30g惯性力计算.doc

Average Front Door O/S Handle Lever Return Spring Load : MO/S=0.367N.m=367N.mm Average Front Door Pawl Return Spring Moment : MP/S =0.120N.m =120N.mm Average Front Door Return Spring Force : P=7.15N a=30g(m/s2) W1=0.035kg W2=0.0135kg W3=0.010kg W4=0.008kg W5=0.020kg L1=5mm L2=40mm L3=95mm L4=8mm L5=65mm L6=20mm L7=7mm L8=28mm L9=20mm L10=18mm L11=1.5mm L15=30mm F= ma = W/g X 30g = 30W(kg) = 294.3W(N) F1= 294.3W1 = 294.3 X 0.0351 = 10.33(N) F2= 294.3W2xL2/L3=294.3x0.0135x40/95=1.67(N) Mopen=F1L1=51.65Nmm Mclose=F2L4+Mo/s=1.678+367=380.36Nmm Mopen-Mclose=51.65-380.36=-328.71Nmm Force tending to open Latch is considered as zero because it can not be transmited to Pawl F3= 294.3W3x(L5-L15)/L5=294.3x0.010x(65-30)=1.58(N) F4= 294.3W2-F2 =294.3x0.0135-1.67 = 2.3(N) F5= 294.3W5 =294.3x0.020 = 5.89(N) F6= 294.3W4 =294.3x0.008 = 2.35(N) F7= (F3xL6+F6xL7+F4xL6-PxL8)/L9=(1.58x20+2.35x7+2.3x20-7.15x28)/20=-5.31(N) ;System is not affected by F7. (F7 0 , F7 = 0) Force(F7) tending to open Latch is considered as zero because it can not be transmited to Pawl. Mopen=F7xL10+F6xL11=0x18+2.35x1.5=3.53(N.mm). Mclose=MP/S =0.120N.m =120N.mm Mopen -Mclose = 3.53-120=-116.47(N.mm)Average Front Door I/S Handle Return Spring Moment : MI/S=0.364N.m =364N.mm Average Front Door Return Sprign Force : P=7.15N a=30g(m/s2)W6=0.020kg W7=0.010kg W8=0.005kg L12=15mm L13=20mm L14=1.5mm L16=22mm L17=5mm L8=28mm L19=24mm L18=15mm F= ma = W/g X 30g = 30W(kg) = 294.3W(N) F8= 294.3W6 = 294.3 X 0.020 = 5.89(N) F9= 294.3W7 = 294.3 X 0.010 = 2.94(N) F6=( F8 X L12-F9XL14- MI/S)/L12= (5.89X15-2.94X1.5-364)/15=-18.67(N) F10=294.3W8 = 294.3 X 0.005 = 1.47(N) F11=(F6XL16+F10XL17)/L18 =(-18.67X22+1.47X5)/15 = -26.89(N) ;System is not affected by F11. (F11 0 , F11 = 0) Force(F7) tending to open Latch is considered as zero because it can not be transmited to Pawl. Mopen=(F11xL19-PxL8)/L9xL10=(0x24-7.15