DEBUG实验报告.doc

debug cpu pc win7_x64dosbox status window debug.exe (1) debugcpu b8 20 4emov ax,4e20h 05 16 14 add ax,1416h bb 00 20 mov bx,2000h 01 d8 add ax,bx 89 c3 mov bx,ax 01 d8 add ax,bx b8 1a 00mov ax,001ah bb 26 00mov bx,0026h 00 d8 add al,bl 00 dc add ah,bl 00 c7 add bh,al b4 00 mov ah,0 00 d8 add al,bl 04 9c add al,9ch- 1 - 2 -:mov ax,4e20 add ax,1416 mov bx,2000 add ax,bx4e20hax, ax+1416hax,a 2000hbx, ax+bxax, ax=4e20h x=6236h bx=2000h ax=8236h- 3 -mov bx,axaxbx, bx=8236h add ax,bx ax+bxax,ax, ax=046ch mov ax,001a001ahax, ax=001ah mov bx,0026 0026hbx, bx=0026h add al,bl al+blal,ah=00h,al=40h,ax=0040h add ah,bl ah+blah,ah=26h,al=40h,ax=2640h add bh,al bh+albh,bh=40h,bl=26h,bx=4026h mov ah,0 0000hah, ah=00h,al=40h,ax=0040h, add al,bl al+blal,ah=00h,al=66h,ax=0066h add al,9chal+9chal,ah=00h,al=02h,ax=0002h,(2) 32000:0328mov ax,1 add ax,axjmp 2000:0003- 4 - 5 -debug 1122073011221. debugdebug 2. 3. 12. debug1. 120hal mov al , 20h 2al*2mov al , 02hmul al325hbl mov bl , 25h 4al*blmul bl ax= ax=0940h2. 1bx4 and bx , f0h 2ax41 or ax , f0h (3)dx4 xor dx , 0fh (4)cx and cx , 0ff0h(5)axbx1 xorax , bx3.ax=?mov ax ,4312 mov cl , 8 sar ax ,cl dec ax mov cx ,8 mul cxax=210.9h4. =,=, debug rdebugo debug debug1. ,2. debug 1. ,:dat segment mov al,bmov z+1,aladb 20 ;()call sub1bdb 15 ;()ydb 3 dup(0) add word ptr y,axzdb 0,0 adc byte ptry+2,0 dat ends retsta segment stack starendpdw 50 dup(?)sub1procsta ends mov al,zcod segment mov ah,z+1assume cs:cod,ds:dat mul ahstarproc far add word ptr y,ax push ds adc byte ptry+2,0 xor ax,ax retpush axsub1endpmov ax,datcod endsmov ds,ax end starmov ax,stamov ss,axmov al,amov z,almov z+1,alcall sub1mov al,bmov z,almov z+1,alcall sub1mov al,amov z,al2. ,3. debug ,(1) d , a b (2) u ,., (3) t .:, (4) sub1 , g ,(5) e a,b ,(6) m a : (add adc) call sub1 ,(7) debug4. , star ., debug . u ,( star) ? masm1u , , 1512:0000h(2) d , a b 150a:0000h a150a:0001h b(3) t .:, push ax ip2 mov ds,ax ds 14fah150ah z0005hz0005