最好的Java俄罗斯方块源代码.pdf.doc

import java.awt.Color; import java.awt.Graphics;import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.awt.event.KeyEvent; import java.awt.event.KeyListener; import java.util.Random;import javax.swing.JFrame; import javax.swing.JMenu; import javax.swing.JMenuBar; import javax.swing.JMenuItem; import javax.swing.JOptionPane; import javax.swing.JPanel; import javax.swing.Timer;public class myblock extends JFrame private static final long serialVersionUID = 1L; public static void main(String args)final JFrame frame = new JFrame(俄罗斯方块。); final Tetrisblok a = new Tetrisblok();frame.addKeyListener(a);frame.add(a);final Timer timer = new Timer(400, a.new TimerListener(); timer.start();JMenuBar menu = new JMenuBar(); frame.setJMenuBar(menu); /定义游戏菜单项JMenu gameMenu = new JMenu(游戏（G）); JMenuItem newitem = new JMenuItem(新游戏（N）); gameMenu.add(newitem);final JMenuItem pauseitem = new JMenuItem(暂停（P）); gameMenu.add(pauseitem);JMenuItem contitem = new JMenuItem(继续（c）); gameMenu.add(contitem);JMenuItem exititem = new JMenuItem(退出（E）); gameMenu.add(exititem); /添加监听器来实现游戏菜单上的各个菜单项的功能,采用匿名内部类 /新游戏菜单项的功能实现newitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)a.newmap();a.drawwall(); a.score = 0; a.x=4; a.y=-1;a.blockType=a.ran.nextInt(7); a.turnState=a.ran.nextInt(4); a.nextb=a.ran.nextInt(7); a.nextt=a.ran.nextInt(4);); /暂停菜单项的功能实现pauseitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.stop(); pauseitem.setEnabled(false);); /继续菜单项的功能实现contitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.start(); pauseitem.setEnabled(true);); /退出菜单项的功能实现exititem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.stop();Object options = 是的，我要退出, 不好意思，点错了 ; int option = JOptionPane.showOptionDialog(null, 您确定要退出吗？,退出提 示.,JOptionPane.OK_CANCEL_OPTION,JOptionPane.WARNING_MESSAGE,null,options, options0); if(option = JOptionPane.OK_OPTION) System.exit(0);timer.start();); /定义帮助菜单项JMenu helpMenu = new JMenu(帮助（H）);JMenuItem aboutitem = new JMenuItem(关于游戏（G）); helpMenu.add(aboutitem);JMenuItem writeitem = new JMenuItem(关于作者（W）); helpMenu.add(writeitem);helpMenu.addSeparator();JMenuItem adviitem = new JMenuItem(游戏忠告（A）); helpMenu.add(adviitem);/添加监听器来实现帮助菜单上的各个菜单项的功能,采用匿名内部类 /关于游戏菜单项的功能实现aboutitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.stop(); JOptionPane.showMessageDialog(frame,本游戏由孤独的野狼制作！n如需要源代码，随时欢迎联系作者！n +作者邮箱：nQQ号：2442701497n本游戏功能基本上是齐全的！n +并新增了“暂停”、“重新开始”等功能 .n希望您喜欢！n + 如有任何疑问及改善意见，随时欢迎指出。n我们将尽最大的努力满足您的需求！n +最后谢谢您的使用！n版权所有，请勿侵权！,关于游 戏.,JOptionPane.INFORMATION_MESSAGE);timer.start();); /关于作者菜单项的功能实现writeitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.stop(); JOptionPane.showMessageDialog(frame,作者：孤独的野狼n性别：男n籍贯：湖南邵阳n出生日：1990年11月9日n + 本科院校：上海应用技术学院n现居地：上海n自我介绍：不帅也不丑n偶像：爱因斯坦n +最喜欢的歌手：刀郎n最向往的地方：北京n座右铭：疯狂源自梦想n + 勤奋铸就辉煌n最喜欢的话：我愿变成一座石桥，受五百年风吹，五百年雨打，n +五百年日晒，只求你从上面走过.n +梦想：天地有多大，梦有多潇洒n,关于作 者.,JOptionPane.INFORMATION_MESSAGE);timer.start();); /游戏忠告菜单项的功能实现adviitem.addActionListener(new ActionListener() public void actionPerformed(ActionEvent e)timer.stop();JOptionPane.showMessageDialog(frame,抵制不良游戏 , 拒绝盗版游戏nn注意自我保护 , 谨防受骗上当nn +适度游戏益脑 , 沉迷游戏伤身nn合理安排时间 , 享受健康生活n,健康游戏忠告。, JOptionPane.INFORMATION_MESSAGE); timer.start(););menu.add(gameMenu);menu.add(helpMenu); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setBounds(300,100,400,520); frame.setVisible(true);frame.setResizable(false);/ 创建一个俄罗斯方块类class Tetrisblok extends JPanel implements KeyListener private static final long serialVersionUID = 1L; Random ran = new Random(); /使用Random函数；public int blockType; / blockType代表方块类型 public int score = 0; /分数；public int turnState; / turnState代表方块状态 public int x; /方块起始位置的横坐标public int y; /方块起始位置的纵坐标public int nextb = ran.nextInt(7); /下一个方块类型；public int nextt = ran.nextInt(4); /下一个方块的形状； private int i = 0;private int j = 0;private boolean flag = false; int map = new int1323; Tetrisblok()newblock();newmap();drawwall();/第一组代表方块的形状，方块形状类型有S、Z、L、J、I、O、T 7种 /第二组代表方块旋转几次 /第三四组为方块矩阵private final int shapes = new int / 棒型方块 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0 , 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0 ,/ s型方块 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0 , 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0 ,/ z型方块 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 ,/ 右l型方块 0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0 , 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 ,/ 田型方块 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ,/ 左l型方块 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0 , 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 1, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0 , 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 ,/ t型方块 0, 1, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0 , 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 , 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0 ;/ 生成新方块的方法public void newblock() blockType = nextb; turnState = nextt;nextb = ran.nextInt(7);nextt = ran.nextInt(4); x = 4;y = 0;if (gameover(x, y) JOptionPane.showMessageDialog(null,不好意思，游戏结束，请再接再厉！); newmap();drawwall(); score = 0;/ 判断游戏结束的方法public boolean gameover(int x, int y)if (blow(x, y, blockType, turnState) return true;elsereturn false;/ 是否合法的方法public boolean blow(int x, int y, int blockType, int turnState) for (int a = 0; a 4; a+) for (int b = 0; b 4; b+)if (shapesblockTypeturnStatea * 4 + b = 1) & (mapx+ b + 1y + a = 1)| (shapesblockTypeturnStatea * 4 + b = 1) & (mapx+ b + 1y + a = 2)return true;return false;/ 初始化地图public void newmap()for (i = 0; i 12; i+) for (j = 0; j 22; j+)mapij = 0;/ 画围墙public void drawwall()for (i = 0; i 12; i+) mapi21 = 2;for (j = 0; j 22; j+) map11j = 2; map0j = 2;/ 旋转的方法public void turn()int tempturnState = turnState; turnState = (turnState + 1) % 4;if (!blow(x, y, blockType, turnState)if (blow(x, y, blockType, turnState) turnState = tempturnState;repaint();/ 左移的方法public void left()if (!blow(x - 1, y, blockType, turnState) x = x - 1;repaint();/ 右移的方法public void right()if (!blow(x + 1, y, blockType, turnState) x = x + 1;repaint();/ 下落的方法public void down()if (!blow(x, y + 1, blockType, turnState) y = y + 1;if (blow(x, y + 1, blockType, turnState) add(x, y, blockType, turnState); newblock();delline();repaint();/ 消行的方法public void delline() int c = 0;int i = 0; /i用来确定本次消了几行 for (int b = 0; b 22; b+)for (int a = 0; a 0; d-) for (int e = 0; e 11; e+) maped = maped - 1;c = 0;/确定消行分数 switch (i) case 1:score = score +1; break;case 2:score = score +3; break;case 3:score = score +6; break;case 4:score = score +10; break;default: break;/ 把当前添加mappublic void add(int x, int y, int blockType, int turnState) int j = 0;for (int a = 0; a 4; a+) for (int b = 0; b 4; b+)if (mapx + b + 1y + a = 0)mapx + b + 1y + a = shapesblockTypeturnStatej;j+;/ 画方块的的方法public void paintComponent(Graphics g)/Object yanse = BLUE,GREEN,LIGHT_GRAY,YELLOW,PINK; super.paintComponent(g);/ 画当前方块for (j=0;j16;j+)if (shapesblockTypeturnStatej=1) /画矩形区域g.setColor(Color.BLUE); g.fill3DRect(j%4+x+1)*20,(j/4+y)*20,20,20,true);g.setColor(Color.BLACK); g.draw3DRect(j%4+x+1)*20,(j/4+y)*20,20,20, true);/画下一个方块for (j = 0; j 16; j+)if (shapesnextbnexttj = 1) g.setColor(Color.BLUE);g.fill3DRect(j%4+1)*20+250,(j/4)*20+40, 20, 20,true); g.setColor(Color.BLACK);g.draw3DRect(j%4+1)*20+250,(j/4)*20+40, 20, 20, true);/ 画已经固定的方块for (j = 0; j 22; j+) for (i = 0; i 12; i+)if (mapij=2) /画围墙 g.setColor(Color.BLACK);g.fill3DRect(i*20,j*20,20,20,true); g.