复数的四则运算.doc

#includetypedef struct double real;double img;ComplexNumber;void CreateComplexNumber(ComplexNumber *c,double a,double b) c-real=a; c-img=b; return;void AddComplexNumber(ComplexNumber *c,ComplexNumber c1,ComplexNumber c2)c-real=c1.real+c2.real;c-img=c1.img+c2.img;return;void SubComplexNumber(ComplexNumber *c,ComplexNumber c1,ComplexNumber c2) c-real=c1.real-c2.real; c-img=c1.img-c2.img; return;void MultiComplexNumber(ComplexNumber *c,ComplexNumber c1,ComplexNumber c2)c-real=c1.real*c2.real-c1.img*c2.img;c-img=c1.real*c2.img+c1.img*c2.real;return;void ConComplexNumber(ComplexNumber *c,ComplexNumber c1)c-real=c1.real;c-img=c1.img*(-1);return;voidPrint(ComplexNumber *c)if(c-real=0.0&c-img=0.0)printf(0n);if(c-real=0.0&c-img!=0.0)printf(i%5.2lfn,c-img);if(c-real!=0.0&c-img=0.0)printf(%5.2lfn,c-real);if(c-real!=0.0&c-img!=0.0)printf(%5.2lf+i%5.2lfn,c-real,c-img);void Print_real(ComplexNumber *c)printf(该复数的实部是：%5.2lfn,c-real);void Print_img(ComplexNumber *c)printf(该复数的虚部是：i%5.2lfn,c-img);void main() double a,b,c,d; ComplexNumber c1,c2,add,sub,multi,con; printf(请分别输入两个复数的实部和虚部：n); scanf(%lf%lf%lf%lf,&a,&b,&c,&d); CreateComplexNumber(&c1,a,b); Print(&c1); Print_real(&c1); Print_img(&c1); CreateComplexNumber(&c2,c,d); Print(&c2); Print_real(&c2); Print_img(&c2); AddComplexNumber(&add,c1,c2); printf(两复数的和为:); Print(&add); SubComplexNumber(&sub,c1,c2); printf(两复数的差为:); Print(&sub); MultiComplexNumber(&multi,c1,c2); printf(两复数的积为:); Print(&multi); ConComplexNumber(&con,c1); printf(该复数的共轭复