C++第9次作业.doc

实验九: 多态性（一）1、 定义计数器Counter类，对其重载运算符 + 。实验代码：#include class counterprivate:int n;public:counter( ) n=0;counter(int i) n=i;counter operator+(counter c)counter temp;temp.n=n+c.n;return temp; void disp( )coutn=nendl;void main() counter c1(15),c2(10),c3; c3=c1+c2; c1.disp(); c2.disp(); c3.disp();实验结果：2、 定义一个基类BaseClass，从它派生出类DerivedClass，BaseClass有成员函数fn1()、fn2()，DerivedClass也有成员函数fn1()、fn2()，在主程序中定义一个DerivedClass的对象，分别用DerivedClass的对象以及BaseClass和DerivedClass的指针来调用fn1()、fn2()，观察运行结果。实验代码：#include class BaseClasspublic: void fn1(); void fn2(); ; void BaseClass:fn1()cout 调用基类的函数fn1() endl; void BaseClass:fn2()cout 调用基类的函数fn2() endl; class DerivedClass : public BaseClass public:void fn1(); void fn2(); ; void DerivedClass:fn1() cout 调用派生类的函数fn1() endl; void DerivedClass:fn2() cout 调用派生类的函数fn2() fn1(); pBaseClass-fn2(); pDerivedClass-fn1(); pDerivedClass-fn2(); 实验结果：3、 实现重载函数Double(x)，返回值为输入参数的两倍；参数分别为整型、长整型、浮点型、双精度型，返回值类型与参数一样。实验代码：#includeusing namespace std;int Double(int a)return 2.0*a;long int Double(long int a)return 2*a;float Double(float a)return 2.0*a;double Double(double a)return 2.00000*a;void main()int m;coutm;cout它的两倍是Double(m)endl;long int p;coutp;cout它的两倍是Double(p)endl;float r;coutr;cout它的两倍是Double(r)endl;double n;coutn;cout它的两倍是Double(n)endl;实验结果：4、 定义一个复数类，重载“+”；“-”；“*”，“/”运算符实现复数的四则运算。实验代码：#include class complex private:double real; double imag; public:complex() real=imag=0; complex(double rpart,double ipart) real=rpart;imag=ipart;complex operator+(const complex &com) complex temp;temp.real=real+com.real;temp.imag=imag+com.imag;return temp;complex operator-(const complex &com) complex temp;temp.real=real-com.real;temp.imag=imag-com.imag;return temp;complex operator*(const complex &com) complex temp;temp.real=real*com.real-imag*com.imag;temp.imag=real*com.imag+imag*com.real;return temp;complex operator/(const complex &com) complex temp;temp.real=(real*com.real+imag*com.imag)/(com.real*com.real+com.imag*com.imag);temp.imag=(imag*com.real-real*com.imag)/(com.real*com.real+com.imag*com.imag);return temp;void display() if(imag=0)cout(real+imagi);elsecout(realimagi);int main(void)double a,b,c,d;coutabcd;complex n1(a,b),n2(c,d);cout两个复数值为：;coutA=; n1.display();cout B=;n2.display(); coutendl;coutendlendl两个复数的加法：endl;complex result1;result1=n1+n2; n1.display();cout+;n2.display();cout=;result1.display(); coutendlendl两个复数的减法：endl;complex result2;result2=n1-n2; n1.display();cout-;n2.display();cout=;result2.display(); coutendlendl两个复数的乘法：endl;complex result3;result3=n1*n2; n1.display();cout;n2.display();cout=;result3.display(); coutendlendl两个复数的除法：endl; if(c=0&d=0)