C语言基础编程练习

1、1.屏幕上输入：This is a C program#include int main()printf(This is a C program.n);return 0;2、求两个整数之和#include void main()int a,b,sum;a=123;b=456;sum=a+b;printf(%dn,sum);3、求两个整数中的较大者#include void main()int max(int x,int y);int a,b,c;scanf(%d,%d,&a,&b);c=max(a,b);printf(max=%d,c);int max(int x,int y)int z;if

2、(xy)z=x;elsez=y;return(z);4、编写一个程序，输入a,b,c三个值，输出其中最大者#include void main()int a,b,c,max; printf(input a,b,c:n); scanf(%d,%d,%d,&a,&b,&c); max=a; if(maxb) max=b; if(maxc) max=c; printf(最大数是%dn,max);5、求5！#include void main()int t=1,i=2; while(i=5) t=t*i; i=i+1; printf(%dn,t);6、求多项式1-1/2+1/3-1/4+1/99-1/

3、100的值#include void main() int sign=1; double deno=2.0,sum=1.0,term; while(deno=100) sign=-sign; term=sign/deno; sum=sum+term; deno=deno+1; printf(%fn,sum);7、将华氏温度64F转换为摄氏度#include void main() float f,c; f=64.0; c=(5.0/9.0)*(f-32); printf(c=%fn,c);8、1000元存一年：（1）活期，年利率为r1；（2）一年期顶起，年利率r2；（3）存两次半年定期，年利率

4、为r3.分别计算3种方法本息和#include void main() float p0=1000,r1=0.0036,r2=0.0225,r3=0.0193,p1,p2,p3; p1=p0*(1+r1); p2=p0*(1+r2); p3=p0*(1+r3/2)*(1+r3/2); printf(p1=%fnp2=%fnp3=%fn,p1,p2,p3);9、给定一个大写字母A，输出其小写字母#include void main()char c1,c2;c1=A;c2=c1+32;printf(%cn,c2);printf(%dn,c2);10、给出三角形三边长，求面积#include #in

5、clude int main()double a,b,c,s,area;a=3.67;b=5.43;c=6.21;s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c);printf(a=%ftb=%ftc=%fn,a,b,c);printf(area=%fn,area);11、输入一个double类型的数，使该数保留小数点后两位，对第三位小数进行四舍五入后处理，然后输出此数，以便验证处理是否正确。#includevoid main()double x;printf(Enter x:);scanf(%lf,&x);printf(1)x=%fn,x);x=x*100+

6、0.5;x=(int)x;x=x/100;printf(2)x=%fn,x);12、编程从键盘输入两个整数给变量x和y，然后输出x和y的值，最后交换x和y的值并输出。#includevoid main()int x,y,t;printf(Enter x,y:n);scanf(%d %d,&x,&y);printf(x=%d y=%dn,x,y);t=x;x=y;y=t;printf(x=%d y=%dn,x,y);13、从键盘输入两个两位的正整数给变量x和y，并将x和y合并形成一个整数放在变量z中。合并的方式是：将数x的十位和各位依次放在z的千位和十位，将y的十位和个位放在z的个位和百位上。#

7、includevoid main()int x,y,z;printf(Input x,y:);scanf(%d,%d,&x,&y);x=x%100;y=y%100;z=(x/10)*1000+(x%10)*10+y/10+(y%10)*100;printf(x=%d,y=%d,z=%dn,x,y,z);14、输入3个整数，分别放入在变量a，b，c中，程序把输入的数据重新按由从小到大的顺序放在变量a，b，c中，最后输出a，b，c中的值#includevoid main()int a,b,c,t;printf(input a,b,c:);scanf(%d%d%d,&a,&b,&c);printf(

8、a=%d,b=%d,c=%dn,a,b,c);if(ab)t=a;a=b;b=t;if(ac)t=a;a=c;c=t;if(bc)t=b;b=c;c=t;printf(a=%d,b=%d,c=%dn,a,b,c);15、根据输入的学生成绩，给出相应的等级，90分以上的等级为A，60以下为E，其余每10分一个等级。#includevoid main()int g;printf(Enter g:);scanf(%d,&g);printf(g=%d:,g);if(g=90) printf(An);else if(g=80) printf(Bn);else if(g=70) printf(Cn);el

9、se if(g=60) printf(Dn);else printf(En);#includevoid main()int g;printf(Enter g:);scanf(%d,&g);printf(g=%d:,g);switch(g/10)case 9: printf(An);break;case 8: printf(Bn);break;case 7: printf(Cn);break;case 6: printf(Dn);break;default: printf(En);16、平面点M(x,y),若M落在圆心在坐标原点单位圆上，key=1；圆外，key=2；圆内key=0#includ

10、e#includevoid main()float x,y,r;int key;printf(input x,y:); scanf(%f,%f,&x,&y);r=sqrt(x*x+y*y);if(r1) key=2;else if(r=1) key=1;else if(r1) key=0; printf(%.1f,%.1f):%dn,x,y,key); -1，x0#includevoid main()int x,y;printf(Enter x:); scanf(%d,&x);if(x0) y=-1;elseif(x=0) y=0; elsey=1; printf(x=%d，y=%dn,x,y

11、);#includevoid main()int x,y;printf(Enter x:); scanf(%d,&x); y=-1; if(x!=0) if(x0)y=1;elsey=0; printf(x=%d,y=%dn,x,y);18、判定某年是否闰年。#includevoid main()int year,leap;printf(input the year:);scanf(%d,&year);if(year%4=0&year%100!=0)|(year%400=0) leap=1;else leap=0;if(leap=1)printf(%d is a leap yearn,year

12、);elseprintf(%d is not a leap yearn,year);#includevoid main()int year,leap;printf(input the year:);scanf(%d,&year);if(year%4=0)if(year%100!=0)leap=1;elseif(year%400=0)leap=1;elseleap=0;elseleap=0;if(leap=1)printf(%d is a leap yearn,year);elseprintf(%d is not a leap yearn,year); #includevoid main()in

13、t year,leap;printf(input the year:);scanf(%d,&year);if(year%400=0) leap=1;elseif(year%4=0)if(year%100=0)leap=0;else leap=1;else leap=1;if(leap=1)printf(%d is a leap yearn,year);elseprintf(%d is not a leap yearn,year);#includevoid main()int year,leap;printf(input the year:);scanf(%d,&year);if(year%4!

14、=0) leap=0;else if(year%100=0) leap=0;else if(year%400=0) leap=1;else leap=1;if(leap=1)printf(%d is a leap yearn,year);elseprintf(%d is not a leap yearn,year);19、求一元二次方程ax2+bx+c=0的解。分析：a=0，非二次方程 b*b-4*a*c=0 ,两个相等实根 0,两个不等实根 0,两个共轭复根#include#includevoid main()float a,b,c,disc,x1,x2,realpart,imagpart;

15、printf(input a,b,c:);scanf(%f,%f,%f,&a,&b,&c);printf(The equation); if(fabs(a)=1E-6)printf(is not quadraticn);else disc=b*b-4*a*c;if(fabs(disc)1E-6)x1=(-b+sqrt(disc)/(2*a);x2=(-b+sqrt(disc)/(2*a);printf(has distinct real roots:%8.4f and %8.4fn,x1,x2); elserealpart=-b/(2*a);imagpart=sqrt(-disc)/(2*a)

16、;printf(has complex roots:n);printf(%8.4f+%8.4fin,realpart,imagpart);printf(%8.4f-%8.4fin,realpart,imagpart);20、编写程序，从键盘输入一个以秒为单位的时间数，将其换算成几小时几分几秒，然后输出。#includevoid main() int x,h,m,s;scanf(%d,&x);h=x/3600;m=x%3600/60;s=x%60;printf(%ds=%d:%d:%d!n,x,h,m,s);21、任意输入一个字符，若是大写字母将其转换成小写字母#includevoid main

17、()char ch;ch=getchar();ch=(ch=A&ch=Z)?ch+32:x;if(ch!=*)putchar(ch);putchar(n);22、编写程序，输入能代表一个日期的3个整数，计算并输出该日是改年的第几天。#includevoid main()int y,m,d,dd=0;printf(Enter y/m/d:); scanf(%d/%d/%d,&y,&m,&d);printf(%d/%d/%d,y,m,d);switch(m-1)case 11: dd=dd+30;case 10: dd=dd+31;case 9: dd=dd+30;case 8: dd=dd+31

18、;case 7: dd=dd+31;case 6: dd=dd+30;case 5: dd=dd+31;case 4: dd=dd+30;case 3: dd=dd+31;case 2: dd=dd+28;case 1: dd=dd+31;case 0: dd=dd+d;if(m2)&(y%4=0&y%100!=0|y%400=0)dd=dd+1;printf( %dn,dd);23、当一个人的月收入在2000元以下时免税；月收入在2000元到5000元之间时，超过2000的部分纳税8%；月收入在5000元以上时，2000至5000之间的部分纳税8%，超过5000的部分纳税15%。编写程序从键

19、盘输入月收入income，计算并输出应交税款tax。#include stdio.hmain()int income;float tax; printf(enter income:);scanf(%d,&income);if(income=2000)tax=0;else if(income=5000)tax=0.08*(income-2000);elsetax=0.08*3000+0.15*(income-5000);printf(tax=%fn,tax);24、回文是指正读和反读都一样的数或字符串。例如：12321、55455、35553等都是回文。请编写一个程序，从键盘上读取一个包含五位数

20、字的长整数，并判断它是否是回文。（提示：用除法运算和求余运算把一个数的个位、十位、百位、千位等分别分离出来。）#include stdio.hmain()long x;int a,b,d,e;printf(enter x:);scanf(%ld,&x);a=x/10000;b=x%10000/1000;d=x%100/10;e=x%10;if(a=e&b=d)printf(%ld is a huiwenn,x);elseprintf(%ld is not a huiwenn,x);25、设计一个简单的计算器，完成两个数的加减乘除分析：输入二个数及运算符 switch表达式：运算符 常量：+-*

21、/#includevoid main()float x,y;char op;printf(enter x,op,y:);scanf(%f %c %f,&x,&op,&y);switch(op)case +:printf(%.2f%c%.2f=%.2fn,x,op,y,x+y);break;case -:printf(%.2f%c%.2f=%.2fn,x,op,y,x-y);break;case *:printf(%.2f%c%.2f=%.2fn,x,op,y,x*y);break;case /:if(y=0)printf(errorn);elseprintf(%.2f%c%.2f=%.2fn,

22、x,op,y,x/y);break;26、编写程序，求1+2+3+。+100的值#includevoid main() int i=1,sum=0; while(i=100) sum=sum+i; i+; printf(sum=%dn,sum);#includevoid main() int i=1,sum=0; do sum=sum+i; i+; while(i=100); printf(sum=%dn,sum);#includemain() int i,sum; for(i=1,sum=0;i=100;i+) sum=sum+i; printf(sum=%dn,sum);27、求100以内

23、奇偶数之和#includevoid main() int n=1,odd=0,even=0; while(n100) odd+=n; even+=n+1; n+=2; printf(odd和=%d,even和=%dn,odd,even);28、求两个正整数m和n，求最大公约数和最小公倍数分析：1、用辗转相除法求最大公约数2、最小公倍数=两数积/最大公约数#includevoid main() int m,n,m1,n1,a; printf(输入两个正整数:n); scanf(%d,%d,&m,&n); m1=m;n1=n; a=m1%n1; while(a!=0) m1=n1;n1=a;a=m

24、1%n1; printf(最大公约数是%dn,n1); printf(最小公倍数是%dn,m*n/n1);29、求n！#includemain() int i,n; long s=1; printf(enter n:); scanf(%d,&n); for(i=1;i=n;i+) s=s*i; printf(%d!=%ldn,n,s);30、编写一个程序，计算半径为0.5，1.5,2.5,3.5,4.5,5.5mm时的圆面积#includemain()float r,s;for(r=0.5;r=5.5;r+)s=3.14159*r*r;printf(r=%f s=%fn,r,s);31、循环嵌

25、套的应用输出九九乘法表#includemain()int i,j;for(i=1;i=9;i+)for(j=1;j=i;j+)printf(%d*%d=%d ,i,j,i*j);printf(n);#includemain()int m,n;m=1;while(m=9) n=1; while(n=2*n并m=3*n#includemain() int i,j,k,n,m,s=0; for(i=1;i=2;i+) for(j=0;j=9;j+) for(k=2;k+2*n&m=2*i并m=3*i#includemain() int i,n1,n2,n3,m,s=0; for(i=101;i=2*

26、i&m3*i) printf(%d ,i); s+; if(s%10=0) printf(n); 33、在循环体中使用break语句#includemain()int i,s;s=0;for(i=1;i5)break;printf(s=%dn,s);34、在循环体中使用continue语句#includemain() int i,s=0; for(i=1;i=8;i+) s+=i; printf(ni=%d,i); if(i%2=0) continue; printf( s=%dn,s); 35、从键盘输入全班的学习成绩，统计出最高分、最低分和平均分#includemain() int x,m

27、ax,min,n; float sum=0; max=0; min=100; n=0; printf(enter x(-1 to end):); scanf(%d,&x); while(x=0) sum=sum+x; n=n+1; if(xmax) max=x; if(x0) printf(max=%d,min=%d,aver=%fn,max,min,sum/n);36、编程求输入的某个正整数是否为素数#includemain() int m,i,t; printf(enter a integer:); scanf(%d,&m); for(i=2;i=m-1;i+) if(m%i=0) t=0

28、; break; else t=1; printf(%d:,m); if(t=1) printf(is a prime number!n); else printf(is not a prime number!n);#include#includemain()int m,i, k;scanf(%d,&m);k=sqrt(m);for(i=2;ik)printf(%d是素数,m);else printf(%d是合数,m);37、求100200之间的素数#include#includemain()int m,i,k,n=0;for(m=101;m200;m=m+2)k=sqrt(m);for(i=

29、2;ik)printf(%6d,m);n+; if(n%10=0)printf(n);38、公鸡5块一个，母鸡3块一个，小鸡3个一块，百元买百只，问分别多少只？分析：设公鸡x，母鸡y，小鸡z，x=19#includemain()int x,y,z;for(x=0;x=19;x+)for(z=0;z=0)&(x*5+y*3+z/3=100)printf(x=%d,y=%d,z=%dn,x,y,z);#includemain() int x=0,y,z; while(x=19) y=0; while(y=33) z=100-x-y; if(5*x+3*y+z/3=100) printf(x=%d

30、y=%d z=%dn,x,y,z); y+; x+; 39、有一根长度为323米的钢材，要将它截取为两种规格a，b的长度分别为17米和27米的短料，每种至少一段，问分割成a，b各多少段后，剩余的残料r最少？#includemain()int na,nb,a,b,r,rmin;na=1;nb=1;rmin=323-17-27;for(na=1;na=(323-27)/17;na+)nb=(323-na*17)/27;r=323-na*17-nb*27;if(rrmin)rmin=r;a=na;b=nb;printf(a=%d,b=%d,min=%dn,a,b,rmin);40、猴子吃桃问题。小猴

31、在某天摘桃若干个，当天吃掉一半，觉得还不过瘾，又多吃了一个；第二天吃了剩下桃子的一半又多一个；以后每天都这样吃下去，直到第8天要吃时只剩一个桃子了，问小猴子第一天共摘下多少个桃子？分析：递推问题X(n-1)=(Xn+1)*2#includemain()int tao,n;tao=1;for(n=1;n=7;n+)tao=(tao+1)*2;printf(tao(1)=%dn,tao);41、斐波那契数列：1，1,2,3,5,8,13,21.。此数列的第一项和第二项为1，从第三项开始，每一项为前两项之和。编程输出该数列的前15项，每行输出5个数。#includemain()int i,f1=1,

32、f2=1,f3;printf(%5d%5d,f1,f2);for(i=3;i=15;i+)f3=f1+f2;printf(%5d,f3);if(i%5=0)printf(n);f1=f2;f2=f3;42、用公式pi/4=1-1/3+1/5-1/7.求pi的近似值，直到最后一项的绝对值小于10-4为止#include#includemain()int n;float t,s,pi;pi=0; n=1;s=1.0;t=s/n;while(fabs(t)=0.0001)pi=pi+t;n=n+2;s=-1*s;t=s/n;printf(pi=%fn,pi*4);#include#includema

33、in()float n,t1,t2,pi;pi=1; n=1;t2=1;while(fabs(t2)=0.0001)n=n+4;t1=1/(n-2);t2=1/n;pi=pi-t1+t2;printf(pi=%fn,pi*4);43、高次方程求根。求方程3X3-4X2-5X+13=0的根#include#includemain()float a,b,c,fa,fb,fc;do printf(enter a,b:); scanf(%f,%f,&a,&b); fa=3*a*a*a-4*a*a-5*a+13; fb=3*b*b*b-4*b*b-5*b+13;while(fa*fb0);doc=(a+

34、b)/2;fc=3*c*c*c-4*c*c-5*c+13;if(fa*fc0) a=c;else b=c;while(fabs(fc)0.0001);printf(3*x*x*x-4*x*x-5*x+13=0 nx=%f,f=%fn,c,fc);44、编写程序，打印出所有的“水仙花数”（一个三位数各位数字立方和等于该数本身）#includemain()int a,b,c,x;for(x=100;x=999;x+)a=x/100;b=x/10%10;c=x%10;if(x=a*a*a+b*b*b+c*c*c)printf(%d ,x); printf(n);打印出最大或最小的“水仙花数”#inc

35、ludemain()int a,b,c,x;for(x=999;x=100;x-)a=x/100;b=x/10%10;c=x%10;if(x=a*a*a+b*b*b+c*c*c)printf(%d ,x);break; printf(n);45、编写程序，输出从公元1980年至2880年所有的闰年年号。每输出5个年号换一行#includemain()int x,flag,s=0; for(x=1980;x=2880;x+)flag=(x%4=0&x%100!=0)|(x%400=0);if(flag)printf(%5d,x);s+;if(s%5=0)printf(n);45、数组的初始化#i

36、ncludemain()int a5=1,2,3,4,5;int b5=1,2,3;int c=1,2,3,4,5;static int d5;int e5;int i;for (i=0;i5;i+)printf(%d,ai);printf(n); for (i=0;i5;i+)printf(%d,bi);printf(n); for (i=0;i5;i+)printf(%d,ci);printf(n); for (i=0;i5;i+)printf(%d,di);printf(n); for (i=0;i5;i+)printf(%d,ei);printf(n);46、用数组来求fibonacc

37、i数列问题分析：fi=fi-2+fi-1 i=220#includemain()int i;static int f20=1,1;for (i=2;i20;i+)fi=fi-2+fi-1;for (i=0;i20;i+)if(i%4=0) printf(n);printf(%6d,fi);47、统计全班某门功课期末考试的平均分和最高分（人数30）用简单变量：#include#define N 30main() int i,sum=0,high=0,score; float average; printf(input everyones score:n); for(i=0;ihigh)high=

38、score; average=(float)sum/N; printf(average=%fn,average); printf(highest=%dn,high);分析：*定义一个整形数组score30，存放全班同学分数 *用for循环读入分数，并求出总分和平均分 *定义变量high存放当前得到的“最高分”，每得到一个分数都要与high的值比较，若比high大，则放入high中。#include#define N 30main()int i,sum=0,high,scoreN;float average;printf(input everyones score:n);for(i=0;iN;i

39、+) for(high=0,i=0;iN;i+)scanf(%d,&scorei); scanf(%d,&scorei);for(high=score0,i=0;ihigh)high=scorei;if(scoreihigh)high=scorei;average=(float)sum/N;printf(average=%fn,average);printf(highest=%dn,high);48、统计选票，设候选人有8人，编号为18，约定0为统计结束标志#includemain()static int x,n9;printf(input No.:);scanf(%d,&x);while(x)nx+=1;printf(input No.:);scanf(%d,&x);for(x=1;x=8;x+)printf(tNo.%d=%d,x,nx);if