MatLab与信息处理实验三.doc

MatLab与信息处理实验三西华师大物电学院学生信息：班级：7 学号：200909440736 姓名：杨柳 注意: 1,请按要求作题,填写求解的MatLab语句和输出的答案,并保存文件.2,仔细填写 “学生信息”.3,把此word文档的文件名更名为你的 “系别班级姓名”.上传到教师上相应的班级的文件夹中。例： “MatLab%.doc” - “0901敖兵.doc” 1、 已知各离散序列的波形如图所示，试用Matlab求下列卷积和，并绘出卷积和序列的时域波形。（1）（2）(3) 1. n1=-2:3; f1=0 1 2 1 0 0; n2=-3:3; f2=0 1 1 1 1 1 0; n3=-2:3; f3=0 0 3 2 1 0; n4=-1:4; f4=0 1 -1 1 -1 0; x12,n12=gghconv(f1,f2,n1,n2)x = 0 0 1 3 4 4 4 3 1 0 0 0n = -5 -4 -3 -2 -1 0 1 2 3 4 5 6x12 = 0 0 1 3 4 4 4 3 1 0 0 0n12 = -5 -4 -3 -2 -1 0 1 2 3 4 5 6 2. figure(2) x34,n34=gghconv(f3,f4,n3,n4)x = 0 0 0 3 -1 2 -2 -1 -1 0 0n = -3 -2 -1 0 1 2 3 4 5 6 7x34 = 0 0 0 3 -1 2 -2 -1 -1 0 0n34 = -3 -2 -1 0 1 2 3 4 5 6 73. figure(3) f5,n5=jxl(f2,f1,n2,n1)f5 = 0 1 0 -1 0 1 0n5 = -3 -2 -1 0 1 2 3 x53,n53=gghconv(f5,f3,n5,n3)x = 0 0 0 3 2 -2 -2 2 2 1 0 0n = -5 -4 -3 -2 -1 0 1 2 3 4 5 6x53 = 0 0 0 3 2 -2 -2 2 2 1 0 0n53 =-5 -4 -3 -2 -1 0 1 2 3 4 5 62、 已知各连续信号的波形如下图所示，试用解析方法求下列卷积，并用Matlab绘出卷积信号波形，将其与解析计算结果进行比较(2)1. t1=-1:0.01:4; f1=Heavisider(t1)-Heavisider(t1-2); t2=t1; f2=Heavisider(t2-1)-Heavisider(t2-3); t3=t1; f3=0.5*t3.*(Heavisider(t3)-Heavisider(t3-2); t4=t2; f4=(0.5*t4+1).*(Heavisider(t4+2)-Heavisider(t4)+(-0.5*t4+1).*(Heavisider(t4)-Heavisider(t4-2); t12,f12=gggfconv(f1,f2,t1,t2)d: 0.01 t34,f34=gggfconv(f3,f4,t3,t4)d: 0.013、 用MATLAB 绘出下列信号的卷积积分f1 (t ) * f2 (t) 的时域波形。1. t1=-5:0.01:5; t2=t1; f1=t1.*Heavisider(t1); f2=Heaviside(t2); t12,f12=gggfconv(f1,f2,t1,t2)d: 0.012. t1=-5:0.01:5; t2=t1; f1=Heavisider(t1)-Heavisider(t1-4); f2=sin(pi*t2).*Heavisider(t2); t12,f12=gggfconv(f1,f2,t1,t2)d: 0.014、 已知描述系统的微分方程如下，试用MATLAB 求系统在010 秒范围内冲激响应和阶跃响应的数值解，并绘出系统冲激响应和阶跃响应的时域波形。1. a=1 3 2; b=1; subplot(2,1,1); impulse(b,a,10) y=impulse(b,a,0:10)y = 0 0.2325 0.1170 0.0473 0.0180 0.0067 0.0025 0.0009 0.0003 0.00010.0000 subplot(2,1,2); step(b,a,10) y=step(b,a,0:10)y = 0 0.1998 0.3738 0.4515 0.4819 0.4933 0.4975 0.4991 0.4997 0.4999 0.50002. a=1 2 2; b=1 0; subplot(2,1,1); impulse(b,a,10) y=impulse(b,a,0:10)y = 1.0000 -0.1108 -0.1794 -0.0563 0.0019 0.0084 0.0031 0.0001 -0.0004 -0.0002 -0.0000 subplot(2,1,2); step(b,a,10) y=step(b,a,0:10)y = 0 0.3096 0.1231 0.0070 -0.0139 -0.0065 -0.0007 0.0006 0.0003 0.0001 -0.00005、 已知描述离散系统的差分方程如下，试用MATLAB 求出系统020 时间样点的单位序列响应和阶跃响应的数值解，并绘出其序列波形图。1. a=1 2; b=0 1; subplot(2,1,1); impz(b,a,0:20); y= impz(b,a,0:20)y = 0 1 -2 4 -8 16 -32 64 -128 256 -512 1024 -2048 4096 -8192 16384 -32768 65536 -131072 262144 -524288 subplot(2,1,2); n=0:20; x=Heavisiden(n); y=filter(b,a,x)y = Columns 1 through 13 0 1 -1 3 -5 11 -21 43 -85 171 -341 683 -1365 Columns 14 through 21 2731 -5461 10923 -21845 43691 -87381 174763 -349525 stem(n,y,filled)2. a=1 0 -1; b=1; subplot(2,1,1); impz(b,a,0:20); y= impz(b,a,0:20)y = 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 subplot(2,1,2); n=0:20;