上机考试复习题.doc

上机考试复习题一、填空题 1、建立一个对象数组，内放5个学生的数据（学号、成绩），用指针指向首元素，输出第1、3、5个学生的数据。#include using namespace std;class Studentpublic: 【1】1、Student(int n, float s)num=n; score=s; void display();private: int num; float score;void Student:display()【2】2、coutnum: num;cout”score:”score;int main()Student stud5= Student(101,78.5),Student(102,85.5),Student(103,98.5), Student(104,100.0),Student(105,95.5); 【3】3、Student *p=stud;for(int i=0;idisplay();return 0;2、定义一个复数类Complex，重载运算符“-”使之能用于复数的减。运算符重载函数作为Complex类的成员函数。编写程序，分别求两个复数之差。#include using namespace std;class Complexpublic: Complex()real=0;imag=0; Complex(double r,double i)real=r;imag=i;Complex operator-(Complex &c2); void display();private: double real; double imag;【6】6、Complex Complex:operator-(Complex &c2)Complex c; 【7】7、c.real=real-c2.real; 【8】8、c.imag=imag-c2.imag;return c;void Complex:display()cout(real,imagi)endl;int main()Complex c1(1,2),c2(-6,7),c3;【9】9、c3=c1-c2;coutc1-c2=;【10】10、c3.display();return 0;3、建立一个对象数组，内放5个学生的数据(学号、成绩)，设立一个函数max，用指向对象的指针作函数参数，在max函数中找出5个学生中成绩最高者，并输出其学号。#include using namespace std;class Studentpublic: Student(int n,float s):num(n),score(s) int num; float score;void main()Student stud5= Student(101,78.5),Student(102,85.5),Student(103,98.5), Student(104,100.0),Student(105,95.5); 【11】11、void max(Student* ); 【12】12、Student *p=&stud0; 【13】13、max(p); void max(Student *arr) float max_score=arr0.score;int k=0;for(int i=1;imax_score) max_score=arri.score;k=i;【15】15、coutarrk.num max_scoreendl;4、有两个矩阵a和b，均为2行3列。求两个矩阵之和。重载运算符“+”，使之能用于矩阵相加（如c=a+b）。#include class Matrix public: Matrix(); 【16】16、friend Matrix operator+(Matrix &,Matrix &); void input(); void display(); private: int mat23;Matrix:Matrix() for(int i=0;i2;i+) for(int j=0;j3;j+) 【17】17、matij=0;Matrix operator+(Matrix &a,Matrix &b) Matrix c;for(int i=0;i2;i+) for(int j=0;j3;j+) 【18】18、c.matij=a.matij+b.matij;return c; void Matrix:input() coutinput value of matrix:endl;for(int i=0;i2;i+) for(int j=0;jmatij;void Matrix:display() for (int i=0;i2;i+) for(int j=0;j3;j+) coutmatij ; coutendl;int main()Matrix a,b,c;a.input();b.input();coutendlMatrix a:endl;a.display();coutendlMatrix b:endl;b.display();【19】19、c=a+b;coutendlMatrix c = Matrix a + Matrix b :endl;【20】20、c.display();return 0;1、#include using namespace std; int main( ) int add(int x,int y); int a,b,c; cinab; c=add(a,b); couta+b=cendl; return 0; int add(int x,int y) int z;z=x+y;return(z);二、程序改错题1、#include using namespace std; int main( ) int add(int x,int y); int a,b,c; cinab; c=add(a,b); couta+b=cendl; return 0; int add(int x,int y) int z;z=x+y;return(z);#include using namespace std; class Time public:int hour; int minute; int sec; ;Time t; int main()void set_time(void) ; void show_time(void) ;set_time();show_time();void set_time(void) cint.hour; cint.minute; cint.sec;void show_time(void) coutt.hour:t.minute:t.secendl;3、#include#includeclass Pointpublic: double x,y; Point(double a,double b) x=a;y=b; friend double distance(Point a,Point b);double distance(Point a,Point b) double dist; dist=sqrt(a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y); return dist;void main()Point p1(2,2),p2(5,5);cout上述两点之间的距离:distance(p1,p2)endl;3、#include#includeclass Point double x,y; Point(double a,double b) x=a;y=b; friend double distance(Point a,Point b);double Point:distance(Point a,Point b) double dist; dist=sqrt(a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y); return dist;void main()Point p1(2,2),p2(5,5);cout上述两点之间的距离:p1. distance(p1,p2)endl;4、#include#includeusing namespace std; class Pixcelpublic: double x; double y;void set(double ix,double iy)x=ix;y=iy;double xoffset()return x;double yoffset()return y;double angle()return (180/3.14159)*atan2(y,x);double radius()return sqrt(x*x+y*y); ;void main()Pixcel p;double x,y;coutEnter x and y: xy;p.set(x,y);p.x+=8;p.y+=9;coutangle=p.angle() ,radius=p.radius() ,x offset=p.xoffset() ,y offset=p.yoffset()endl; 4、#includeusing namespace std;class Pixcelprotected: double x=0; double y=0;public: void set(double ix,double iy)x=ix;y=iy; double xoffset()return x; double yoffset()return y; double angle()return (180/3.14159)*atan2(y,x); double radius()return sqrt(x*x+y*y);void main() Pixcel p; double x,y; coutEnter x and y: xy; p.set(x,y); p.x+=8; p.y+=9; coutangle=p.angle() ,radius=p.radius() ,x offset=p.xoffset() ,y offset=p.yoffset()endl;三、编程题1、分别声明Teacher(教师)类和Cadre(干部)类，采用多重继承方式由这两个类派生出新类Teacher_Cadre(教师兼干部)类。要求：在两个基类中都包含姓名、年龄、性别、地址、电话等数据成员。在Teacher类中还包含数据成员title(职称)，在Cadre类中还包含数据成员post(职务)，在Teacher_Cadre类中还包含数据成员wages(工资)。对两个基类中的姓名、年龄、性别、地址、电话等数据成员用相同的名字，在引用这些数据成员时，指定作用域。在类体中声明成员函数，在类外定义成员函数。在派生类Teacher_Cadre的成员函数show中调用Teacher类中的display函数，输出姓名、年龄、性别、职称、地址、电话，然后再用cout语句输出职务与工资。（已给出主函数、Teacher(教师)类和Cadre(干部)类，将程序补充完整）#include#include using namespace std;class Teacherpublic: Teacher(string nam,int a,char s,string tit,string ad,string t); void display(); protected: string name; int age; char sex; string title; string addr; string tel;Teacher:Teacher(string nam,int a,char s,string tit,string ad,string t): name(nam),age(a),sex(s),title(tit),addr(ad),tel(t) void Teacher:display()coutname:nameendl; coutageageendl; coutsex:sexendl; couttitle:titleendl; coutaddress:addrendl; couttel:telendl; class Cadrepublic: Cadre(string nam,int a,char s,string p,string ad,string t); void display(); protected: string name; int age; char sex; string post; string addr; string tel;Cadre:Cadre(string nam,int a,char s,string p,string ad,string t): name(nam),age(a),sex(s),post(p),addr(ad),tel(t)void Cadre:display()coutname:nameendl; coutage:ageendl; coutsex:sexendl; coutpost:postendl; coutaddress:addrendl; couttel:telendl; class Teacher_Cadre /此处自己编写代码class Teacher_Cadre:public Teacher,public Cadre public: Teacher_Cadre(string nam,int a,char s,string tit,string p,string ad,string t,float w); void show( ); private: float wage; ;Teacher_Cadre:Teacher_Cadre(string nam,int a,char s,string t,string p,string ad,string tel,float w): Teacher(nam,a,s,t,ad,tel),Cadre(nam,a,s,p,ad,tel),wage(w) void Teacher_Cadre:show( ) Teacher:display(); coutpost:Cadre:postendl; coutwages:wageendl; /此处自己编写代码int main( )Teacher_Cadre te_ca(Wang-li,50,f,prof.,president,135 Beijing Road,Shanghai,(021)61234567,1534.5); te_ca.show( ); return 0;2、商店销售某一商品，每天公布统一的折扣(discount)。同时允许销售人员在销售时灵活掌握售价(price)，在此基础上，一次购10件以上者，还可以享受9.8折优惠。现已知当天3个销货员销售情况为：销货员号(num) 销货件数(quantity) 销货单价(price)101 5 23.5102 12 24.56103 100 21.5请编写程序，计算出当日此商品的总销售款sum以及每件商品的平均售价。要求用静态数据成员和静态成员函数。(提示：将折扣discount，总销售款sum和商品销售总件数n声明为静态数据成员，再定义静态成员函数average(求平均售价)和display(输出结果)。（已给出主函数、Product类，将程序补充完整）#include using namespace std;class Productpublic: Product(int n,int q,float p):num(n),quantity(q),price(p); void total(); static float average(); static void display(); private: int num; int quantity; float price; static float discount; static float sum; static int n;void Product:total() float rate=1.0; if(quantity10) rate=0.98*rate; sum=sum+quantity*price*rate*(1-discount); n=n+quantity; void Product:display() coutsumendl; coutaverage()endl; float Product:average() return(sum/n);float Product:discount=0.05;float Product:sum=0;int Product:n=0;/此处编写代码int main() Product Prod3= Product(101,5,23.5),Product(102,12,24.56),Product(103,100,21.5) ; for(int i=0;i3;i+) Prodi.total(); Product:display(); return 0;3、有两个矩阵a和b,均为2行3列。求两个矩阵之和。重载运算符“+”，使之能用于矩阵相加（如c=a+b）请把需要添加的部分补充完整。#include using namespace std;class Matrix public: Matrix(); friend Matrix operator+(Matrix &,Matrix &); void input(); void display(); private: int mat23; ;Matrix:Matrix() /补充完整Matrix operator+(Matrix &a,Matrix &b) /补充完整 void Matrix:input() coutinput value of matrix:endl; for(int i=0;i2;i+) for(int j=0;jmatij;void Matrix:display() for (int i=0;i2;i+) for(int j=0;j3;j+) coutmatij ; coutendl;int main()Matrix a,b,c; a.input(); b.input(); coutendlMatrix a:endl; a.display(); coutendlMatrix b:endl; b.display(); c=a+b; coutendlMatrix c = Matri