Oracle 数据库上机试验指导1(答案).doc

Oracle 数据库上机试验指导 实验一试验1 DDL & DML试验目的: 熟悉Oracle下数据库基表的创建&修改&删除 熟悉Oracle下数对数据的插入&修改&删除试验步骤: 运行给定脚本(该脚步是创建一个用户,并赋予该用户一定的权限!)启动Oracle数据库Dos控制台下运行sqlplus /nolog命令Conn stud/stud as sysdba;-stud是一个不存在账户，主要用sysdba来登录，可以show user 来查看一下当前用户 c:createUser.sql; -该文件在实验材料文件夹里，请将其考入到C:根目录下conn csj/csj -完成用户CSJ的创建 二 在CSJ用户模式下完成以下工作(自己写sql脚本,然后调试运行)创建一张学生表创建一张课程表创建一张选课表分别向学生表,课程表,选课表插入下面数据思考以下问题:如何得到所有男生/女生人数?如何得到某一门课程(如数学)的选课人员清单?如何得到某一门课程(如数学)的选课人员总数?如何得到某一门课程(如数学)的选课人员的平均成绩?三. 上交脚本,并且以”姓名 学号.sql”上交脚本(当场上交,逾期不收).学生表(student)姓名(非空)学号(PK)性别(只能输入男or 女)住址李白100001男和平区杜甫100002男河西区李清照100003女河北区白居易100004男红桥区蔡琰100005女红桥区课程表(course)课程名称(不允许重名)课程编号(pk)上课教师课程学分(1,3,5)数学M1001奥巴马3军事理论J2002拿破仑5摔跤S3003普京1选课表(courSelc)记录编号(PK,自增)学号(FK)课程编号(FK)考试成绩(0,100)1100001M2001702100001J2002603100001S3003804100002M2001755100002J2002856100002S3003957100003M2001508100003J2002559100003S30034510100004M20011011100004J20021512100004S300325参考脚本：- 创建学生表create table student( studid char(6) primary key, studname varchar2(16) not null, gender char(4) check(gender in(男,女), addr varchar2(256);- 创建课程表create table course( courseid char(6) primary key, coursename varchar2(32) not null unique, teacher varchar2(16) , score number check(score in (1,3,5);- 创建选课表create table courSelc( recid number(4) primary key, studid char(6), courseid char(6), score number(2) check(score =0 and score =100), constraint fk_stud foreign key(studid) references student(studid), constraint fk_cour foreign key(courseid) references course(courseid);- 插入数据insert into student values(100001,李白,男,和平区);insert into student values(100002,杜甫,男,河西区);insert into student values(100003,李清照,女,河北区);insert into student values(100004,蔡琰,女,红桥区);insert into course values(M1001,数学,奥巴马,3);insert into course values(J2002,军事理论,拿破仑,5);insert into course values(S3003,摔跤,普京,1);insert into courSelc values(1,100001,M1001,70);insert into courSelc values(2,100001,J2002,60);insert into courSelc values(3,100001,S3003,80);insert into courSelc values(4,100002,M1001,75);insert into courSelc values(5,100002,J2002,85);insert into courSelc values(6,100002,S3003,95);insert into courSelc values(7,100003,M1001,50);insert into courSelc values(8,100003,J2002,55);insert into courSelc values(9,100003,S3003,45);insert into courSelc values(10,100004,M1001,10);insert into courSelc values(11,100004,J2002,15);insert into courSelc values(12,100004,S3003,25);select count(*) from student where gender=男;select count(*) from student where gender=女;select s.studid,s.studname,c.coursename,cs.score from student s,course c,courSelc cswhere s.studid=cs.studid and c.courseid=cs.courseid and c.coursename=数学;select count(*) from courSelc cs join course c on c.cou