C语言课后题答案-高教出版社(程光华主编).doc

C语言程序设计课后习题答案第一章一.判断题1.对 2.错 3.对 4.错 5.错 6.错 7.错 8.对 9.对 10.对二.选择题1.D 2.D 3.D 4.A 5.D 6.A三.程序设计题1.# include stdio.h void main() printf(我的姓名是陈暄n); printf(我的性别是男n); printf(我的年龄是29岁n); 2.略3.略(参看课本P37图3-2)第二章一.判断题1.错 2.对 3.错 4.对 5.错 6.对7.对 8.错 9.对 10.对二.选择题1.C 2.C 3.D 4.C 5.A 6.A 7.D8.A 9.D 10.A 11.A 12.C 13.A14.A 15.A 16.B三.程序阅读题1.10,92.6,4第三章一.选择题1.D 2.C 3.A 4.A 5.A 6.B 7.B二.程序填空题1.scanf(%d,%d,%d,&num1,&num2,&num3); aver=sum/3;2.da=basic*0.35; hra=basic*0.25;3.clrscr() b=a-32;三.程序阅读题1.02.8100四.程序设计题1.# include stdio.h void main() float hua,she; scanf(%f,&hua); she=5.0/9.0*(hua-32); printf(%f,she); 2.# include stdio.h # include math.h void main() float a,b,c,disc,x1,x2,realpart,imagpart; scanf(%f,%f,%f,&a,&b,&c); disc=b*b-4*a*c; x1=(-b+sqrt(disc)/(2*a); x2=(-b-sqrt(disc)/(2*a); printf(%f,%f,x1,x2); 第四章一.选择题1.C 2.B 3.B 4.D 5.C 6.B 7.B二.程序设计题1. u,v xy uz2.ch=A&ch0)&(m%5= =0)&(m%7= =0) printf(YES); else printf(NO); 2. # include stdio.h void main() int a,b,c,d,max; scanf(%d,%d,%d,%d,&a,&b,&c,&d); if(ab) max=a; else max=b; if(maxc) c=max; if(maxd) d=max; printf(max is %d,max); 3.# include stdio.h # include math.h void main() int x,y; scanf(%d,&x); if(x-1) y=fabs(x); else if(x1) y=2-sin(x); else if(x=3) y=cos(x)+3; else y=x*x; printf(%d,y); 第五章一.选择题1.B 2.A 3.D 4.D 5.C二.程序填空题1.float s=0,item=1; fabs(item)1e-6 flag=-flag;2.s=1 j=i/2; i= =s3.scanf(%d,&n),n=0 t=t*2;4.m=0&nn)?n:m三.程序阅读题1.2#4#7#11#16#2.18 求两个数的最小公倍数3.223357114.12 9四.程序设计题1.# include stdio.h void main() float sn=20,hn=2*sn/3; int n; for(n=2;n=3;n+) sn=sm+2*hn; hn=hn*2/3; printf(第三次落地共经过%f米n,sn); printf(第三次反弹的%f米n,hn); 2.#include void main() int i, j; for (i=1; i=9; i+) for (j=1; j=i; j+) printf(%d*%d=%2d,i,j,i*j); printf(n); 3.# include stdio.h void main() float x,s=0.0; int in,i,t1=1,t2=1,flag=1; scanf(%f%d,&x,&n); for(i=1;i=n;i+) t1=t1*x; t2=t2*i; s=s+flag*t1/t2; flag=flag*(-1); printf(s=%f,s); 4.# includestdio.h void main() int cnt=0,sum=0,max=min=0; float v; while(1) while(scanf(%d,&n),nmax) max=n; if(nmin) min=n; v=(float)sum/cnt;printf(数据有%d个,和是%d,平均值是%f,最大值是%d,最小值是%d,cnt,sum,v,max,min); 5.# include stdio.h # include math.h void main() float s=1,t=1,i=3; while(1) if(i= =3) t=i*(i-1)*(i-2); else t=t*i*(i-1); if(fabs(1.0/t)1e-5) break; t=-t; s=s+1.0/t; i=i+2; printf(s=%f,s); 6.# includestdio.h void main() int x,y,z,k=0; for(x=-45;x=45;x+) for(y=-45;y=45;y+) for(z=-45;z=45;z+) if(x*x+y*y+z*z= =2000) printf(x=%d,y=%d,z=%dn,x,y,z); 第六章一.选择题1.A 2.C 3.D 4.D 5.B 6.D 7.B8.A 9.C 10.D 二.程序填空题1. f1+f2 i%5= =0 f2=f2. s1i+=s2j+ s1i三.程序阅读题1.1,1,2,3,5,8,13,21,34,552.sum=偶数的个数3.数组中的字符从小到大的排序四.程序设计题1.# include stdio.h void main() int a10,i,max=min=0; for(i=0;i10;i+) scanf(%d,&ai); for(i=0;i10;i+) if(maxai) min=ai; printf(max=%d,min=%d,max,min); 2.# include stdio.h void main() int a55,i,j,sum=0; for(i=0;i5;i+) for(j=0;j5;j+) scanf(%d,&aij); for(i=0;i5;i+) for(j=0;j5;j+) if(i= =j) sum=sum+aij; if(i+j= =5) sum=sum+aij; printf(sum=%d,sum); 3.假设3个学生4门功课 # includestdio.h void main() float a34,sum=aver=0.0; int i,j; for(i=0;i3;i+) for(j=0;j4;j+) scanf(%d,&aij); for(i=0;i3;i+) sum=0.0; for(j=0;j4;j+) sum=sum+aij; aver=sum/4； printf(第%d个学生的平均成绩是%f,i+1,aver); for(j=0;j4;j+) sum=0.0; for(i=0;i3;i+) sum=sum+aij; aver=sum/3; printf(第%d门课程的平均成绩是%f,j+1,aver); 第七章一.选择题1.C 2.C 3.D 4.A 5.C二.程序填空题1.x x*x+12.sum=sum+ai; v=average(a);三.程序阅读题1.152.8,17四.程序设计题1.# include stdio.h void f(int a,int n) int i,j,temp; for(i=0;in-1;i+) for(j=0;jn-1-i;j+) if(ajaj+1) temp=aj; aj=aj+1; aj+1=temp; void main() int a10,i; for(i=0;i10;i+) scanf(%d,&ai); f(a,10); for(i=0;i10;i+) printf(%d,ai); 2.# include stdio.h long f(int n) long fact=1; int i,j; for(i=1;i=n;i+) fact=fact*i; return fact; void main() int a,b; long s; scanf(%d%d,&a,&b); s=f(a)+f(b); printf(s=%ld,s); 3.# includestdio.h long f(int m,int k) int i,t=1; for(i1;i=k;i+) t=t*m; return t; void main() int i,n,k; long s=0; scanf(%d,%d,&n,&k); for(i=1;iam t=ak;ak=ai;ai=t;四.程序阅读题1.29801 2.略 3.1bc,a23五.程序设计题1.# include stdio.h # inlcude string.h void main() char a80; int cnt=0,i; gets(a); for(i=0;si!=0;i+) cnt+; printf(%d,cnt); 2.# include stdio.h # include string.h void main() char b100,a100; int i,cnt=0,n,m; gets(a); scanf(%d,&m); n=streln(a); for(i=0;i=n-m;i+) bcnt+=am-1+i; bcnt=0; puts(b); 3.# include stdio.h # include string.h void main() char *temp,*p; char *nation5=Amercia,China,Korea,Japanese,Aferica; int i,j,k; p=nation; for(i=0;i4;i+) for(j=0;j0) temp=*(p+j); *(p+j)=*(p+j+1); *(p+j+1)=temp; for(i=0;i5;i+) printf(%sn,*(p+i); 第九章一.选择题1.D 2.D 3.B 4.A 5.A二.程序填空题1.ab cd 2.sk.aver maxsubinf(p-nxet)-inf三.程序阅读题1.182.1 2 30 41四.程序设计题1.# include stdio.h struct data int y,m,d; void main() int s; struct data a; scanf(%d-%d-%d,&a.y,&a.m,&a.d); s=a.d; switch(a.m-1) case 11:s+=30; case 10:s+=31; case 9:s+=30; case 8:s+=31; case 7:s+=31; case 6:s+=30; case 5:s+=31; case 4:s+=30; case 3:s+=31; case 2:if(a.y%4= =0&a.y%100!=0|a.y%400= =0) s+=29; else s+=28; case 1:s+=31; printf(%d-%d-%d是该年的第%d天n,a.y,a.d,s); 2. # include stdio.h struct std_info char no10; char name9; float score; a5; void main() float aver=0,max; int i,t; for(i=0;i5;i+) scanf(%s,ai.no); scanf(%s,ai,name); scanf(%f,ai.score); max=a0.score; t=0; for(i=0;i5;i+) aver=aver+ai.score; if(maxno,no) p=p-next; if(p!=NULL) p-score=score; else printf(学号%s找不到!n,no); return head; 4.# define NULL 0 # define LEN sizeof(struct node) stuct node int no; struct node *next; ; struct node *josephus(struct node *head,int n,int s,int m) struct node *p,*prior,*head_out,*tail_out; int count,num=0; p=head;prior=NULL; for(count=1;countnext; while(num=n-1) count=1; for(;countnext= =NULL) prior=NULL; p=head; else prior=p; p=p-next; prior-next=p-next; num+; if(num= =1) head_out=tail_out=p; else tail_out-nxt=p;tail_out=p; if(p= =head) head=head-next; if(p-next= =NULL) p=head; else p=p-next;