C++与数据结构基础简明教程课后习题答案.docx

C+与数据结构基础简明教程课后习题答案1-7-1/输出一个数的10倍#include using namespace std;int main() couta; coutresult=a*10endl; return 0;1-7-2/输出两个数中的较小的#include using namespace std;int main() double x,y,min; coutplease input two numbersxy; min=(xy?y:x); coutthe smaller is minendl; return 0;1-7-3/输入半径计算周长和面积#include using namespace std;int main() coutrad; double c,s; c=2*3.14*rad; s=3.14*rad*rad; cout周长是cendl; cout面积是sendl; return 0;1-7-4/将10000秒化成小时分钟秒#include using namespace std;int main() int hour,min,second; hour=10000/3600; min=(10000%3600)/60; second=10000-hour*3600-60*min; couthourhoursminminutessecondsecondsendl; return 0;1-7-5/将一个三位数倒叙输出#include using namespace std;int main()int num,num_bai,num_shi,num_ge;coutnum;num_bai=num/100;num_shi=(num-num_bai*100)/10;num_ge=num-num_bai*100-num_shi*10;coutnum_geendl;coutnum_shiendl;coutnum_baiendl;return 0;2-3/简单的输入输出#include using namespace std;int main() double y,n; coutn; if (n0) y=n+1; if (n0) y=n*n; if (n=0) y=0; coutthe result is: y; return 0;2-4/输出学生学号和对应的成绩等级#include using namespace std;int main() double fenshu; int xuehao; char dengji; int i; for (i=1;i=10;i+) onerror:coutfenshu; if (fenshu=90&fenshu=80&fenshu=600&fenshu=0&fenshu60) dengji=D; if (fenshu0) cout100) couterror; goto onerror; coutthe id isiendl; coutthe score isdengjiendl; return 0;2-5/判断输入字符类别#include using namespace std;int main()char zifu;int ascii;coutzifu;ascii=zifu;if (ascii=48&ascii=57) cout=97&ascii=122) cout=65&ascii=90) cout大写字母n; goto end; cout其他字符;coutendl;end:return 0;2-6/求圆周率的近似值#include #include using namespace std;int main()int xishu=-1;double danshu=1.0;int i=1;double sifenzhipi=0;do xishu=xishu*(-1); danshu=1.0/(2*i-1); sifenzhipi=sifenzhipi+xishu*danshu; i+;while(danshu=0.000001);coutsetprecision(15)sifenzhipi*4endl;return 0;2-7/输出斐波那契数列前40个数，以8*5的格式输出#include #include using namespace std;int main() int b=2; int feibo1=0; int feibo2=1; coutsetw(9)0setw(9)1; for(int i=1;i=38;i+) int a=feibo2; feibo2=feibo1+feibo2; feibo1=a; coutsetw(9)feibo2; b=b+1; if(b%8=0) coutendl; return 0;2-8/统计输入的元音字母个数#include using namespace std;int main() char zimu; int a,e,i,o,u; a=e=u=i=o=0; begin:cinzimu; switch(zimu) case a :a+;break; case e :e+;break; case i :i+;break; case o :o+;break; case u :u+;break; case # :goto end; goto begin;end:coutaendleendliendloendluendla+e+i+o+u; return 0;2-10/计算5!+6!+7!#include using namespace std;int main() int i,j; int sum=0; for (i=5;i=7;i+) int jiecheng=1; for (j=1;j=i;j+) jiecheng=jiecheng*j; sum=sum+jiecheng; coutsum; return 0;2-11/从2开始100个素数#include using namespace std;int main() int num=1; int sushu=0; start:; num+; for (int i=2;i=num;i+) if(num%i=0) break; if (i=num) coutnumendl; sushu+=1; if(sushu!=100) goto start; return 0;2-12/百钱买百鸡问题#include using namespace std;int main() int x,y,z; for(x=0;x=100;x+) for(y=0;y=100;y+) for(z=0;z=100;z+) if (x+y+z=100&5*x+3*y+z/3=100&z%3=0) coutxtytzendl; return 0;2-13#include using namespace std;int main() int a,b,c,d,e; c=0; cina; cout输入aendl该数的三次方是a个连续奇数; b=1; e=a*a*a; while (c!=e) d=b; c=0; for (int i=1;i=a;i+) c=c+d; d=d+2; b=b+2; /coutb-2; int f=b-4; for (int j=1;j=a;j+) f=f+2; coutf ; cout的和n; return 0;2-14/输出四方*形状#include using namespace std;int main() int i,j; for (i=1;i=9;i+) j=1; for(j=1;j=6&i+j=14&j-i=4&i-j=4) cout*; else cout ; coutendl; return 0;3-1-1/向数组a中输入10个整数，求其中的最大值，最小值和10个数的算术平均值#include using namespace std;int main() int a10; for(int i=0;iai; int max=a0,min=a0,sum=a0; for(int j=0;jaj?max:aj); min=(minaj?min:aj); double ave=sum/10.00; coutmaxendlminendlaveendl; return 0;3-1-2#include using namespace std;int main() int score10; int sum=0,a=0,b=0; for(int i=0;iscorei; sum=sum+scorei; double ave=sum/10.0; for(int j=0;jave) a+; if(scorej60) b+; cout成绩大于平均值的人数是aendl成绩小于60的人数bendl; return 0;3-3-1#include using namespace std;int main() int a10,sum=0,min,max; double ave; int *ptoa=a; for (int i=0;i*(a+i); sum+=*(a+i); min=*(a); max=*(a); for (int j=1;j=9;j+) min=(min*(a+j)?max:*(a+j); coutmaxendlminendl; ave=sum/10.0; coutaveendl; return 0;3-3-2#include using namespace std;int main() int a10,sum=0,j=0,c=0; /定义数组a，sum是各学生成绩之和，j是小于60的个数，c是大于平均值的个数 double ave=0; /定义平均值 int *ptoa=a; /使用指针 for (int i=0;i*(ptoa+i); sum+=*(ptoa+i); if (*(ptoa+i)60) j+; ave=sum/10.0; /计算平均值 /coutaveendl; /可以输出平均值 for (int k=0;kave) c+; coutcendlj; return 0;3-3-3#include using namespace std;int main() char string100; cinstring; int i=0,an=0,in=0; cout您输入的字符串; while (stringi!=0) if(stringi=a) an+; if(stringi=i) in+; coutstringi; i+; coutendlanendlinendl; return 0;3-3-3a#include using namespace std;int main() char a100; /定义存放字符串的数组 char *ptoa=a; /使用指针 int i=0,an=0,in=0; /an，in分别为a，i的个数 cina; while (*(ptoa+i)!=0) /a【i】 cout*(ptoa+i); switch (*(ptoa+i) /判断 case a : an+;break; case i : in+;break; i+; coutendlanendlin; return 0;3-3-4#include using namespace std;int main() int a33; for (int i=0;i=2;i+) for(int j=0;j*(*(a+i)+j); cout*(*(a+0)+0)+*(*(a+1)+1)+*(*(a+2)+2)endl; cout*(*(a+0)+2)+*(*(a+1)+1)+*(*(a+2)+0)endl; return 0;3-3-5v1#include using namespace std;int main() int a11=2,4,5,8,12,14,16,18,20,30,0,b,i,m,j; cinb; a10=b; if (b30) goto end2; for(i=0;ib) m=i+1; goto end; end:; for (j=10;j=m+1;j-) aj=aj-1; am=b;end2:; for (int k=0;k=10;k+) coutakendl; return 0;3-3-5v2#include using namespace std;int main() int i,j,temp; int a11=2,4,5,8,12,14,16,18,20,30; cina10; for (i=0;i=10;i+) for(j=0;jaj+1) temp=aj+1; aj+1=aj; aj=temp; for (int k=0;k=10;k+) coutak ; coutn; return 0;3-3-5v3#include using namespace std;int main() int a11=2,4,5,8,12,14,16,18,20,30,num,i,j; coutnum; if (numa9) a10=num; else for (i=0;inum) for(j=9;j=i;j-) aj+1=aj; ai=num; break; for (i=0;i=10;i+) coutai ; return 0;3-3-5final#includevoid main() int a11=2,4,5,8,12,14,16,18,20,30,b,i=0,j=10; cinb; while(aib&ii) aj=aj-1; j-; ai=b; cout输入插入后的结果：; for(i=0;i11;i+)coutai ; coutendl;3-3-6#include using namespace std;int main() int a53,s5=0,0,0,0,0,temp; for (int i=0;i=4;i+) cout请输入第i+1行的数据endl; for (int j=0;j*(*(a+i)+j); *(s+i)+=*(*(a+i)+j); /* /注释掉的部分可以输出每行数据之和 for (int k=0;k=4;k+) cout*(s+k)endl; */ for (int m=0;m=4;m+) for (int n=0;n*(s+n+1) temp=*(s+n+1); *(s+n+1)=*(s+n); *(s+n)=temp; for (int l=0;l=4;l+) coutendl*(s+l); coutendl; system(pause); return 0;4-3#include using namespace std;int fun1(int x,int y);int fun2(int x,int y);int fun3(int x,int y);int fun4(int x,int y);int main() int a,b; coutab; cout两个数的和的平方是fun1(a,b)endl; cout两个数的平方和是fun2(a,b)endl; cout两个数的差的平方是fun3(a,b)endl; cout两个数平方的差是fun4(a,b)endl; return 0;int fun1(int x,int y) int z=(x+y)*(x+y); return z;int fun2(int x,int y) int z=x*x+y*y; return z;int fun3(int x,int y) int z=(x-y)*(x-y); return z;int fun4(int x,int y) int z=x*x-y*y; return z;4-4#include using namespace std;double jc(int x);int sm(int x);int main() int m,n,s2; double s1; cinmn; s1=jc(m)/(jc(n)*jc(m-n); s2=sm(m)-sm(n); couts1endls2; return 0;double jc(int x) double s=1; for (int i=1;i=x;i+) s*=i; return s;int sm(int x) int s=0; for (int i=1;i=x;i+) s+=i; return s;4-6#include #include using namespace std;double jxf(int n);double txf(int n);double f(double x);/const pi=3.1415927;int main() int n; double y1,y2; cinn; y1=jxf(n); y2=txf(n); couty1endly2; return 0;double jxf(int n) double sum=0,s; for (int i=0;i=n-1;i+) s=(i*3.14)/n; sum+=(3.14/n)*f(s); return sum;double txf(int n) double sum=0,s1,s2; for (int i=0;i=n-1;i+) s1=i*3.14/n; s2=(i+1)*3.14/n; sum+=3.14/n*(f(s1)+f(s2); sum/=2.0; return sum;double f(double x) double y; y=sin(x)+cos(x); return y;4-6v1#include #include using namespace std;double jxf(int n);double txf(int n);double f(double x);const pi=3.1415927;int main() int n; double y1,y2; cinn; y1=jxf(n); y2=txf(n); if (abs(y1-2)abs(y2-2) cout矩形法; else cout梯形法; return 0;double jxf(int n) double sum=0; for (int i=0;i=n-1;i+) sum+=pi/n*f(i*pi/n); return sum;double txf(int n) double sum=0; for (int i=0;i=n-1;i+) sum+=pi/n*(f(i*pi/n)+f(i+1)*pi/n); sum/=2; return sum;double f(double x) double y; y=sin(x)+cos(x); return y;4-6v2error#include #include using namespace std;double jxf(int n);double txf(int n);double f(double x);const pi=3.1415927;int main() int n; double y1,y2; cinn; y1=jxf(n); y2=txf(n); if (abs(y1-2)abs(y2-2) cout矩形法; else cout梯形法; return 0;double jxf(int n) double sum=0; for (int i=0;i=n-1;i+) sum+=pi/n