压床-----齿轮机构设计(Ⅱ).doc

机械原理课程设计编程说明书设计题目：压床-齿轮机构设计()目录1. 设计任务及要求2. 数学模型的建立3. 程序框图4. 程序清单及运行结果5、齿轮啮合图 6设计总结7参考文献8.中期检查报告1. 设计任务及要求已知:齿轮,齿轮为正常齿制，工作情况位开式传动，齿轮与曲柄共轴。要求：1) 用C语言编写程序计算A. 中心距（圆整尾数为5或0或双数）；B. 啮合角；C. 按小轮不发生根切为原则分配变位系数；D. 计算基圆直径 节圆展角；E. 重合度;2) 计算出齿形曲线，在2号图纸上绘制齿轮传动的啮合图。3) 编写出计算说明书。2. 数学模型1) 注：下列尺寸单位为mm齿轮基本参数： 齿数： =10 =35 模数： m=6压力角： 齿顶高系数： 齿根高系数： 2) 实际中心距的确定： ； =（a/5+1）5；3) 啮合角： ； 分度圆分离系数： 分度圆直径； 基圆直径； 节圆直径： 4) 按小轮不发生根切为原则分配变位系数； ； 齿顶高变动系数： 齿顶高： 齿根高： 齿顶圆直径： 齿根圆直径； 分度圆齿厚： 基圆齿厚： 齿顶厚： 一般取基圆展角：5)重合度： 一般情况应保证 3. 程序框图输入m 计算 Y N 计算 计算 y Y0.25m N 计算Y1.2 N 计算 Y or N 计算 y 输出计算结果 4. 程序清单及运行结果(1) 程序清单#includemath.h#includestdio.h#define z510.0#define z6 35.0#define t 20*3.14/180 /*yalijiao,unit:rad*/#define m 6 /*moshu*/#define hax 1.0#define cx 0.25#define Zmin 17.0#define pi 3.14main() int a,ai; double ti; /*niehejiao*/ double x5,x6,xh; double db5,db6; /*jiyuanzhijing*/ double d5,d6; /*fenduyuanzhijing*/ double ha5,ha6; /*chidinggao*/ double hf5,hf6; /*chigengao*/ double df5,df6; /*chigenyuanzhijing*/ double di5,di6; /*jieyuanzhijing*/ double da5,da6; /*chidingyuanzhijing*/ double S5,S6; /*chihou*/ double Sb5,Sb6; /*jiyuanchihou*/ double Sa5,Sa6; /*chidingyuanchihou*/ double o5,o6; /*jieyuanzhanjiao*/ double e; /*chonghedu*/ double y; /*fenduyuanfenlixishu*/ double Xmin5,Xmin6; /*zuixiaobianweixishu*/ double cdm; /*chidinggaobiandongxishu*/ double u5,u6; double T5,T6,E5,E6; int j,i; a=m*(z5+z6)/2; printf(a=%d n,a); i=a/5; ai=(i+1)*5; printf(ai=%d (mm)n,ai); ti=acos(a*cos(t)/ai); printf(ti=%4.3f (rad)n,ti); y=0.5*(z5+z6)*(cos(t)/cos(ti)-1); printf(y=%5.3lf n,y); d5=m*z5; d6=m*z6; printf(d5=%5.3lf,d6=%5.3lf (mm)n,d5,d6); db5=m*z5*cos(t); db6=m*z6*cos(t); printf(db5=%5.3lf,db6=%5.3lf (mm)n,db5,db6); di5=d5*cos(t)/cos(ti); di6=d6*cos(t)/cos(ti); printf(di5=%5.3lf,di6=%5.3lf (mm)n,di5,di6); Xmin5=hax*(Zmin-z5)/Zmin; printf(Xmin5=%3.4lf (mm)nn,Xmin5); Xmin6=hax*(Zmin-z6)/Zmin; printf(Xmin6=%3.4lf (mm)nn,Xmin6); xh=0.5*(tan(ti)-ti-(tan(t)-t)*(z5+z6)/tan(t); printf(xh=x5+x6=%5.3f n,xh); for(j=0;j10;j+) x5=Xmin5+0.04*j; x6=xh-x5; if(x6=1.2)printf(重合度满足要求n);elseprintf(重合度不满足要求n);if(Sa5=0.25*m)&(Sa6=0.25*m)printf(齿顶厚满足要求n);elseprintf(齿顶厚不满足要求n);if(T5=E5)&(T6=E6)printf(不发生干涉n);elseprintf(发生干涉n); if(S5cx*m)&(S6cx*m)&(Sb5cx*m)&(Sb6cx*m)&(Sa5cx*m)&(Sa6cx*m)&(e1.2) printf(x5=%5.3lf,x6=%5.3lf (mm)n,x5,x6); printf(cdm=%5.3lf n,cdm); printf(ha5=%5.3lf,ha6=%5.3lf (mm)n,ha5,ha6); printf(hf5=%5.3lf,hf6=%5.3lf (mm)n,hf5,hf6); printf(da5=%5.3lf,da6=%5.3lf (mm)n,da5,da6); printf(df5=%5.3lf,df6=%5.3lf (mm)n,df5,df6); printf(S5=%5.3lf,S6=%5.3lf (mm)n,S5,S6); printf(Sb5=%5.3lf,Sb6=%5.3lf (mm)n,Sb5,Sb6); printf(Sa5=%5.3lf,Sa6=%5.3lf (mm)n,Sa5,Sa6); printf(o5=%6.5lf,o6=%6.5lf (rad)n,o5,o6); printf(e=%5.31f n,e); printf(u5=%5.3f,u6=%5.3f n,u5,u6); printf(T5=%5.3f,T6=%5.3f (mm)n,T5,T6); printf(E5=%5.3f,E6=%5.3f (mm)n,E5,E6); (2) 运行结果a=135ai=140 (mm)ti=0.437 (rad)y=0.833d5=60.000,d6=210.000 (mm)db5=56.385,db6=197.348 (mm)di5=62.222,di6=217.778 (mm)Xmin5=0.4118 (mm)Xmin6=-1.0588 (mm)xh=x5+x6=0.937重合度满足要求齿顶厚满足要求发生干涉x5=0.412,x6=0.526 (mm)cdm=0.104ha5=7.846,ha6=8.529 (mm)hf5=5.029,hf6=4.346 (mm)da5=75.693,da6=227.059 (mm)df5=49.941,df6=201.307 (mm)S5=11.217,S6=11.714 (mm)Sb5=11.381,Sb6=13.945 (mm)Sa5=2.772,Sa6=2.651 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2535171846914954000000000000000u5=4.249,u6=-6.529T5=0.108,T6=-0.515 (mm)E5=-0.002,E6=0.279 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.452,x6=0.486 (mm)cdm=0.104ha5=8.086,ha6=8.289 (mm)hf5=4.789,hf6=4.586 (mm)da5=76.173,da6=226.579 (mm)df5=50.421,df6=200.827 (mm)S5=11.392,S6=11.540 (mm)Sb5=11.545,Sb6=13.781 (mm)Sa5=2.576,Sa6=2.777 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2462562884050261000000000000000u5=3.489,u6=-6.446T5=0.126,T6=-0.512 (mm)E5=0.022,E6=0.272 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.492,x6=0.446 (mm)cdm=0.104ha5=8.326,ha6=8.049 (mm)hf5=4.549,hf6=4.826 (mm)da5=76.653,da6=226.099 (mm)df5=50.901,df6=200.347 (mm)S5=11.567,S6=11.365 (mm)Sb5=11.709,Sb6=13.617 (mm)Sa5=2.375,Sa6=2.899 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2386576453645259000000000000000u5=2.908,u6=-6.369T5=0.143,T6=-0.510 (mm)E5=0.047,E6=0.265 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.532,x6=0.406 (mm)cdm=0.104ha5=8.566,ha6=7.809 (mm)hf5=4.309,hf6=5.066 (mm)da5=77.133,da6=225.619 (mm)df5=51.381,df6=199.867 (mm)S5=11.741,S6=11.191 (mm)Sb5=11.873,Sb6=13.453 (mm)Sa5=2.168,Sa6=3.018 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2307225583191714000000000000000u5=2.451,u6=-6.299T5=0.161,T6=-0.507 (mm)E5=0.072,E6=0.258 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.572,x6=0.366 (mm)cdm=0.104ha5=8.806,ha6=7.569 (mm)hf5=4.069,hf6=5.306 (mm)da5=77.613,da6=225.139 (mm)df5=51.861,df6=199.387 (mm)S5=11.916,S6=11.016 (mm)Sb5=12.037,Sb6=13.289 (mm)Sa5=1.955,Sa6=3.135 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2224517403518671000000000000000u5=2.082,u6=-6.234T5=0.178,T6=-0.504 (mm)E5=0.097,E6=0.251 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.612,x6=0.326 (mm)cdm=0.104ha5=9.046,ha6=7.329 (mm)hf5=3.829,hf6=5.546 (mm)da5=78.093,da6=224.659 (mm)df5=52.341,df6=198.907 (mm)S5=12.090,S6=10.841 (mm)Sb5=12.201,Sb6=13.125 (mm)Sa5=1.736,Sa6=3.248 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2138453318745659000000000000000u5=1.776,u6=-6.175T5=0.196,T6=-0.502 (mm)E5=0.122,E6=0.244 (mm)重合度满足要求齿顶厚满足要求发生干涉x5=0.652,x6=0.286 (mm)cdm=0.104ha5=9.286,ha6=7.089 (mm)hf5=3.589,hf6=5.786 (mm)da5=78.573,da6=224.179 (mm)df5=52.821,df6=198.427 (mm)S5=12.265,S6=10.667 (mm)Sb5=12.365,Sb6=12.961 (mm)Sa5=1.511,Sa6=3.358 (mm)o5=0.03004,o6=0.03004 (rad)e=1.2049029135696958000000000000000u5=1.520,u6=-6.119T5=0.214,T6=-0.499 (mm)E5=0.147,E6=0.237 (mm)重合度不满足要求齿顶厚不满足要求发生干涉重合度不满足要求齿顶厚不满足要求发生干涉重合度不满足要求齿顶厚不满足要求发生干涉5、齿轮啮合图6、设计总结在这次课程设计中我初次接触到数学建摸，对于数学建模同课程设计的结合运用有了进一步的了解，并且熟悉了C语言和公式编辑器以及WORD文档的运用。但更重要的是在这次设计中，加深了对啮合齿轮的工作原理：大、小齿轮啮合时，小齿轮采用正变位，大齿轮采用负变位，是不等变位正传动，这样设计可以减小齿轮机构的尺寸，使齿轮承载能力提高，结论