c语言比赛-商人过河源代码.doc

#include#includevoid print() printf(*n); printf(* *n); printf(* welcome to the game *n); printf(* *n); printf(* Game rules: *n); printf(* 3man and 3rateiners and goods to pass *n); printf(*the river,the number of rateiners not more *n); printf(*over the number mans in the passing river. *n); printf(* Game operrations: *n); printf(* 1.input the number of men and rateiners *n); printf(* in turn *n); printf(* 2.input error keys,the game will restart*n); printf(*n);void began()/游戏开始 char ch; printf(nn); printf(press and key to start the game (Q key to quit).n); scanf(%c,&ch);if(ch=Q|ch=q) exit(0);/退出键void xianshi(char *a,char *b)/显示过河的动态 int ax=0,ay=0,bx=0,by=0;/ax ay代表原始岸边的人数，bx by代表现在岸那边人数 int i; for(i=0;i6;i+) if(*(a+i)=M)/岸这边商人数 ax+; if(*(a+i)=S)/岸这边仆人数 ay+; if(*(b+i)=M)/岸那边商人数 bx+; if(*(b+i)=S)/岸那边仆人数 by+; printf(this bankn);/岸边状况 for(i=1;iax;i+) printf(mann); printf(n); for(i=1;iay;i+) printf(rateinersn); printf(nn); printf(this bankn); for(i=1;ibx;i+) printf(mann); printf(n); for(i=1;iby;i+) printf(rateinersn); printf(nn);if(ax=0&ay=0&bx=3&by=3)/商人和仆人都运送过河 printf(congrarulation!You have finished the game!n);/游戏完成 exit(0);/退出游戏void pan(int ax,int ay,int bx,int by)/判断过河的商人与仆人是否安全即就是商人人数不少于仆人数 if(axay|bxby) printf(the men are killed!game overn); exit(0);main() int i,x=0,y=0; int ax=3,ay=3,bx=0,by=0; char a6,b6; system(color 1E); print(); began(); print();for(i=0;i3;i+)/M代表商人，s代表仆人 ai=M;for(i=3;i6;i+) ai=S;for(i=0;i6;i+)/游戏开始前的动态 即是3商人和3仆人在等待 bi=0;xianshi(a,b);/开始前动态do printf(please input number of man to that bank:);/输入商人乘船数 scanf(%d,&x); while(x2)/判定过河人数是否正确即不能超过2人或无人 printf(the wrong number ,please enter again:); scanf(%d,&x); print(); xianshi(a,b); printf(please input number of rateiners to that bank:);/输入仆人乘船数 scanf(%d,&y); while(y2|x+y2)/判定过河人数是否正确即不能超过2人或无人 printf(the wrong number ,please enter again:); scanf(%d,&y); ax=ax-x;ay=ay-y;pan(ax,ay,bx,by);bx=bx+x;by=ay+y;/一次过后，两边商人与仆人的人数print();for(i=0;i6;i+)ai=0;bi=0;for(i=0;iax;i+) ai=M;for(i=3;i3+ay;i+) ai=S;for(i=0;ibx;i+) bi=M;for(i=3;i3+by;i+) bi=S;xianshi(a,b); printf(please input number of man to this bank:); scanf(%d,&x); while(x2) printf(the wrong number ,please enter again:); scanf(%d,&x); print(); xianshi(a,b); printf(please input number of rateiners to that bank:);/输入仆人乘船数 scanf(%d,&y); while(y2|x+y2)/判定过河人数是否正确即不能超过2人或无人 printf(the wrong number ,please enter again:); scanf(%d,&y); bx=bx-x;by=by-y;pan(ax,ay,bx,by);ax=ax+x;ay=ay+y;/一次过后，两边商人与仆人的人数print();for(i=0;i6;i+)ai=0;bi=0;for(i=0;iax;i+) ai=M;for(i=3;i3+ay;i+) ai=S;for(i=0;ibx;i+) bi=M;for(i=3;i3+by;i+) bi=S;xianshi(a,b); printf(please input number of