计算机等级考试三级PC技术上机16

1、2013年计算机等级考试三级pc技术上机（16）请编制程序，其功能是：对经常上下波动的数据可采用只记录峰值的数据压缩方法。即每次将采样到的当前值和前一次值比较，如数据变化方向改变(原变大现变小或原变小现变大)，说明已过峰值，这时就将前一值(峰值)记录下来。例如(下例数据均为无符号数)：原数据： 23h,45h,89h,67h,5ch,36h,3ch压缩后： 23h,89h,36h内存中从source连续存放着48个八位无符号数，假定无相邻两数相等的情况，编程按上述方法进行压缩，结果保存在result开始的内存单元中。部分程序已给出, 其中原始数据由过程load从文件input1.dat中读入s

2、ource开始的内存单元中。运算结果要求从result开始存放,由过程save保存到文件output1.dat中。填空begin和end之间已给出的一段源程序使其完整(空白已用横线标出,每行空白一般只需一条指令, 但采用功能相当的多条指令亦可),或删除begin和end之间原有的代码并自行编程来完成要求的功能。对程序必须进行汇编,并与io.obj链接产生prog1.exe执行文件,最终运行程序产生结果(无结果或结果不正确者均不得分)。调试中若发现整个程序中存在错误之处, 请加以修改。试题程序：extrn load:far,save:farn equ 40stac segment stackdb

3、 128 dup(?)stac endsdata segmentsource db n dup(?)result db n dup(0)name0 db input1.dat,0name1 db output1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axmov es,ax ;置附加段寄存器lea dx,source ;数据区起始地址lea si,name0 ;原始数据文件名mov cx,n ;字节数call lo

4、ad ;从input1.dat中读取数据;*begin*lea si,sourcelea di,resultcldmovsbxor ax,axxor bx,bxlodsbmov bl,si-2sub ax,bxmov dx,axmov cx,n-2filter: xor ax,axxor bx,bxlodsb ;xnmov bl,si-2 ;xn-1sub ax,bx ;xn-xn-1_ ;相邻两差值(ax,dx)符号位是否相同_j_ skip ;相同，数据方向未变_ ;不同，数据变化，保存峰值stosbskip: _loop filter;*end*lea dx,result ;结果数据区首

5、址lea si,name1 ;结果文件名mov cx,n ;字节数call save ;保存结果到文件retstart endpcode endsend startqcwa3ptgz7r4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgshls50clmtwn60eo8wgqv7xav2ohum32wgeauwydiawgmer4i30ka1dkaghn3xtkknbycudxqa7fhyi2chhi92tgkqcwa3ptgz7r4i30ka1dkagtgkqcwa3p tgz7r4i30ka1dkaghn3xtkknbycudxqa7fhy

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