Java大学基础教程(英文第六版)课后第二章自测题答案.docx

package my.p2;import java.util.Scanner;public class Practice public static void main(String args) / 2.14ASystem.out.println(习题2.14答案);System.out.println(1 2 3 4);/ 2.14BSystem.out.print(1 );System.out.print(2 );System.out.print(3 );System.out.print(4);/ 2.14CSystem.out.printf(n%d %d %d %d, 1, 2, 3, 4); / % 格式说明符，后接数据类型/ 2.15：import firstSystem.out.print(n习题2.15答案（提示：类似SelfTest2_5.java）);Scanner input = new Scanner(System.in);int n1, n2, products, quotients, sums, differences;System.out.print(ninput the first integer:n);n1 = input.nextInt();System.out.print(input the second integer:n);n2 = input.nextInt();sums = n1 + n2;differences = n1 - n2;products = n1 * n2;quotients = n1 / n2;System.out.printf(the four operations(+ - /) outcomes are %d %d %d %d, sums,differences, products, quotients);/ 2.16System.out.print(nn习题2.16答案n);System.out.printf(The numbers are %d and %d, n1, n2);if (differences 0)System.out.printf(nnThe larger is n1= %dn, n1);if (differences n3)min = n3;if (n3 n1)max = n3;System.out.printf(nThe maximum number is %d , and the minimum number is %d,max, min);/ 2.18System.out.print(n习题2.18答案n);System.out.print(nthe quadrate is n);System.out.printf(*n* *n* *n* *n* *n* *n* *n* *n* *n*n);System.out.print(nthe ellipse is n);System.out.printf( * n * * n* *n* *n* *n* *n* *n* *n * * n * n);System.out.print(nthe arrow is n);System.out.printf( * n * n * n * n * n * n * n * n * n * n);System.out.print(nthe rhombus is n);System.out.printf( * n * n * * n * * n* *n * * n * * n * n * n);/ pentagam/ System.out.print(n)/ 2.19System.out.print(n习题2.19答案n);System.out.println(*n*n*n*n*);/ 2.20-23略，2.24略/ 2.25System.out.print(n习题2.25答案n);int n4, testn;System.out.print(n输入一个5位整数n);n4 = input.nextInt();testn = n4 % 2;if (testn = 0)System.out.printf(n%d is 偶数n, n4);if (testn != 0)System.out.printf(n%d is 奇数n, n4);/ 2.26System.out.print(n习题2.26答案n);int testnn;testnn = n1 % n2;if (testnn = 0)System.out.printf(n%d is %d 的倍数n, n1, n2);if (testnn != 0)System.out.printf(n%d isnt %d 的倍数n, n1, n2);/ 2.28System.out.print(n习题2.26答案n);int r = n3;double di, ci, ar;di = 2 * r;ci = 2 * Math.PI * r;ar = Math.PI * r * r;System.out.printf(nThe diameter of the circle is %f;nthe perimeter of the circle is %f;nand the area of the circle is %fn,di, ci, ar); / %f 不能写成%d/ 2.29System.out.print(n习题2.29测试n);System.out.printf(The character of %c has the value %dn, A,(int) A);System.out.printf(The character of %c has the value %dn, B,(int) B);System.out.printf(The character of %c has the value %dn, C,(int) C);System.out.printf(The character of %c has the value %dn, a,(int) a);System.out.printf(The character of %c has the value %dn, b,(int) b);System.out.printf(The character of %c has the value %dn, c,(int) c);System.out.printf(The character of %c has the value %dn, 0,(int) 0);System.out.printf(The character of %c has the value %dn, 1,(int) 1);System.out.printf(The character of %c has the value %dn, 2,(int) 2);System.out.printf(The character of %c has the value %dn, $,(int) $);System.out.printf(The character of %c has the value %dn, *,(int) *);System.out.printf(The character of %c has the value %dn, +,(int) +);System.out.printf(The character of %c has the value %dn, /,(int) /);/ 2.30System.out.print(n习题2.30答案n);System.out.print(n 查看n4n);System.out.printf(The character of %d divided into the value %d %d %d %d %d,n4, (n4 - n4 % 10000) / 10000),(n4 % 10000 - n4 % 10000 % 1000) / 1000),(n4 % 1000 - n4 % 100) / 100,(n4 % 100 - n4 % 10) / 10, n4 % 10);/2.31System.out.print(n习题2.30答案n);System.out.printf(%st%st%sn,number,square,cube);System.out.printf(%st%st%sn,0,0,0);System.out.printf(%st%st%sn,1,1,1);System.out.printf(%st%st%sn,2,4,8);System.out.printf(%st%st%sn,3,9,27);System.out.printf(%st%st%sn,4,16,64);System.out.printf(%st%st%sn,5,25,1