=0;int Qrposm1;int yasuo1()int t=0;ar1pos0=0;for(int r=0;rm1;r+)for(int c=0;cn1;c+)if(a1rc!=0)stu1t.i=r;stu1t.j=c;stu1t.value=a1rc;t+;ar1posr+1=t;return t;int yasuo2()int t=0;ar2pos0=0;for(int r=0;rm2;r+)for(int c=0;cn2;c+)if(a2rc!=0)stu2t.i=r;stu2t.j=c;stu2t.value=a2rc;t+;ar2posr+1=t;return t;void chengfa(int x1,int x2)int a1m=0;int a2m=0;int tp,p,br,t,q,ccol;int qtu=0;for(a1m=0;a1mm1;a1m+)int ctempm1=0;if(a1m(m1-1)tp=ar1posa1m+1;elsetp=x1;for(p=ar1posa1m;ptp;+p)br=stu1p.j;if(br(m2-1)t=ar2posbr+1;elset=x2;for(q=ar2posbr;qt;+q)ccol=stu2q.j;ctempccol+=stu1p.value*stu2q.value;for(ccol=0;ccoln2;+ccol)if(ctempccol!=0)stu3qtu.i=a1m;stu3qtu.j=ccol;stu3qtu.value=ctempccol;+qtu;void display()int x=0;printf(a1与a2乘积之后的三元组是：n);for(x=0;x=99;x+)if(stu3x.value=0)break;printf(%d,%d,%d ,stu3x.i,stu3x.j,stu3x.value);printf(n);void display1()int m,n;printf(a1矩阵为：n);for(m=0;mm1;m+)for(n=0;nn1;n+)printf(%d ,a1mn);printf(n);printf(a2矩阵为：n);for(m=0;mm2;