2020大二轮高考总复习理数课件：自检2复数与算法.ppt[文字可编辑]

1、第二版块,高考小题自检区,自检,02,复数与算法,A,组,高考真题集中训练,栏,目,导,航,考点,1,复数的概念与运算,考点,2,程序框图与算法,复数的概念与运算,3,i,1,2017,全国卷,D,1,i,A,1,2i,C,2,i,B,1,2i,D,2,i,3,i,3,i,1,i,3,3i,i,1,解析,2,i,故选,D,2,1,i,1,i,1,i,2,2017,全国卷,设复数,z,满足,1,i,z,2i,则,z,C,1,A,2,C,2,2,B,2,D,2,2i,解析,方法一,由,1,i,z,2i,得,z,1,i,1,i,z,2,故选,C,方法二,2i,1,i,由,1,i,z,2i,1,i,得

2、,z,1,i,z,2,故选,C,2,2,3,2016,全国乙卷,设,1,i,x,1,y,i,其中,x,y,是实数，则,x,y,i,B,A,1,C,3,B,2,D,2,解析,1,i,x,1,y,i,x,x,i,1,y,i,又,x,y,R,x,1,y,1,x,y,i,1,i,2,故选,B,4,2016,全国甲卷,已知,z,m,3,m,1)i,在复平面内对应的点在第四象限，则,实数,m,的取值范围是,A,A,3,1,C,1,B,1,3,D,3,m,3,0,解析,由题意知,m,1,0,即,3,m,1,故实数,m,的取值范围为,3,1,4i,5,2016,全国丙卷,若,z,1,2i,则,C,z,z,1,

3、A,1,C,i,B,1,D,i,4i,4i,解析,因为,z,1,2i,则,z,1,2i,所以,z,z,1,2i)(1,2i,5,则,4,z,z,1,i,故选,C,1,z,6,2015,全国卷,设复数,z,满足,i,则,z,A,1,z,A,1,C,3,B,2,D,2,1,z,1,i,1,i,1,i,2i,解析,由,i,得,z,i,所以,z,i,1,故选,A,2,2,1,z,1,i,7,2015,全国卷,若,a,为实数，且,2,a,i,a,2i,4i,则,a,B,A,1,C,1,B,0,D,2,2,解析,2,a,i,a,2i,4i,4,a,a,4)i,4i,4,a,0,2,a,4,4,解得,a,0

4、,故选,B,程序框图与算法,1,2017,全国卷,如图所示的程序框图是为了求出满,足,3,2,1 000,的最小偶数,n,那么在,白框中，可以分别填入,D,A,A,1 000,和,n,n,1,B,A,1 000,和,n,n,2,C,A,1 000,和,n,n,1,D,A,1 000,和,n,n,2,n,n,和两个空,解析,因为题目要求的是,满足,3,2,1,000,的最小偶数,n,所以,n,的叠加,值为,2,所以内填入,n,n,2,由程序框图知，当,输出,n,所以,内填入,A,1 000,故选,D,内的条件不满足时,n,n,2,2017,全国卷,执行如图所示的程序框图，为,使输出,S,的值小于

5、,91,则输入的正整数,N,的最小值为,D,A,5,B,4,C,3,D,2,解析,假设,N,2,程序执行过程如下,t,1,M,100,S,0,100,1,2,S,0,100,100,M,10,10,t,2,10,2,2,S,100,10,90,M,10,1,t,3,3,2,输出,S,90,91,符合题意,N,2,成立显然,2,是最小值故选,D,3,2017,全国卷,执行如图所示的程序框图，如果输入,A,2,B,3,的,a,1,则输出的,S,B,C,4,D,5,解析,当,K,1,时,S,0,1,1,1,a,1,执行,K,K,1,后,K,2,当,K,2,时,S,1,1,2,1,a,1,执行,K,K

6、,1,后,K,3,当,K,3,时,S,1,1,3,2,a,1,执行,K,K,1,后,K,4,当,K,4,时,S,2,1,4,2,a,1,执行,K,K,1,后,K,5,当,K,5,时,S,2,1,5,3,a,1,执行,K,K,1,后,K,6,当,K,6,时,S,3,1,6,3,执行,K,K,1,后,K,7,6,输出,S,3,结束循,环故选,B,4,2016,全国甲卷,中国古代有计算多项式值的秦九韶算法，如,图是实现该算法的程序框图执行该程序框图，若输入的,x,2,n,2,依次输入的,a,为,2,2,5,则输出的,s,C,A,7,B,12,C,17,D,34,解析,第一次运算,s,0,2,2,2,

7、k,1,第二次运算,s,2,2,2,6,k,2,第三次运算,s,6,2,5,17,k,32,结束循环,s,17,5,2016,全国丙卷,执行如图所示的程序框图，如果输入的,a,4,b,6,那么,输出的,n,B,A,3,C,5,解析,程序运行如下,开始,a,4,b,6,n,0,s,0,第,1,次循环,a,2,b,4,a,6,s,6,n,1,第,2,次循环,a,2,b,6,a,4,s,10,n,2,B,4,D,6,第,3,次循环,a,2,b,4,a,6,s,16,n,3,第,4,次循环,a,2,b,6,a,4,s,20,n,4,此时，满足条件,s,16,退出循环，输出,n,4,故选,B,6,201

8、5,全国卷,执行如图所示的程序框图，如果输入的,t,0.01,则输出的,n,C,A,5,C,7,B,6,D,8,1,1,解析,运行第一次,S,1,2,2,0.5,m,0.25,n,1,S,0.01,运行第二次,S,0.5,0.25,0.25,m,0.125,n,2,S,0.01,运行第三次,S,0.25,0.125,0.125,m,0.062 5,n,3,S,0.01,运行第四次,S,0.125,0.062 5,0.062 5,m,0.031 25,n,4,S,0.01,运行第五次,S,0.031 25,m,0.015 625,n,5,S,0.01,运行第六次,S,0.015 625,m,0.

9、007 812 5,n,6,S,0.01,运行第七次,S,0.007 812 5,m,0.003 906 25,n,7,S,0.01,输出,n,7,故选,C,7,2015,全国卷,下边程序框图的算法思路源于我国古代数学名著九章算,术中的“更相减损术”执行该程序框图，若输入的,a,b,分别为,14,18,则输出的,a,B,A,0,B,2,C,4,D,14,解析,a,14,b,18,第一次循环,14,18,且,1418,b,18,14,4,第二次循环,14,4,且,144,a,14,4,10,第三次循环,10,4,且,104,a,10,4,6,第四次循环,6,4,且,64,a,6,4,2,第五次循环,2,4,且,24,b,4,2,2,第六次循环,a,b,2,跳出循环，输出,a,2,故选,B,8,2014,全国卷,执行如图所示的程序框图，若输入的,a,b,k,分别为,1,2,3,则输出的,M,D,20,A,3,7,C,2,16,B,5,15,D,8,3,3,解析,第一次循环,M,2,a,2,b,2,n,2,8,3,8,第二次循环,M,3,a,2,b,3,n,3,15,8,15,第三次循环,M,8,a,3,b,8,n,4,15,