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_ _ 诚信应考,考试作弊将带来严重后果! 华南理工大学期末考试 Data Structure A试卷注意事项:1. 考前请将密封线内填写清楚; 2. 所有答案请直接答在试卷上; 3考试形式:闭卷; 4. 本试卷共十大题,满分100分,考试时间120分钟。题 号一二三四五六七八九十总分得 分评卷人1. Select the correct choice. (20 scores, each 2 scores)(1) An algorithm must be or do all of the following EXCEPT: ( D )(A) Correct (B) Finite (C) Terminate (D) Ambiguous(2) Pick the growth rate that corresponds to the most efficient algorithm as n gets large: ( C )(A) n! (B) 2n (C) 10nlog n (D) 2n2(3) If a data element requires 6 bytes and a pointer requires 4 bytes, then a linked list representation will be more space efficient than a standard array representation when the fraction of non-null elements is less than about: ( B ) (A) 2/3 (B) 3/5 (C) 3/4 (D) 1/2(4) Which statement is not correct among the following four: ( A )(A) The worst case for my algorithm is n becoming larger and larger because that is the slowest.(B) A cluster is the smallest unit of allocation for a file, so all files occupy a multiple of the cluster size.(C) The selection sort is an unstable sorting algorithm.(D) The number of leaves in a non-empty full binary tree is one more than the number of internal nodes.(5) Which of the following is a true statement: ( C )(A) In a BST, the left child of any node is less than the right child, and in a heap, the left child of any node is less than the right child.(B) In a BST, the left child of any node could be less or greater than the right child, but in a heap, the left child of any node must be less than the right child. (C) In a BST, the left child of any node is less than the right child, but in a heap, the left child of any node could be less than or greater than the right child.(D) In both a BST and a heap, the left child of any node could be either less than or greater than the right child.(6) The most effective way to reduce the time required by a disk-based program is to: ( B ) (A) Improve the basic operations. (B) Minimize the number of disk accesses. (C) Eliminate the recursive calls. (D) Reduce main memory use.(7) The max-heap constructed by a sequence of key (46, 79, 56, 38, 40, 84) is ( )?(A) 79, 46, 56, 38, 40, 84 (B) 84, 79, 56, 46, 40, 38(C) 84, 79, 46, 38, 40, 56 (D) 84, 56, 79, 40, 46, 38(8) If there is 0.5MB working memory, 4KB blocks, yield 128 blocks for working memory. By the multi-way merge in external sorting, the average run size and the sorted size in one pass of multi-way merge on average are separately ( A )?(A) 1MB, 128MB (B) 1MB, 64MB(C) 2MB, 64 MB (D) 0.5 MB, 128MB(9) Tree indexing methods are meant to overcome what deficiency in hashing? ( D )(A) Inability to handle range queries. (B) Inability to maximum queries(C) Inability to handle queries in key order (D) All of above.(10) Assume that we have eight records, with key values A to H, and that they are initially placed in alphabetical order. Now, consider the result of applying the following access pattern: E D F G B G F A F E G B, if the list is organized by the move-to-front heuristic, then the final list will be ( B ).(A) B G E F D A C H (B) B G E F A D C H(C) A B F D G E C H (D) F D G E A B C H2. Fill the blank with correct C+ codes: (13 scores)(1) Given an array storing integers ordered by value, modify the binary search routines to return the position of the first integer with the greatest value less than K when K itself does not appear in the array. Return ERROR if the least value in the array is greater than K: (10 scores)/ Return position of greatest element = Kint newbinary(int array, int n, int K) int l = -1; int r = n; / l and r beyond array bounds while (l+1 != r) / Stop when l and r meet _ int i=(l+r)/2_; / Look at middle of subarray if (K arrayi) _ l=i _ / In right half / Search value not in array _ return l _; / l at first value less than K / l=-1, no value less than K(2) A full 5-ary tree with 100 internal vertices has _501_vertices. ( 3 scores)3. A certain binary tree has the preorder enumeration as ABECDFGHIJ and the inorder enumeration as EBCDAFHIGJ. Try to draw the binary tree and give the postorder enumeration. (The process of your solution is required!) (8 scores)EBCDFHIGJAABEFCDHIGJABEFCDGJHIABEFCDGJHIPostorder enumeration: EDCBIHJGFA4. Determine for the following code fragments in the average case. Assume that all variables are of typ
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