基于单片机的LED路灯时控光控模拟系统设计.doc

基于单片机的LED路灯时控光控模拟系统设计原理图中的滑动变阻器实际使用光敏电阻。程序如下#include#define uchar unsigned char #define uint unsigned int sbit key_0=P23;sbit key_1=P22;sbit key_2=P21;sbit key_3=P20;sbit wela_0=P27;sbit wela_1=P26;sbit wela_2=P25;sbit wela_3=P24; sbit ludeng=P10; sbit inlamp1=P12; sbit inlamp2=P14; sbit guangmin=P16; uchar code table=0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f;unsigned int hour,min,STH,STM,LH,LM,f1,f0; uint aa;void delay(uint u) /延时子程序 uint x,y ; for(x=u;x0;x-) for(y=110;y0;y-);void display(uchar h,uchar m) /动态扫描子程序，扫描周期为50ms uchar hhour,lhour,hmin,lmin; hhour=h/10; lhour=h%10; hmin=m/10; lmin=m%10; P0=tablehhour; P2=0x8f; /P0口加上拉电阻才能显示高电平。不然是高阻态。 delay(2); P0=tablelhour; P2=0x4f; delay(2); P0=tablehmin; P2=0x2f; delay(2); P0=tablelmin; P2=0x1f; delay(2); void main() EA=1; TMOD=0x11; TH0=0x4b; TL0=0xfd; TH1=0x4b; TL1=0xfd; TR0=1; TR1=1; ET0=1; ET1=1; EX0=1;EX1=1;IT0=1;IT1=1; PX0=1;PX1=0;hour=12;min=0;STH=19;STM=0;LH=5;LM=0;aa=0; while(1) if(key_0=0) delay(2);if(key_0=0)hour+; /在检测按键按下时，按键需要一个消除/抖动的延时 if(hour=24)hour=0; while(key_0!=1)display(hour,min); if(key_1=0) delay(2);if(key_1=0)min+; if(min=60)min=0; while(key_1!=1)display(hour,min); if(hour=STH) /条件符合点亮路灯 if(min=STM) ludeng=0; TR1=0; if(hour=LH) /条件符合熄灭路灯 if(min=LM) ludeng=1; TR1=1; display(hour,min); void time1() interrupt 3 TH1=0x3c; TL1=0xb0; f1=guangmin; if(ludeng=1) switch(f1) case 1:ludeng=0;break; case 0:ludeng=1;break; default :break; if(ludeng=0) switch(f1) case 1:ludeng=0;break; case 0:ludeng=1;break; default :break; void time() interrupt 1 /定时器0 用来控制实时时间 TH0=0x3c; TL0=0xb0; aa+; if(aa=600) aa=0; min+; if(min=60) min=0; hour+; if(hour=24) hour=0; void timedot() interrupt 0 /设置点亮时间 inlamp1=0; inlamp2=1; while(key_2=1) if(key_0=0) delay(2);if(key_0=0)STH+; if(STH=24)STH=0; while(key_0!=1)display(STH,STM); if(key_1=0) delay(2);if(key_1=0)STM+; if(STM=60)STM=0; while(key_1!=1)display(STH,STM); display(STH,STM); inlamp1=1; void timelong() interrupt 2 /设置熄灭时间 inlamp2=0; while(key_2=1) if(key_0=0) delay(2);if(key_0=0)LH+; if(LH=24)LH=0; while(key_0!=1)display(LH,LM); i