已阅读5页,还剩3页未读, 继续免费阅读
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
第二章p40(页码)1.(题号)Percentage Holding Period Return:= (44- 40 + 0.4)/40 x 100% = 11%2Percentage Holding Period Return:= (100,000 - 99500)/99500 x 100% = 0.50%3. Percentage Holding Period Return:= (1,000 - 975 + 60)/975 x 100% = 8.72%4.a. Expected Percentage Holding Period Return = (65 - 60 + 4)/60 x 100% = 15.0% b. Realized Percentage Holding Period Return = (75 - 60 + 4)/60 x 100% = 31.67% c. Realized Percentage Holding Period Return =(58 - 60 + 4)/60 x 100% = 3.33% d. Realized Percentage Holding Period Return = (50 - 60 + 4)/60 x 100% = -10.0% 5. Percentage Holding Period (HP) Return = (12,800 - 14,000)/14,000 x 100% = -8.57%第三章 p731. a. 50 days = Accounts Receivable/(1,600,000/365 days) 50 days = Accounts Receivable/4,383.56 Accounts Receivable = 219,178 b. Cost of sales = (1 - 0.35)(1,600,000) = 1,040,000 Inventory Turnover = Cost of Sales/Average Inventory Inventory Turnover =6 6 = 1,040,000/Average Inventory Average Inventory = 173,333 6. Forecasted Balance Sheet Cash 104,000Accounts receivable 1,096,000 Total current liabilities 1,200,000Inventory 1,200,000 Long term debt 2,800,000Total current assets 2,400,000 Total debt 4,000,000Net fixed assets 7,600,000 Stockholders equity 6,000,000Total assets 10,000,000 Total liabilities and 10,000,000 stockholders equity a. Profit margin on sales = 0.05 = 1,000,000/Sales Sales = 20,000,000 b. Total asset turnover = 2 = 20,000,000/Total assets Total assets = 10,000,000 c. Total debt to total assets = 0.4 = Total debt/10,000,000 Total debt = 4,000,000 d. Current liabilities to stockholders equity = 0.2 = Current liabilities/6,000,000 Current liabilities = 1,200,000 e. Current ratio = 2 = Current assets/1,200,000 Current assets = 2,400,000 f. Fixed assets = Total assets minus current assets = 10,000,000 - 2,400,000 = 7,600,000 g. Quick ratio = 1 = (2,400,000 - Inventories)/1,200,000 Inventories = 1,200,000 h. Average collection period = 20 days = Accounts receivable/(20,000,000/365) Accounts receivable = 1,096,000 (rounded to the nearest 1,000) i. Cash = Current assets minus accounts receivable minus inventories Cash = 2,400,000 - 1,096,000 - 1,200,000 = 104,000第四章 P931. ATCF = EAT + Depreciation + Deferred taxes = 650,000 + 400,000 + 100,000 = 1,150,000 3. Midland Manufacturing CorporationStatement of Cash Flows For the Year Ended December 31, 2002 ( millions) Cash Flows from Operating Activities: Net income 8.3 Adjustments to reconcile net income to net cash provided from operating activities Depreciation 9.5 (Increase) decrease in current assets or liabilities Accounts receivable (0.3) Inventories (0.7) Accounts payable 1.5 Other current liabilities 2.2 Increase (decrease) in deferred taxes 0.2 Total adjustments 12.4 Net cash provided from (used by) operating activities 20.7 Cash Flows from Investing Activities Proceeds from sale of facilities or equipment 1.0 Capital expenditures (115.0 - 80.7 + 1.0) (35.3) Net cash used by investing activities (34.3) Cash Flows from Financing Activities Proceeds from issuance of long-term debt 15.0 Repayments of long-term debt (2.0) Dividends paid (3.5) Net cash provided from (used by) financing activities 9.5 Net Increase (Decrease) in Cash (4.1)Cash - Beginning of Year 4.9Cash - End of Year 0.8第五章 P1241. a. FV3 = 1,000(FVIF0.06,3) = 1,000(1.191) = 1,191 b. FV5 = 1,000(FVIF0.06,5) = 1,000(1.338) = 1,338 c. FV10 = 1,000(FVIF0.06,10) = 1,000(1.791) = 1,791 2. a. Present value of 5,000 today = 5,000 b. Present value of 15,000 received in 5 years at 9%: PV0 = 15,000(PVIF0.09,5) = 15,000 (0.650) = 9,750 c. Present value of a 15 year, 1,000 annuity at 9%: PVAN0 = 1,000 (PVIFA0.09,15) = 1,000(8.061) = 8,061 15 a. FV3 = 10,000(FVIF0.04,6) = 10,000(1.265) = 12650b.FV3 = 10,000(FVIF0.02,12) = 10,000(1.268) = 12680c.FV3 = 10,000(FVIF0.006,36) = 10,000(1.270) = 1270018.PV0 = 20,000(PVIF0.15,1) + 30,000(PVIF0.15,2) + 15,000(PVIF0.15,3) PV0 = 20,000(0.870) + 30,000(0.756) + 15,000(0.658) PV0 = 49,950 49,950 = PMT(PVIFA0.15,3) = PMT(2.283) PMT = 21,879第六章 P16711 . a. Security Beta P 0.8(0.10)(0.08)/(0.8)2 = 1.00 Q 0.6(0.20)(0.08)/(0.8)2 = 1.50 R 0.4(0.15)(0.08)/(0.8)2 = 0.75b. Security Expected Return Beta Required Return P 12% 1.00 7% + 8.8 (1.00) = 15.8% Q 18 1.50 7% + 8.8 (1.50) = 20.2% R 15 0.75 7% + 8.8 (0.75) = 13.6% 第七章P188 1. a. Po = I/kd I = 1000 X0 .04 = 40 kd =0 .04Po = 40/0.04 = 1000 b. I = 40 kd = 0.05Po = 40/0.05 = 800 c. I = 40 kd = 0.06 Po = 40/0.06 = 666.673. a. Po = I/(1 + kd)t + M/(1 + kd)n t=1 I =0 .0875 X 1000 = 87.50 kd = 0.07 M = 1000 n = 12 years (2012 - 2004)=12 Po = 87.50/(1 + 0.07)t + 1000/(1 + 0.07)12 = 87.50(PVIFA0.07,12) + 1000 (PVIF0.07,12) = 87.50(7.943) + 1000 (0.444) = 1139b. I = 87.50 kd =0 .09 M = 1000 n = 12 Po = 87.50/(1 +0 .09)t + 1000/(1 + 0.09)12 = 87.50 (PVIFA0.09,12) + 1000(PVIF0.09,12) = 87.50(7.161) + 1000 (0.356) = 983 c. I = 87.50 kd =0 .11 M = 1000 n = 12 Po = 87.50/(1 + 0.11)t + 1000/(1 + 0.11)12 = 87.50 (PVIFA0.11,12) + 1000(PVIF0.11,12) = 87.50(6.492) + 1000 (0.286) = 854 d. I =0 .0875(1000)/2 = 43.75 M = 1000 kd = 0.08/2 = 0.04; n = 12 X 2 = 24 Po = 43.75/(1 + 0.04)t + 1000/(1 + 0.04)24 = 43.75(PVIFA0.04,24) + 1000(PVIF0.04,24) = 43.75(15.247) + 1000(0.390) = 1057第八章 P2051 Present Value of First 6-Years Dividends:Do(1 + g1)t/(1 + ke)t; Do = 5.00; g1 =0 .07; ke =0 .12 Year Dividend Interest Factor Present Valuet Dt = 5.00(1 + 0.07)t PVIF.12,t Dt x PVIF.12,t 1 5.00(1 + .07)1 = 5.35 0.893 4.7782 5.00(1 + 0.07)2 = 5.725 0 .797 4.5633 5.00(1 +0 .07)3 = 6.125 0 .712 4.3614 5.00(1 +0 .07)4 =6.554 0 .636 4.1685 5.00(1 +0 .07)5 = 7.013 0.567 3.9766 5.00(1 +0 .07)6 = 7.504 0.507 3.805 PV (First 6-Years Dividends) = 25.651alue of Stock at End of Year 6:P6 = D7/(ke - g2) g2 = 0.00D7 = D6(1 + g2) = 7.504(1 + 0.00) = 7.504P6 = 7.504/(0.12 - 0.00) = 62.533 Present Value of P6: PV(P6) = P6/(1 + ke)6 = 62.533/(1 +0 .12)6= 62.533 x PVIF0.12,6= 62.533 X 0.507= 31.704 Value of Common Stock (Po): Po = PV (First 6-Years Dividends) + PV(P6) = 25.651 + 31.704 = 57.36 第九章P2291.a.straight-lineafter-tax operating cash flow=(200-130+15)x60%+15=48accelerated depreciationafter-tax operating cash flow=(200-130+25)x60%+25=52 2. Annual depreciation amount = Installed cost / Number of years over which the asset is depreciate
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 池州市人民医院夹板固定技术专项技能考核
- 宣城市人民医院急性脑梗死静脉溶栓决策能力考核
- 南京市中医院鉴别诊断思维能力考核
- 徐州市中医院国际会议发言能力考核
- 综合养老服务中心人性化设计与实施方案
- 内科护理模考试题(附答案)
- 南京市人民医院功能检查科主治医师晋升考核
- 淄博市中医院穿脱防护用品流程技能资格认证
- 宜春市中医院烧伤心理康复干预考核
- 宣城市中医院血管通路并发症处理考核
- 2025北京经济技术开发区城市运行局招聘职能部门安全生产专职安全员5人考试模拟试题及答案解析
- 2025陕西延安市安塞区总工会招聘工会社会工作者8人考试参考试题及答案解析
- 湖南省部分校2025-2026学年高二上学期10月联考语文试题(含答案)(解析版)
- 董明珠课件教学课件
- Unit2课时7 Reading for Writing-仁爱科普版八年级《英语》上册教学课件
- 游戏文化与传统文化的融合-游戏与传统文化
- 机场停机坪地坪施工方案
- 2025年广东省中考英语试卷深度评析及2026年备考策略
- (2025)全市党员干部党规党纪廉政知识竞赛题库及答案
- 定额〔2025〕1号文-关于发布2018版电力建设工程概预算定额2024年度价格水平调整的通知
- 无底薪业务员协议书范本
评论
0/150
提交评论