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1、总复习方程教学目标:(一)进一步理解和掌握求方程的解的方法,并正确地求简易方程的解和列方程解文字叙述题。(二)会用方程表示简单情境中的等量关系,正确解方程,提高解题能力。(三)理解等式的性质,会用等式的性质解简单的方程。教学重难点: 使学生进一步理解和掌握求简易方程的解的算理和算法,并正确地求简易方程的解和列方程解文字叙述题。教学过程:一、回顾交流1、回顾方程的含义。并举例(生凭借已有的经验说,说的不规范的话先不纠正,在下题中感悟后加深理解)出示:下列各式中是等式的打上“”,是方程的打上“”。 36() 2+58() 2.7=3.7( ) 151十x( )第题同时出现了“”和“”记号,说明了什
2、么?什么是方程?生交流:总结概括 2、解下列方程。9x-1.8=5.4 54348670 3.5xx=1.73、怎样解简易方程?根据什么?怎样检验?生独立思考,小组交流(检验不做要求,让学生了解一下) 小结:根据等式的基本性质解方程;多步的问题要进行转化处理,根据加、减、乘、除各部分的关系求解。(虽然教材中强调根据等式的性质解,我觉得两种方法都有必要让学生了解,选择自己喜欢的用)4、列方程解决下面的问题出示课本p61的2题请同学们独立在练习本上完成,然后想一想列方程解应用题的一般步骤有哪些?说说你是怎样做的?生集体交流:强调:列方程时,找出等量关系是很重要的 二、巩固练习 1.解方程 2x一5
3、.56=3 3x十1.5x=13.5 (x十2)0.5=1.l 40%x=4.2 6x6=4x4 7x一4.25.8=1.9 2.列方程,并解方程。 (1)某数增加 5倍后与 3的差等于 117,求某数。 (2) 15加上一个数的 2倍等于 38的一半,求这个数。 (3)5的3倍比一个数的一半多8,求这个数。 (4)某数的8倍加上10,等于它的10倍减去8,求这个数。(5)4.9减去4.9与0.5的积,比x的5倍少1.65,求x。3、甲乙两个工程队同修一条公路,它们从两端同时施工(1)甲队每天修a米,乙队每天修b米,8天修完,这条公路长多少米? (2)如果这条公路长3000米,甲队每天修85米
4、,乙队每天修65米,修完这条公路需要几天?课后延伸: 一个正方形的边长增加它的1/3后,得到的新正方形的周长是48厘米,原正方形的边长是多少厘米?(图见课本62页)geauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7
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