


全文预览已结束
下载本文档
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
DDR2 Layout Request1. Routing rules for CLK1) From OPL-06750-BG to 22 match resistor should be less than 30mm.2) From 22ohm match resistor to 100 diff. match resistor should be less than 135mm.3) From 100 diff. match resistor to DDR2 chip should be less than 5mm.4) Total length: 80mm CLK/CLK# 120mm1、时钟路由规则1)从opl-06750-bg 到22匹配电阻应小于30mm。2) From 22ohm match resistor to 100 diff. match resistor should be less than 135mm.2)从22ohm匹配电阻到100不同匹配电阻应小于135mm。3) From 100 diff. match resistor to DDR2 chip should be less than 5mm.3)从100不同匹配电阻到DDR2内存芯片应小于5mm。4) Total length: 80mm CLK/CLK# 120mm4)总长度:80mm 时钟/时钟#1202. Routing rule for Address/Command signals (DDR2_A0-A12/CAS/RAS/CS/WE/CKE/ODT)1) From OPL-06750-BG to 22 match resistor should be less than 70mm.2) From 22 match resistor to DDR2 chip should be less than 75mm.3) The total routing length should be less than 155mm.4) Tcmd/addr + 0.1ns= Tclk.2。地址/命令信号路由规则(ddr2_a0-a12 / CAS / RAS / CS /我们/非常/ ODT)1) From OPL-06750-BG to 22 match resistor should be less than 70mm.1)从opl-06750-bg到 22匹配电阻应小于70mm。2) From 22 match resistor to DDR2 chip should be less than 75mm.2)从22到DDR2芯片匹配电阻应小于75mm。3) The total routing length should be less than 155mm.3)的总路径长度不应超过155毫米。4) Tcmd/addr + 0.1ns= Tclk.4)TCMD /地址+ 0.1nsTCLK3. Routing rule for DQ/DM/DQS1) From OPL-06750-BG to 22ohm match resistor should be less than 40mm.2) From 22ohm match resistor to DDR2 chip should be less than 20mm.3) DQ/DM total routing length should be less than 60mm.3。路由规则的DQ / DM /的DQS1) From OPL-06750-BG to 22ohm match resistor should be less than 40mm.1)从opl-06750-bg到22ohm匹配电阻应小于40mm。2) From 22ohm match resistor to DDR2 chip should be less than 20mm.2)从22ohm 到DDR2芯片匹配电阻应小于20mm。3) DQ/DM total routing length should be less than 60mm.3)DQ / DM总路径长度应小于60mm。4) DQS/DQS#total routing length should be less than 60mm.4)DQS /的DQS #总路径长度应小于60mm。5) 140mm CK/CK# + DQS/DQS#4. Via placement rules within the byte lane(DQ,DQS,DM)1) Maximum number of Via within the same bit is 2.2) The number of Via within the same byte lane and the distance between each Via should be same.3) If there is any Via along with DQS line, the routing length difference between the differential pair should be less than 0.4mm.4) The Via clearance should be as small as possible.5) Take care not to cut the GND plane by placing the Via clearance in rows.6) Do not route any signal where GND place does not exist under the signals due the Via clearance.5. DDR2 single side trace impedance: 50 (10%); Differential traces impedance: 100 (10%).4。通过配置规则的字节通道(DQ,DQS,DM)1) Maximum number of Via within the same bit is 2.1)过孔数最多两个。2) The number of Via within the same byte lane and the distance between each Via should be same.2)在同一字节通道之间的过孔的数量要一样并且每个过孔的距离应该是一样的。(同时转层)3) If there is any Via along with DQS line, the routing length difference between the differential pair should be less than 0.4mm.3)如果有任何过孔在DQS线上,两条差分对之间的长度差应小于0.4mm。4) The Via clearance should be as small as possible.4)过孔的间隙应尽可能小。5) Take care not to cut the GND plane by placing the Via clearance in rows.5)放置过孔时不要把地平面切割。6) Do not route any signal where GND place does not exist under the signals due t
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 单个活动策划方案
- 后勤比武活动方案
- 古风国画活动方案
- 友好奶茶活动方案
- 口头表达活动方案
- 司法大讲堂开展活动方案
- 可视空调活动方案
- 厦门退休老师活动方案
- 单位食堂团年活动方案
- 十一陶艺活动方案
- 专利代理所管理制度
- 2025至2030年中国核电材料行业市场现状分析及发展战略研判报告
- 玄隐遗密(含黄帝内经)
- 2025至2030年中国高镍三元材料产业发展动态及投资方向分析报告
- DB13T 1320.10-2010 中药材种子质量标准 第10部分:防风
- 2025年毕节市大方富民村镇银行招聘题库带答案分析
- 惠州市城乡规划管理技术规定(2020年)
- (高清版)TDT 1055-2019 第三次全国国土调查技术规程
- 23秋国家开放大学《视觉设计基础》形考任务1-5参考答案
- 超星尔雅学习通《国际金融》2020章节测试含答案(上)
- 危险性较大的分部分项工程清单
评论
0/150
提交评论