C语言程序设计现代方法第八章答案

Chapter 8Answers to Selected Exercises1.was #4 The problem withsizeof(a)/sizeof(t)is that it cant easily be checked for correctness by someone reading the program. (The reader would have to locate the declaration ofaand make sure that its elements have typet.)2.was #8 To use a digitd(in character form) as a subscript into the arraya, we would writead-0. This assumes that digits have consecutive codes in the underlying character set, which is true of ASCII and other popular character sets.7.was #10const int segments107 = 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 0, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1;Answers to Selected Programming Projects2.was #2#include int main(void) int digit_count10 = 0; int digit; long n; printf(Enter a number: ); scanf(%ld, &n); while (n 0) digit = n % 10; digit_countdigit+; n /= 10; printf (Digit: ); for (digit = 0; digit = 9; digit+) printf(%3d, digit); printf(nOccurrences:); for (digit = 0; digit = 9; digit+) printf(%3d, digit_countdigit); printf(n); return 0;5.was #6#include #define NUM_RATES (int) (sizeof(value) / sizeof(value0)#define INITIAL_BALANCE 100.00int main(void) int i, low_rate, month, num_years, year; double value5; printf(Enter interest rate: ); scanf(%d, &low_rate); printf(Enter number of years: ); scanf(%d, &num_years); printf(nYears); for (i = 0; i NUM_RATES; i+) printf(%6d%, low_rate + i); valuei = INITIAL_BALANCE; printf(n); for (year = 1; year = num_years; year+) printf(%3d , year); for (i = 0; i NUM_RATES; i+) for (month = 1; month = 12; month+) valuei += (double) (low_rate + i) / 12) / 100.0 * valuei; printf(%7.2f, valuei); printf(n); return 0;8.was #12#include #define NUM_QUIZZES 5#define NUM_STUDENTS 5int main(void) int gradesNUM_STUDENTSNUM_QUIZZES; int high, low, quiz, student, total; for (student = 0; student NUM_STUDENTS; student+) printf(Enter grades for student %d: , student + 1); for (quiz = 0; quiz NUM_QUIZZES; quiz+) scanf(%d, &gradesstudentquiz); printf(nStudent Total Averagen); for (student = 0; student NUM_STUDENTS; student+) printf(%4d , student + 1); total = 0; for (quiz = 0; quiz NUM_QUIZZES; quiz+) total += gradesstudentquiz; printf(%3d %3dn, total, total / NUM_QUIZZES); printf(nQuiz Average High Lown); for (quiz = 0; quiz NUM_QUIZZES; quiz+) printf(%3d , quiz + 1); total = 0; high = 0; low = 100; for (student = 0; student high) high = gradess