Java根据输入的日期

1、Java根据输入的日期，输出第二天的日期import java.util.Scanner;public class nextDateTest static int year,nextYear; static int month,nextMonth; static int day,nextDay; public static void main(String args) Scanner sc; loop:while(true) sc=new Scanner(System.in); System.out.println(请输入的日期（例：2012 3 25）：); try year=sc.next

2、Int(); month=sc.nextInt(); day=sc.nextInt(); catch(Exception e) continue loop; /对所有月份进行过滤 if(month12|month31|day30) System.out.println(您输入的有误！); continue loop; /对二月份过滤 if(isLeapYear(year) if(month=2&day29) System.out.println(您输入的有误！); continue loop; else if(month=2&day28) System.out.println(您输入的有误！)

3、; continue loop; break loop; nextDate(year,month,day); System.out.println(输入的日期是：+year+年+month+月+day+日); System.out.println(第二天的日期是：+nextYear+年+nextMonth+月+nextDay+日); public static void nextDate(int year,int month,int day) nextYear=year; nextMonth=month; nextDay=day; switch(month) /大月有31号 case 1: c

4、ase 3: case 5: case 7: case 8: case 10: case 12: if(day=31) nextDay=1; nextMonth=month+1; if(month=12) /12月31号 nextYear=year+1; nextMonth=1; else nextDay=day+1; break;/小月 case 4: case 6: case 9: case 11: if(day=30) nextDay=1; nextMonth=month+1; else nextDay=day+1; break; /平月 case 2: if(isLeapYear(year) if(day=29) nextDay=1; nextMonth=month+1; else nextDay=day+1; else if(day=28) nextDay=1; nextMonth=month+1; else nextDay=day+1; break; default: System.out.println(月份输入有误！); public static boolean isLeapYear(int year) return