推箱子-电信081-陈剑-3080432008.doc

推箱子实验报告1、实验目的运用Java有关知识更进一步掌握编程方法；了解一些小游戏的相关代码，2、设计思路 在这个游戏的设计中，牵涉到图形界面的显示与更新、数据的收集与更新，并且在这个游戏的开发中，还要应用类的继承机制以及一些设计模式。玩家和箱子的正确移动，包括对撞墙的检测；当所有的箱子都到达目的地的时候，就提示“恭喜过关”；家可以用键盘的“上下左右”来控制前进的方向；整个代码的思路是：把游戏界面看成一个二维的数组，然后用一个布尔型的数组boolean a去填充它。3、设计方法 / 初始化界面元素 public GamePanel()加入提示菜单public static void main(String args) GameFrame frame = new GameFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.show(); JOptionPane.showMessageDialog(null, 红色方块代表玩家n把紫色箱子推到蓝框中过关n方向键控制方向n不能返回到上一步); 要给方块绘制游戏背景,玩家和箱子.，绘制墙壁，绘制目的地.，/ 定义箱子，玩家和目的地的初始位置 int x = 5; int y = 8; man = new Node(x, y); axy = true; / 定义游戏中的箱子的位置,并置为TRUE; b = new Node4; box = new Node(10, 9); a109 = true; b0 = box; box1 = new Node(6, 7); a67 = true; b1 = box1; box2 = new Node(11, 8); a118 = true; b2 = box2; box3 = new Node(8, 8); a88 = true; b3 = box3; / 定义墙和目的地. createWall(); target = new Node4; target0 = new Node(7, 9); target1 = new Node(6, 9); target2 = new Node(7, 10); target3 = new Node(6, 10); public void move(int d1, int d2) aman.xman.y = false; man.x += d1; man.y += d2;/ 如果所有的箱子到位,则游戏结束 public void isArrive(Node n) for (int i = 0; i target.length; i+) if (targeti.x = n.x & targeti.y = n.y) list.add(targeti); else if (targeti.x = man.x & targeti.y = man.y) list.remove(targeti); if (list.size() = target.length) end = true; 4、流程图游戏开始提示 游戏结束游戏过程5、实验过程 实验开始箱子撞墙游戏过关6、相关代码import javax.swing.*;import java.awt.*;import java.awt.event.*;import java.util.*;import java.awt.geom.*;public class PushBox public static void main(String args) GameFrame frame = new GameFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.show(); JOptionPane.showMessageDialog(null, 红色方块代表玩家n把紫色箱子推到蓝框中过关n方向键控制方向n不能返回到上一步); class GameFrame extends JFrame static int num; public GameFrame() setSize(400, 400); Container c = getContentPane(); GamePanel panel1 = new GamePanel(); c.add(panel1); class GamePanel_2 extends JPanel public GamePanel_2() this.setBackground(Color.BLACK); class GamePanel extends JPanel implements KeyListener int width = 400; int height = 400; Box b; Node man; Node box; Node target; int d = 1;/ 移动的步长 int sideX = 25; int sideY = 25; GameFrame frame; ArrayList wallList; / 初始化界面元素 public GamePanel() this.setBackground(Color.WHITE); b = new Box(this, width / sideX, width / sideY); this.man = b.man; this.box = b.box; this.target = b.target; this.wallList = b.wallList; this.setFocusable(true); this.addKeyListener(this); public void paintComponent(Graphics g) super.paintComponent(g); Graphics2D g2 = (Graphics2D) g; / 绘制游戏背景,玩家和箱子. g2.setColor(Color.white); g2.fillRect(0, 0, width, height); g2.setColor(Color.RED); draw(g2, man); g2.setColor(Color.MAGENTA); draw(g2, box); draw(g2, b.box1); draw(g2, b.box2); draw(g2, b.box3); / 绘制墙壁 g2.setColor(Color.darkGray); for (int i = 0; i wallList.size(); i+) Node n = (Node) wallList.get(i); draw(g2, n); / 绘制目的地. g2.setColor(Color.blue); for (int i = 0; i target.length; i+) g2.drawRect(targeti.x * sideX, targeti.y * sideY, sideX - 1, sideY - 1); Ellipse2D e = new Ellipse2D.Double(targeti.x * sideX, targeti.y * sideY, sideX - 1, sideY - 1); g2.draw(e); public void keyPressed(KeyEvent e) int keycode = e.getKeyCode(); if (keycode = KeyEvent.VK_UP) Box.direction = 1;/ 要先确定方向再移动 b.move(0, -d); else if (keycode = KeyEvent.VK_RIGHT) Box.direction = 2; b.move(d, 0); else if (keycode = KeyEvent.VK_DOWN) Box.direction = 3; b.move(0, d); else if (keycode = KeyEvent.VK_LEFT) Box.direction = 4; b.move(-d, 0); public void keyReleased(KeyEvent e) public void keyTyped(KeyEvent e) public void draw(Graphics2D g, Node n) g.fillRect(n.x * sideX, n.y * sideY, sideX - 1, sideY - 1); class Node int x; int y; public Node(int x, int y) this.x = x; this.y = y; class Box boolean end = false; static int count = 0; int maxX; int maxY; boolean a; Node man; Node target; Node box; Node box1; Node box2; Node box3; Node wall; Node b; GamePanel panel; / 当一个箱子推到目的时,list储存目的地节点. ArrayList list = new ArrayList(); / 储存墙. ArrayList wallList = new ArrayList(); public static int left = 4; public static int up = 1; public static int right = 2; public static int down = 3; public static int direction = 0; / 在BOX的构造函数中，用布尔型的二维数组填充游戏画面,同时，定义玩家，箱子和目的地。 public Box(GamePanel p, int maxX, int maxY) panel = p; this.maxX = maxX; this.maxY = maxY; a = new booleanmaxXmaxY; for (int i = 0; i maxX; i+) for (int j = 0; j maxY; j+) aij = false; / 定义箱子，玩家和目的地的初始位置 int x = 5; int y = 8; man = new Node(x, y); axy = true; / 定义游戏中的箱子的位置,并置为TRUE; b = new Node4; box = new Node(10, 9); a109 = true; b0 = box; box1 = new Node(6, 7); a67 = true; b1 = box1; box2 = new Node(11, 8); a118 = true; b2 = box2; box3 = new Node(8, 8); a88 = true; b3 = box3; / 定义墙和目的地. createWall(); target = new Node4; target0 = new Node(7, 9); target1 = new Node(6, 9); target2 = new Node(7, 10); target3 = new Node(6, 10); public void move(int d1, int d2) aman.xman.y = false; man.x += d1; man.y += d2; / 如果玩家遇到墙,则不能前进;否则,推动箱子. if (aman.xman.y) if (isOutofwall() moveDisable(man, d1, d2); else for (int i = 0; i b.length; i+) if (man.x = bi.x & man.y = bi.y) bi.x += d1; bi.y += d2; / 如果箱子全部推到位,则游戏结束 isArrive(bi); / 利用一个IF判断箱子是否重叠,如果重叠,则不能前进; if (abi.xbi.y) moveDisable(bi, man, d1, d2); else / 一定要将箱子的位置置为true,不然箱子移动一次以后就不再移动. abi.xbi.y = true; panel.repaint(); if (end) JOptionPane.showMessageDialog(null, 恭喜过关); System.exit(0); / 生成游戏地图 public void createWall() for (int i = 5; i 12; i+) Node walls = new Node(i, 5); wallList.add(walls); for (int i = 11; i 4; i-) Node walls = new Node(i, 11); wallList.add(walls); wallList.add(new Node(5, 10); wallList.add(new Node(4, 10); wallList.add(new Node(4, 9); wallList.add(new Node(4, 8); wallList.add(new Node(4, 8); wallList.add(new Node(4, 7); wallList.add(new Node(5, 7); wallList.add(new Node(5, 6); wallList.add(new Node(7, 7); wallList.add(new Node(8, 7); wallList.add(new Node(9, 7); wallList.add(new Node(8, 9); wallList.add(new Node(8, 10); / 将墙壁的对象置为true for (int i = 0; i wallList.size(); i+) Node n = (Node) wallList.get(i); an.xn.y = true; / 当撞到墙时,玩家不能前进 public void moveDisable(Node n, int d1, int d2) switch (direction) case 4: n.x -= d1; break; case 1: n.y -= d2; break; case 2: n.x -= d1; break; case 3: n.y -= d2; break; / 用来使两个箱子不重叠 public void moveDisable(Node n1, Node n2,